I need some help with our migrated site urls's. We moved our site from Joomla to Worpdress and IN our posts we have over 20K of internal links.
The structure of these links are like these:
www.mysite.nl/current-post-title/index.php?option=com_content&view=article&id=5259:related-post-title&catid=35:universum&Itemid=48
What we need is this:
www.mysite.nl/related-post-title
So basically we need to remove everyhing behind www.mysite.nl/ up until the colon :, i.e. remove this: current-post-title/index.php?option=com_content&view=article&id=5259: (must remove the colon itself too)
And then remove everything behind the first ampersand (including the ampersand itself) until the end of the string, i.e. remove &catid=35:universum&Itemid=48
Of course only url strings containing this index.php?option=com_content must be changed.
I have dumped the table in plain text and opened it in Notepad++ to do a search and replace with regular expression because the content that must be removed from these lines is different every time.
Can someone please help me with the right regular expression?
In find what box enter below:
(www.mysite.nl)\/.*index.php\?option=com[^:]+:([^&]+)&.*
In replace with box enter:
\1/\2
Result
www.mysite.nl/related-post-title
Go inside-out, rather than outside-in, replace \/.+&id=\d+\:(.+?)&.+ with /$1. Also, paste a few into http://www.regexr.com/ and play around, although JavaScript and Notepad++ might have some differences in implemented Regex features, e.g. negative lookbehinds.
Related
At the moment, I have a PHP function that gets the contents of a CSV file and puts it into a multi-dimensional array, which contains text that I print out in various places, using the indexes.
an example of use would be:
$localText[index][pageText][conceptQualityText][$lang];
The first index, [index], would be the name of the page. The second index [pageText] would indicate what it is (text for the page). The third index, [conceptQualityText] indicates what the actual text is. The last index, [$lang] gets the text in the desired language.
so:
->page location
->what is it
->the content
->what language it should be displayed in.
This all worked fine in the previous PHP versions. However, upgrading to 7.2, PHP seems to be a bit more strict. I was a bit more green ~2 years ago when I first made this solution, and now know that since these indexes aren't defined as strings e.g. encapsulated in single quotes like so: ['index'], they fit the notation of a superglobal (DEFINE). I didn't give it much thought back then, but now PHP seems to interpret them as so (superglobals), and so I get thrown the error that x word is an undefined superglobal.
My initial thought is to make a search and replace on my example string:
$localText[index][pageText][conceptQualityText][$lang];
using the regular expression functionality in Notepad++.
However, the example is just one of many, the notation of the array indexing is basically:
$localText[index][index2][index3][$lang];
So my question is:
How can I make use of the Notepad++ search and replace, using a regular expression, so that my index pointers become strings, instead of acting as superglobal variables?
e.g. make:
$localText[index][index2][index3][$lang];
into:
$localText['index']['index2']['index3'][$lang];
I will need some sort of logic that checks for whatever is inside the brackets and encapsulates them with single quotes, except for the last index, [$lang].
I tried to give as much information as possible, let me know if anything needs to be elaborated.
I tried to refer to these docs without much luck.
I found a solution using
this:
find: \b(localText\[)([a-zA-z0-9_\-]+)(\]\[)([a-zA-z0-9_\-]+)(\]\[)([a-zA-z0-9_\-]+)
replace: $1'$2'$3'$4'$5'$6'
and it works like a charm. Thanks for everyone who took their time to help.
You can use the following regex to match:
\[[^'](\w+)[^']\]
The regex matches a Word between Square brackets unless it quoted.
Replace with:
['$1']
The regex will not match the last brackets because it contains a '$' sign.
I've been searching a lot in the web and in here but I can't find a solution to this.
I have to make two replacements in all registry paths saved in a text file as follows:
replace all asterisc with: [#42]
replace all single backslashes with two.
I already have two expressions that do this right:
1st case:
Find: (\*) - Replace: \[#42\]
2nd case:
Find: ([^\\])(\\)([^\\]) - Replace: $1$2\\$3
Now, all I want is to join them together into just one expression so that I can do run this in one time only.
I'm using Notepad++ 6.5.1 in Windows 7 (64 bits).
