I want an input field with a decimal number upto 2 decimals after the point.
I am using
^\d+\.\d{0,2}$
which works just fine with any 2 decimal number after the point but it does not consider two zeros i.e. 2.00.
How can I include 2.11 and as well as 2.00?
Related
I have a range of values and I want to count the decimal points of all values in the range and display the max count. the formula should exclude the zeroes at the end(not count ending zeroes in the decimal points).
for example, in the above sample, in the whole range the max of count of decimal places is 4 excluding the ending zeroes. so the answer is 4 to be displayed in cell D2
I tried doing regex, but do not know how do I do it for a whole range of values.
Please help!
try:
=INDEX(MAX(LEN(IFERROR(REGEXEXTRACT(TO_TEXT(A2:C4), "(\..+)")*1))-2))
Player0's solution is a good start, but uses TO_TEXT which seems to rely on the formatting of your cells.
If you want to safely compute the number of decimal places, use the TEXT function instead.
TEXT(number, format) requires a format whose max. number of decimal places has to be specified. There is no way around this, because formulas like =1/3 can have infinitely many decimal places.
Therefore, first decide on the max, precision for your use-case (here we use 8). Then use below function which works independently from your document's formatting and language:
=INDEX(MAX(
LEN(REGEXEXTRACT(
TEXT(ABS(A2:C4); "."&REPT("#";8));
"[,.].*$"
))-1
))
We subtract -1 since LEN(REGEXEXTRACT()) also counts the decimal separator (. for english, , for many others) .
Everything after the 8th decimal place is ignored. If all your numbers are something like 123.00000000987 the computed max. is 0. If you prefer it to be 8 instead, then add ROUNDUP( ; 8):
=INDEX(MAX(
LEN(REGEXEXTRACT(
TEXT(ROUNDUP(ABS(A2:C4);8); "."&REPT("#";8));
"[,.].*$"
))-1
))
There is a requirement to round the value up(always) to two decimal places. meaning, the number 8.3333333 should become 8.34. Round and format-number functions do not seem to achieve this. Does anyone have an idea on how to get the desired output using xslt transformation please?
To round up a number with precision of two decimal places:
ceiling(100*$value) div 100
If you need trailing zeros (i.e. a string, not a number) then wrap this in format number().
I'm using odoo 8 and i imported an excel file which i introduced float values with 3 digits after the decimal point. After importing the data in odoo 8 as a tree view i noticed that odoo only displays 2 digits after the comma for these digits and it does the rounding however i want to keep the values as is in the excel file (without rounding and with 3 digits after the decimal point). Any idea for help please ?
You need to change the decimal precision using digits.
digits=(6, 2) specifies the precision of a float number: 6 is the total number of digits, while 2 is the number of digits after the comma. Note that it results in the number digits before the comma is a maximum 4
How to write code that converters a input file of binary numbers into octal. I had to write a code that converts it to decimal which I did, but now I'm supposed to write a code that converts it to octal by grouping the binary numbers in groups of 3 and then calling the binary to decimal function.
For example 10100 would be grouped 10 | 100. So I'd call binary to decimal on 10 and 100 and get 2 for 10 and 4 for 100, then place the numbers together to get 24, which is 10100 decimal in octal.
However, I cannot figure out how to group the numbers. (The number is type string by the way). Any tips would help thanks.
Simply add leading zeroes to your string if its length is not divisble by three then group them and convert to octal.
I am trying to convert a column stored from character to numeric. The problem is that this column has varying number of decimal places.
For example,
Data
1052969525
392282764.234
221018301.2
130010764.7894
82340150
183779233.4
I have determined that the likely maximum of decimal places is 4, the width required would be about 15. So I have attempted the following:
datanum = input(data, 15.4);
But this appears to put the decimal place in the wrong place, especially for those that have no decimal places. What is the most reasonable way to convert this column from char to numeric? This column is part of a database table uploaded by someone else so there's not much option to change that. Thanks.
You don't normally supply the decimal width in informats. For a normal number, you only supply the width, and SAS will figure out the decimal for you (based on the position of the decimal point).
datanum = input(data,15.);
The .d part of an informat is to allow for compatibility with (mostly) older systems that did not have decimals in the data, to save space. For example, if I'm reading in money amounts, and I only have 6 spaces:
123456
882348
100000
123400
I can read that in as an integer amount of cents - or I can do:
input cost 6.2;
That will then tell SAS to place the decimal before the last 2 characters.