Biztalk Mapper XSLT to strip out string from input - xslt

Question

I have an source schema with a node forenames (containing forename + ' ' + middlename), which I need to separate out the middle name in the destination schema so this goes out to OtherNames.
I currently have the following xslt template:
<xsl:template name="StringSplit">
<xsl:param name="valFirstnames" />
<xsl:choose>
<xsl:when test="contains($valFirstnames, ' ')">
<xsl:call-template name="StringSplit">
<xsl:with-param name="valFirstnames" select="substring-after($valFirstnames, ' ')" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<OtherFirstNames><xsl:value-of select="$valFirstnames" /></OtherFirstNames>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Current output for this xslt template is writing out the Middlename twice rather than once:
<OtherFirstName>Middlename</OtherFirstName>
<OtherFirstName>Middlename</OtherFirstName>
Expected:
<OtherFirstName>Middlename</OtherFirstName>
Sample Input
<Data>
<SubjectName>
<forenames>first middle</forenames>
</SubjectName>
<SubjectPartner>
<forenames>first middle</forenames>
<Otherforenames>first middle</Otherforenames>
</SubjectPartner>
<etc./>
</Data>
Sample Output
<Data>
<SubjectName>
<firstname>first</firstname>
<OtherFirstName>middle</OtherFirstname>
</SubjectName>
<SubjectPartner>
<firstname>first</firstname>
<OtherFirstName>middle</OtherFirstName>
<OtherFirstName>middle</OtherFirstName>
</SubjectPartner>
<etc./>
</Data>
I'm looking at correcting the current xslt and updating to incorporate other partner elements that have the same child elements forenames.

Answer 1

Your examples do not make much sense to me. I am guessing you want to do something like:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="forenames">
<firstname><xsl:value-of select="substring-before(concat(., ' '), ' ')"/></firstname>
<xsl:if test="contains(., ' ')">
<OtherFirstName><xsl:value-of select="substring-after(., ' ')"/></OtherFirstName>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Note that this assumes a person has at most two forenames. When applied to the following test input:
<Data>
<SubjectName>
<forenames>Alan Benjamin</forenames>
<surname>Adams</surname>
</SubjectName>
<SubjectPartner>
<forenames>Cecily Diana</forenames>
<surname>Crown</surname>
</SubjectPartner>
<Single>
<forenames>Eve</forenames>
<surname>Evans</surname>
</Single>
<Triple>
<forenames>Frank George Herbert</forenames>
<surname>Forrester</surname>
</Triple>
</Data>
the result will be:
<?xml version="1.0" encoding="UTF-8"?>
<Data>
<SubjectName>
<firstname>Alan</firstname>
<OtherFirstName>Benjamin</OtherFirstName>
<surname>Adams</surname>
</SubjectName>
<SubjectPartner>
<firstname>Cecily</firstname>
<OtherFirstName>Diana</OtherFirstName>
<surname>Crown</surname>
</SubjectPartner>
<Single>
<firstname>Eve</firstname>
<surname>Evans</surname>
</Single>
<Triple>
<firstname>Frank</firstname>
<OtherFirstName>George Herbert</OtherFirstName>
<surname>Forrester</surname>
</Triple>
</Data>