Example line in which I want this to work (I include backslashes but i don't know if they will appear right in the html):
HKLM\SOFTWARE\Classes\*\shellex\ContextMenuHandlers\
I already tried separating it with a pipe, like I do in Jscript (WSH), but it doesn't work here. I also tried a lot of other things but none worked.
Any help?
Thanks!
Edit: I have put all the backslashes right, but the page html seem to be "eating" some of them!
Edit2: Someone reedited my text to include an accent that doesn't remove the backslashes, so the expressions went wrong again. But I got it and fixed it. ;-)
Sorry, but this was my first post here. :)
As everyone else already mentioned this is not possible.
But, you can achieve what you want in Notepad++ by using a Macro.
Go to "Macro" > "Start Recording" menu, apply those two search and replace regular expressions, press "Stop Recording", then "Save Current Recorded Macro", there give it a name, assign a shortcut, and you are done. You now can reuse the same replacements whenever you want with one shortcut.
Since your replacement strings are totally different and use data that come not from any capture (i.e. [#42]), you can't.
Keep in mind that replacement strings are only masks, and can not contain any conditional content.
I am currently learning regex and I am trying to filter all links (eg: http://www.link.com/folder/file.html) from a document with notepad++. Actually I want to delete everything else so that in the end only the http links are listed.
So far I tried this : http\:\/\/www\.[a-zA-Z0-9\.\/\-]+
This gives me all links which is find, but how do I delete the remaining stuff so that in the end I have a neat list of all links?
If I try to replace it with nothing followed by \1, obviously the link will be deleted, but I want the exact opposite to have everything else deleted.
So it should be something like:
- find a string of numbers, letters and special signs until "http"
- delete what you found
- and keep searching for more numbers, letters ans special signs after "html"
- and delete that again
Any ideas? Thanks so much.
In Notepad++, in the Replace menu (CTRL+H) you can do the following:
Find: .*?(http\:\/\/www\.[a-zA-Z0-9\.\/\-]+)
Replace: $1\n
Options: check the Regular expression and the . matches newline
This will return you with a list of all your links. There are two issues though:
The regex you provided for matching URLs is far from being generic enough to match any URL. If it is working in your case, that's fine, else check this question.
It will leave the text after the last matched URL intact. You have to delete it manually.
The answer made previously by #psxls was a great help for me when I have wanted to perform a similar process.
However, this regex rule was written six years ago now: accordingly, I had to adjust / complete / update it in order it can properly work with the some recent links, because:
a lot of URL are now using HTTPS instead of HTTP protocol
many websites less use www as main subdomain
some links adds punctuation mark (which have to be preserved)
I finally reshuffle the search rule to .*?(https?\:\/\/[a-zA-Z0-9[:punct:]]+) and it worked correctly with the file I had.
Unfortunately, this seemingly simple task is going to be almost impossible to do in notepad++. The regex you would have to construct would be...horrible. It might not even be possible, but if it is, it's not worth it. I pretty much guarantee that.
However, all is not lost. There are other tools more suitable to this problem.
Really what you want is a tool that can search through an input file and print out a list of regex matches. The UNIX utility "grep" will do just that. Don't be scared off because it's a UNIX utility: you can get it for Windows:
http://gnuwin32.sourceforge.net/packages/grep.htm
The grep command line you'll want to use is this:
grep -o 'http:\/\/www.[a-zA-Z0-9./-]\+\?' <filename(s)>
(Where <filename(s)> are the name(s) of the files you want to search for URLs in.)
You might want to shake up your regex a little bit, too. The problems I see with that regex are that it doesn't handle URLs without the 'www' subdomain, and it won't handle secure links (which start with https). Maybe that's what you want, but if not, I would modify it thusly:
grep -o 'https\?:\/\/[a-zA-Z0-9./-]\+\?' <filename(s)>
Here are some things to note about these expressions:
Inside a character group, there's no need to quote metacharacters except for [ and (sometimes) -. I say sometimes because if you put the dash at the end, as I have above, it's no longer interpreted as a range operator.
The grep utility's syntax, annoyingly, is different than most regex implementations in that most of the metacharacters we're familiar with (?, +, etc.) must be escaped to be used, not the other way around. Which is why you see backslashes before the ? and + characters above.
