I tried to use if(!cin) to validate if the user input really is an integer. However my programm then just goes into an infinite loop never asking vor new input
do{
cin >> temp->data;
if(!cin){
cout << "Please enter a Number!" << '\n';
correct=false;
}
}while(correct==false);
Would be great if someone could help me :)
When std::cin fails to read the input, the appropriate error flags are set. Therefore you want to reset the flags using std::cin.clear() so that the next input operation will work correctly and then skip everything until the new line using std::cin.ignore(..) in order to avoid similarly formatted input.
while (!(std::cin >> temp->data))
{
std::cin.clear();
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
std::cout << "\nPlease enter a number!" << std::endl;
}
std::numeric_limits<std::streamsize>::max() returns the max amount of characters a stream can hold so that the whole line is guaranteed to be ignored.
If you want to do that kind of check, read the data from cin to a string and convert the string to a number:
string str;
do{
cin >> str;
if(!cin){
cout << "Please enter a Number!" << '\n';
correct=false;
}
else{
istringstream stream(str);
stream >> temp->data;
if(!stream){
cout << "Please enter a Number!" << '\n';
correct=false;
}
}
}while(correct==false);
Use cin.fail() to check whether the user entered correct input. cin.fail() returns true if the last cin command failed, and false otherwise. Moreover, your loop is likely to be infinite, so you must also state an else where you will set the check flag correct to true. Thus, to invalidate the loop's condition and exit the loop in the case user entered correct input (see code below):
do{
cin >> temp->data;
if(cin.fail()){
cin.clear();
cin.ignore(10000, '\n');
cout << "Please enter a Number!" << '\n';
correct=false;
} else {
correct=true;
}
}while(correct==false);
Your 'correct' variable actually doesn't do anything the way you are using it. It's not possible to exit the loop without correct being true; so you could do away with it, and just use a loop-exiting command when you have read the number.
Also, none of the answers posted so far handle the input being closed. They would go into an infinite loop in that scenario.
// A loop; we will break out when we successfully read a number.
while ( 1 )
{
// Prompt for a number and read it
cout << "Please enter a Number!" << endl;
cin >> temp->data;
// Exit loop if we successfully read
if ( cin )
break;
// Check to see if we failed due to the input being closed
if ( cin.eof() )
{
cerr << "End of input reached.\n";
return 0; // depends what your function returns of course
}
// reset the error condition that was caused by trying to read an integer and failing
cin.clear();
// discard anything they previously typed
cin.ignore(numeric_limits<streamsize>::max(), '\n');
}
Moving on from this, a good design would be to actually have this code be an entire function in itself. Then you can call the function whenever you need to get a number safely, without needing to duplicate code. The function declaration might be:
void input_number(int &the_number, std::istream &in, std::string prompt);
which would output the_number, and it would handle end-of-file either by throwing an exception, or by relying on the caller to check for !cin, or even by returning a bool; whatever fits in best with your error handling overall.
For one, if you put a "!" before a condition in an if statement. That's supposed to be a "not" operator.
Related
In the following loop, if we type characters as the cin input instead of numbers which are expected, then it goes into infinite loop. Could anyone please explain to me why this occurs?
When we use cin, if the input is not a number, then are there ways to detect this to avoid abovementioned problems?
unsigned long ul_x1, ul_x2;
while (1)
{
cin >> ul_x1 >> ul_x2;
cout << "ux_x1 is " << ul_x1 << endl << "ul_x2 is " << ul_x2 << endl;
}
Well you always will have an infinite loop, but I know what you really want to know is why cin doesn't keep prompting for input on each loop iteration causing your infinite loop to freerun.
The reason is because cin fails in the situation you describe and won't read any more input into those variables. By giving cin bad input, cin gets in the fail state and stops prompting the command line for input causing the loop to free run.
For simple validation, you can try to use cin to validate your inputs by checking whether cin is in the fail state. When fail occurs clear the fail state and force the stream to throw away the bad input. This returns cin to normal operation so you can prompt for more input.
if (cin.fail())
{
cout << "ERROR -- You did not enter an integer";
// get rid of failure state
cin.clear();
// From Eric's answer (thanks Eric)
// discard 'bad' character(s)
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
For more sophisticated validation, you may wish to read into a string first and do more sophisticated checks on the string to make sure it matches what you expect.
Attention
Please pay attention to the following solution. It is not complete yet to clear the error in your case. You will still get an infinite loop!
if (cin.fail())
{
cout << "Please enter an integer";
cin.clear();
}
Complete Solution
The reason is you need clear the failed state of stream, as well as discard unprocessed characters. Otherwise, the bad character is still there and you still get infinite loops.
You can simply can std::cin.ignore() to achieve this. For example,
if (cin.fail())
{
cout << "Please enter an integer";
// clear error state
cin.clear();
// discard 'bad' character(s)
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
Another Solution
You can also use getline and stringstream to achieve. Here is a brief example.
string input;
while (1)
{
getline(cin, input);
stringstream(input) >> x;
cout << x << endl;
}
Perhaps, it's because,
cin is a streaming function. When a
non-numeric is entered instead of
numbers, it is ignored. And you are
prompted for re-entry.
