I'm facing an issue in Django URLs which is when I direct to localhost:8000/dashboard or localhost:8000/dashboard1111111111, it opens the same page.
Although in my urls.py file I have only /dashboard
How do I throw an error page if URL is incorrect?
Add $ at the end of the regular expression:
url(r'^dashboard$', views.dashboard, name='dashboard'),
This would require the end of the string after the dashboard word.
Related
from django.conf.urls import url
from .import views
urlpatterns = [
url(r'^$', views.index,name='index'),
url(r'^About/', views.About,name='About'),
url(r'^checkout/', views.checkout,name='checkout'),
url(r'^contact', views.contact,name='contact'),
url(r'^faqs', views.faqs,name='faqs'),
url(r'^help', views.help,name='help'),
url(r'^icons', views.icons,name='icons'),
url(r'^payment', views.payment,name='payment'),
url(r'^privacy', views.privacy,name='privacy'),
]
The error message:
Page not found (404)
Request Method:
GET
Request URL:
http://127.0.0.1:8000/About.html
Using the URLconf defined in shop.urls, Django tried these URL patterns,
in this order:
admin/
^$ [name='index']
^about/$ [name='about']
^checkout/$ [name='checkout']
^contact/$ [name='contact']
^static\/(?P<path>.*)$
The current path, About.html, didn't match any of these.
This kind of an error could occur from 2 or 3 different scenarios.
In your case, you seem to put the wrong URL in the browser address bar.
Your correct URL should be http://127.0.0.1:8000/About (as you've written in the URL patterns).
Remember, About.html - is the HTML template you create inside the templates folder. Even though you route to the html page (with a string like: app_name/About.html) - the actual URL in the address bar will be according to what you write in the regex path r'^url_name'. If you write r'^About.html' in url patterns, then http://127.0.0.1:8000/About.html should work perfectly.
The second scenario (based on my experience) which could produce this type of an error is when you forget to pass the 'request' argument inside the method that defines view of the URL - in the respective views.py file.
You should be having a method named About which would look like this in views.py
def About(request):
return render(request,'app_name/About.html')
If you forget to pass argument in the paranthesis of About, this kind of an error could occur.
Finally, if you are using django 2, please start using re_path method to serve regex url patterns. The url method is likely to be depracated in future release.
Refer re_path documentation.
your URL will not be http://127.0.0.1:8000/About.html it will just be http://127.0.0.1:8000/about (remember urls are case insensitive), this will take you to your view which is named About, in your view you should reference your template in its render (about.html)
have you read the my first Django app https://docs.djangoproject.com/en/2.0/intro/tutorial01/ its a great place to start if you are unfamiliar with how django operates
What you are trying to hit is not a valid url, you have to hit http://127.0.0.1:8000/About as written in urls.py.
You have to understand the difference between urls and html templates, this About.html would be used in views while rendering like:
return render(request, 'your_app/about.html')
And for sure you can write a url if you want like this:
urlpatterns = [
url(r'^$', views.index,name='index'),
url(r'^About.html/', views.About,name='About'),
.
.
]
Check the documentation
The url which you provide in url ( ) method doesn't contain any suffix of .html
You can goto the about page directly by /About
I am using new Django 1.8 app to learn Django.
I am stumped as to how to get this my simple url to be resolved by urls.py
I create the url in another view as:
<a href="/photoview/{{photo.id}}/"}>
I can successfully pass this url to the browser as:
http://localhost:8000/photoview/300/
I am expecting that this url can be matched by the urls.py expression:
url('r^photoview/(?P<id>\d+)/$', views.photoview),
But this is not working. I have tried variations of this but none have worked so far, such as:
url('r^photoview/(?P<id>[0-9]+)/$', views.photoview),
I get this message in browser when it fails to match
Page not found (404)
Request Method: GET
Request URL: http://localhost:8000/photoview/300/
Using the URLconf defined in asset.urls, Django tried these URL patterns, in this order:
^admin/
^$ [name='index']
^time/$
^about/$
^accounts/$
^photos/$
^tags/$
^users/$
r^photoview/(?P<id>\d+)/$
^static\/photos\/(?P<path>.*)$
The current URL, photoview/300/, didn't match any of these.
Appreciate any help getting this to work.
you have url('r^photoview/(?P<id>\d+)/$', views.photoview),
you want url(r'^photoview/(?P<id>\d+)/$', views.photoview),
(Note the r is in front of the string, not the first character)
As noted in docs.djangoproject.com/en/1.8/topics/http/urls,
The 'r' in front of each regular expression string is optional but
recommended. It tells Python that a string is “raw” – that nothing in
the string should be escaped
Also note that you should use a friendly name in your url definition (e.g. photoview) and then use {% url 'photoview' photo.id %} in your template instead of hardcoding the URL pattern.
urls.py in project root
url(r'^people/',include('profiles.urls'))
profiles/urls.py
urlpatterns = patterns('profiles.views',
url(r'^me/$','home',name='profile_home'),
url(r'^(?P<user_name>[^/])/$','public_profile',name='user_public_profile'),
url(r'^signup/$','register_user',name='signup')
)
I am getting a 404 error and Django isn't able to find the Url's when I type for existing users, such as /people/alice while the other two patterns for the profile home and signup are working fine. Infact, this was working fine yesterday but not now, and I can't locate the problem.
The error message:
Django tried these URL patterns, in this order:
....
....
^people/ ^me/$ [name='profile_home']
^people/ ^(?P<user_name>[^/])/$ [name='user_public_profile']
^people/ ^signup/$ [name='signup']
Your regex only allows for a single character to match the username. You need to add a +:
r'^(?P<user_name>[^/]+)/$'
Regex pattern in the url is not correct
url(r'^(?P<user_name>[^/])/$','public_profile',name='user_public_profile'),
Change it to use [\w]+
url(r'^(?P<user_name>[\w]+)/$','public_profile',name='user_public_profile'),
I'm not sure that my question is correct.
I develop a web site on local machine and I can not understand how to setup a view which will be executed when I open a start page http://127.0.0.1:8000/
I've tried to write a url - url(r'^/', 'pages.views.home', name='home'), but when I go to browser it doesn't work.
Maybe I need to change settings.
Try using the following URL regex:
url(r'^$', 'pages.views.home', name='home')
The first / is not part of the regex because its automatically removed before comparison against the URLs. The above expression will match the first / and nothing more - ^ means 'beginning of the line' and $ means the end.
I'm working with Django, admittedly for the first time doing anything real.
The URL config looks like the following:
urlpatterns = patterns('my_site.core_prototype.views',
(r'^newpost/$', 'newPost'),
(r'^$', 'NewPostAndDisplayList'), # capture nothing...
#more here... - perhaps the perma-links?
)
This is in an app's url.py which is loaded from the project's url.py via:
urlpatterns = patterns('',
# only app for now.
(r'^$', include('my_site.core_prototype.urls')),
)
The problem is, when I receive a 404 attempting to utilize newpost, the error page only shows the ^$ -- it seems to ignore the newpost pattern...
I'm sure the solution is probably stupid-simple but right now I'm missing it. Can someone help get me on the right track...
Your pattern for the include will only match an empty URL string, change it to a prefix which should be mapped to the included urls, or remove the $ from that pattern.