Lastly, the repetition metacharacter in this expression (+) is greedy by default, which could cause problems. I made it lazy by appending a ? to it. The way you have your URL match formulated, it probably wouldn't have caused problems, but if you change your match to, say [^ ] instead of [a-zA-Z0-9./-], you would see URLs on the same line getting combined together.
I did this a different way.
Find everything up to the first/next (https or http) (then everything that comes next) up to (html or htm), then output just the '(https or http)(everything next) then (html or htm)' with a line feed/ carriage return after each.
So:
Find: .*?(https:|http:)(.*?)(html|htm)
Replace with: \1\2\3\r\n
Saves looking for all possible (incl non-generic) url matches.
You will need to manually remove any text after the last matched URL.
Can also be used to create url links:
Find: .*?(https:|http:)(.*?)(html|htm)
Replace: \1\2\3\r\n
or image links (jpg/jpeg/gif):
Find: .*?(https:|http:)(.*?)(jpeg|jpg|gif)
Replace: <img src="\1\2\3">\r\n
I know my answer won't be RegEx related, but here is another efficient way to get lines containing URLs.
This won't remove text around links like Toto mentioned in comments.
At least if there is nice pattern to all links, like https://.
CTRL+F => change tab to Mark
Insert https://
Tick Mark to bookmark.
Mark All.
Find => Bookmarks => Delete all lines without bookmark.
I hope someone who lands here in search of same problem will find my way more user-friendly.
You can still use RegEx to mark lines :)
I have a list of domains and subdomains stored in a .txt file (I'm using Windows XP).
The format of the domains is this:
somesite1.com
sub1.somesite1.com
sub2.somesite1.com
somesite2.com
sub1.somesite2.com
sub2.somesite2.com
somesite3.com
sub1.somesite3.com
sub2.somesite3.com
I use notepad++, and I need to use regular expressions
Anyway, I don't know what to put in the find & replace boxes so it can go through the contents of the file and leave me with only the root domains. If done properly, it would turn the above example list into this:
somesite1.com
somesite2.com
somesite3.com
Can somebody help me out?
Thank you in advance.
It's an old question, but the answers provided didn't work for me. You need a negative lookahead. The correct regex is:
^\w*\.(?!\w+\s*\n)
You can use:
Find what: [^\r\n]+\.[^.\r\n]+\.[^.\r\n]+[\r\n]+
Replace with: empty_string
with regular expression checked and dot match line-feed NOT checked
I suggest using the Mark tab of the Notepad++ Find dialogue. Enter the regular expression ^\w+\.\w+\.\w+$, make sure that Bookmark line is selected, then click Mark all. Next, use Menu => Search => Bookmark => Remove bookmarked lines. These will remove all entries having with three "words" separated by two dots. It will leave all other lines in place.
An alternative is to mark all lines matching the regular expression ^\w+\.\w+$ and use the Remove unmarked lines menu entry. This I do not recommend as it will remove all lines with an unexpected format as well as the lines for subdomains.
Another method would use the Replace tab of the Notepad++ Find dialogue. Enter the regular expression ^\w+\.\w+\.\w+\r\n in the Find what field, and leave the Replace with field empty. The \r\n part of this expression may need some adjustment to account for the line endings set on the file.
I have series of different occurrences of table cells in some html files as shown in this image:
http://screencast.com/t/MqGHN2iwfd
Apart from the beginning and end of each cell, they have the following parts in common:
.net/?mobile=true
/spotlightProfile.htm?f=mkt&v=
/#stats
I want to either be able to remove all the parts that look like that once
OR be able to remove one-by-one in notepad++:
the url part that precede .net/?mobile=true
the url parts before and after /spotlightProfile.htm?f=mkt&v= and
the url part before /#stats
Furthermore, please, I also want to be able to remove the duplicate occurrence also in Notepad++
Thanks a lot in anticipation for helping out.
Regex would look something like this.
Search for: (.*)(\/\?mobild=true|\/spotlightProfile\.htm\?f=mkt&v=|\/#stats)?(.*)
Replace With: \1\3
Basically we create 3 groups:
before the expression you match,
the expression you trying to replace
the rest of the line