Even if you did give numeric inputs,
you will be prompted for more inputs since you're on an infinite loop.
You can solve this problem like this:
1. Create a function to take in a string input.
2. return it as numeric after conversion. Use strtod() for conversion.
Hope this helps :)
Another alternative is operator! ,it is equivalent to member function fail()
//from Doug's answer
if ( !cin )
{
cout << "ERROR -- You did not enter an integer";
// get rid of failure state
cin.clear();
// From Eric's answer (thanks Eric)
// discard 'bad' character(s)
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
In the following loop, if we type characters as the cin input instead of numbers which are expected, then it goes into infinite loop. Could anyone please explain to me why this occurs?
When we use cin, if the input is not a number, then are there ways to detect this to avoid abovementioned problems?
unsigned long ul_x1, ul_x2;
while (1)
{
cin >> ul_x1 >> ul_x2;
cout << "ux_x1 is " << ul_x1 << endl << "ul_x2 is " << ul_x2 << endl;
}
Well you always will have an infinite loop, but I know what you really want to know is why cin doesn't keep prompting for input on each loop iteration causing your infinite loop to freerun.
The reason is because cin fails in the situation you describe and won't read any more input into those variables. By giving cin bad input, cin gets in the fail state and stops prompting the command line for input causing the loop to free run.
For simple validation, you can try to use cin to validate your inputs by checking whether cin is in the fail state. When fail occurs clear the fail state and force the stream to throw away the bad input. This returns cin to normal operation so you can prompt for more input.
if (cin.fail())
{
cout << "ERROR -- You did not enter an integer";
// get rid of failure state
cin.clear();
// From Eric's answer (thanks Eric)
// discard 'bad' character(s)
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
For more sophisticated validation, you may wish to read into a string first and do more sophisticated checks on the string to make sure it matches what you expect.
Attention
Please pay attention to the following solution. It is not complete yet to clear the error in your case. You will still get an infinite loop!
if (cin.fail())
{
cout << "Please enter an integer";
cin.clear();
}
Complete Solution
The reason is you need clear the failed state of stream, as well as discard unprocessed characters. Otherwise, the bad character is still there and you still get infinite loops.
You can simply can std::cin.ignore() to achieve this. For example,
if (cin.fail())
{
cout << "Please enter an integer";
// clear error state
cin.clear();
// discard 'bad' character(s)
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
Another Solution
You can also use getline and stringstream to achieve. Here is a brief example.
string input;
while (1)
{
getline(cin, input);
stringstream(input) >> x;
cout << x << endl;
}
Perhaps, it's because,
cin is a streaming function. When a
non-numeric is entered instead of
numbers, it is ignored. And you are
prompted for re-entry.
Even if you did give numeric inputs,
you will be prompted for more inputs since you're on an infinite loop.
You can solve this problem like this:
1. Create a function to take in a string input.
2. return it as numeric after conversion. Use strtod() for conversion.
Hope this helps :)
Another alternative is operator! ,it is equivalent to member function fail()
//from Doug's answer
if ( !cin )
{
cout << "ERROR -- You did not enter an integer";
// get rid of failure state
cin.clear();
// From Eric's answer (thanks Eric)
// discard 'bad' character(s)
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
I'm writing a program where I get an integer input from the user with cin>>iUserSel;. If the user puts in a letter, the program goes to an infinite loop. I tried to prevent that with the code below, but the program goes to an infinite loop and prints out "Wrong! Enter a #!". How can I fix my program?
cin>>iUserSel;
while (iValid == 1)
{
if (cin.fail())
{
cin.ignore();
cout<<"Wrong! Enter a #!"<<endl;
cin>>iUserSel;
}//closes if
else
iValid = 0;
}//closes while
I found some information on this at Correct way to use cin.fail() and C++ cin.fail() question
, but I didn't understand how to use them to fix my issue.
When cin fails, you need to clear the error flag. Otherwise subsequent input operations will be a non op.
To clear the error flags, you need to call cin.clear().
Your code would then become:
cin >> iUserSel;
while (iValid == 1)
{
if (cin.fail())
{
cin.clear(); // clears error flags
cin.ignore();
cout << "Wrong! Enter a #!" << endl;
cin >> iUserSel;
}//closes if
else
iValid = 0;
}//closes while
I would also suggest you change
cin.ignore();
to
cin.ignore(numeric_limits<streamsize>::max(), '\n');
In case the user enters more than one letter.
The problem you are having is that you don't clear the failbit from the stream. This is done with the clear function.
On a somewhat related note, you don't really need to use the fail function at all, instead rely of the fact that the input operator function returns the stream, and that streams can be used in boolean conditions, then you could do something like the following (untested) code:
while (!(std::cin >> iUserSel))
{
// Clear errors (like the failbit flag)
std::cin.clear();
// Throw away the rest of the line
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
std::cout << "Wrong input, please enter a number: ";
}
Here's what I would recommend:
// Read the data and check whether read was successful.
// If read was successful, break out of the loop.
