Simple parameter pack expansion: expected ';' - c++

Question

In the following snippet:
void normalize(path& p)
{
// do something with p
}
template<typename... T>
void normalize(T&... t)
{
normalize(t)...; // (L)
}
In my actual understanding, the line (L) expands to:
template<typename... T>
void normalize(T&... t) // T = {t1, t2, t3}, for example
{
normalize(t1), normalize(t2), normalize(t3);
}
and each one of these expressions will execute the one-parameter version of normalize. However, g++ (4.8.1) throws me the following error:
prueba.cpp: In function 'void normalize(T& ...)':
prueba.cpp:155:17: error: expected ';' before '...' token
normalize(t)...;
^
prueba.cpp:155:20: error: parameter packs not expanded with '...':
normalize(t)...;
^
prueba.cpp:155:20: note: 't'
What's wrong with my code?

Answer 1

The expansion of parameter packs is not allowed in this context. If you create a helper class pass, you can do the following:
pass{(normalize(std::forward<T>(t)), 0)...};
The helper class pass might look as follows:
struct pass
{
template <typename ...Args>
explicit pass(Args&&...) { }
};

Answer 2

I think you would want to unpack your parameter pack into a function call site or tuple, like this:
make_tuple(normalize(t)...); // (L)
For example, the following code would compile under gcc-4.8.1:
#include <tuple>
using namespace std;
typedef int path;
void normalize(path& p)
{
// do something with p
}
template<typename... T>
void normalize(T&... t)
{
auto tp = make_tuple(normalize(t)...); // (L)
//do whatever you want with the components of tp ...
}
main() {}