// Otherwise, enter the loop.
while ( !(cin >> iUserSel) )
{
// If we have reached EOF, break of the loop or exit.
if ( cin.eof() )
{
// exit(0); ????
break;
}
// Clear the error state of the stream.
cin.clear();
// Ignore rest of the line.
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
// Ask more fresh input.
cout << "Wrong! Enter a #!" << endl;
}
I am a beginner programmer learning c++. I am having a nagging issue with the cin command.
In the program section below, if I enter a wrong type at the 1st cin command, the program will not execute any of the following cin commands at all, but will execute the rest of the program.
//start
#include <iostream>
using namespace std;
int main()
{
int x=0;
cout << endl << "Enter an integer" << endl;
//enter integer here. If wrong type is entered, goes to else
if (cin >> x){
cout << "The value is " << x << endl;
}
else {
cout << "You made a mistake" << endl; //executes
cin.ignore();
cin.clear();
}
cout << "Check 1" << endl; //executes
cin >> x; //skips
cout << "Check 2" << endl; //executes
cin >> x; //skips
return 0;
}
//end
Instead of the if else, if i put the same concept in a loop
while (!(cin >> x))
the program goes into an infinite loop upon enterring a wrong input.
Please help me explain this phenomenon, as the text book i am following says the code typed above should work as intended.
Thank you
cin is an input stream. If an error occurs cin goes into a let's call it "error occured" state. While in this state no character input can be made, your request to collect a character from the input stream will be ignored. With clear() you clear the error and the input stream stops ignoring you.
Here is the ignore function prototype
istream& ignore ( streamsize n = 1, int delim = EOF );
This function gets characters from the input stream and discards them, but you can't get any character if your stream is ignoring you, so you have to first clear() the stream then ignore() it.
Also, a note on the side: If someone inputs, for example "abc", on the first input request your cin gets only one character that is 'a' and "bc" stays in the buffer waiting to be picked up, but the next call to cin gets the 'b' and 'c' stays in the buffer, so you again end up with an error.
The problem with this example is that the cin.ignore() if no arguments are handed to it only ignores 1 character after you clear(). and the second cin gets 'c' so you still have a problem.
A general solution to this problem would be to call
cin.ignore(10000, '\n');
The first number just has to be some huge number that you don't expect someone would enter, I usually put in 10000.
This call makes sure that you pick up all the characters from the false input or that you pick up every character before the enter was pressed so your input stream doesn't get into the "error occurred" state twice.
You may also want to try
if ( std::cin.fail() )
as a backup to prevent a crash due to input of the wrong type when prompted
In the following loop, if we type characters as the cin input instead of numbers which are expected, then it goes into infinite loop. Could anyone please explain to me why this occurs?
When we use cin, if the input is not a number, then are there ways to detect this to avoid abovementioned problems?
unsigned long ul_x1, ul_x2;
while (1)
{
cin >> ul_x1 >> ul_x2;
cout << "ux_x1 is " << ul_x1 << endl << "ul_x2 is " << ul_x2 << endl;
}
Well you always will have an infinite loop, but I know what you really want to know is why cin doesn't keep prompting for input on each loop iteration causing your infinite loop to freerun.
The reason is because cin fails in the situation you describe and won't read any more input into those variables. By giving cin bad input, cin gets in the fail state and stops prompting the command line for input causing the loop to free run.
For simple validation, you can try to use cin to validate your inputs by checking whether cin is in the fail state. When fail occurs clear the fail state and force the stream to throw away the bad input. This returns cin to normal operation so you can prompt for more input.
if (cin.fail())
{
cout << "ERROR -- You did not enter an integer";
// get rid of failure state
cin.clear();
// From Eric's answer (thanks Eric)
// discard 'bad' character(s)
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
For more sophisticated validation, you may wish to read into a string first and do more sophisticated checks on the string to make sure it matches what you expect.
Attention
Please pay attention to the following solution. It is not complete yet to clear the error in your case. You will still get an infinite loop!
if (cin.fail())
{
cout << "Please enter an integer";
cin.clear();
}
Complete Solution
The reason is you need clear the failed state of stream, as well as discard unprocessed characters. Otherwise, the bad character is still there and you still get infinite loops.
You can simply can std::cin.ignore() to achieve this. For example,
if (cin.fail())
{
cout << "Please enter an integer";
// clear error state
cin.clear();
// discard 'bad' character(s)
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
Another Solution
You can also use getline and stringstream to achieve. Here is a brief example.
string input;
while (1)
{
getline(cin, input);
stringstream(input) >> x;
cout << x << endl;
}
Perhaps, it's because,
cin is a streaming function. When a
non-numeric is entered instead of
numbers, it is ignored. And you are
prompted for re-entry.
Even if you did give numeric inputs,
you will be prompted for more inputs since you're on an infinite loop.
You can solve this problem like this:
1. Create a function to take in a string input.
2. return it as numeric after conversion. Use strtod() for conversion.
Hope this helps :)
Another alternative is operator! ,it is equivalent to member function fail()
//from Doug's answer
if ( !cin )
{
cout << "ERROR -- You did not enter an integer";
// get rid of failure state
cin.clear();
// From Eric's answer (thanks Eric)
// discard 'bad' character(s)
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}