I have a xml where i need to check for a condition
[preceding-sibling::heading/title='ABC's Notes. --']
This expression is throwing error as "expected "]" found s ". I need to search for title "ABC's Notes. --" but i think 'ABC' is being interpreted as a separate string.
How should i write the above code to make apostrophe not being treated as end of string. Any inputs would be helpful
Both double ("…") and single ('…') quotes can be used to delimit strings in XSLT. To include either in a string either use the other quotes for the string (in your case switching to double quotes would work, or use the XML entities: ' or " for single and double quotes respectively.
Related
I am using ultraedit with regex. I would like to find (and replace) and embedded double quotes found withing a string that starts/ends with a double quote. This is a text file with pipe | as the delimeter.
How do I find the embedded double quotes:
"This string is ok."|"This is example with a "C" double quoted grade in middle."|"Next line"
I eventually need to replace the double quotes in "C" to just have C.
The big trade off in CSV is correct parsing in every case versus simplicity.
This is a resonably moderated approach. If you have really wily strings with quotes next to pipes in them, you better use something like PERL and Text::CSV.
There is a bother with a regex that requires a non-pipe character on each side of the quote (such as [^|]) in that the parser will absorb the C and then won't find the other quote next to the C.
This example will work pretty well as long as you don't have pipes and quotes next to each other in your actual CSV strings. The lookaheads and behinds are zero-width, so they do not remove any additional characters besides the quote.
1 2 3 4
(?<!^)(?<!\|)"(?!\|)(?!$)
Don't match quotes at the beginning of the line.
Don't match quotes with a pipe in front.
Don't match quotes with a pipe afterwards.
Don't match quotes at the end of a string.
Every quote thus matched can be removed. Don't forget to specify global replacement to get all of the quotes.
Try this find:
(["][^"]*)["]C["]([^"]*["])
and replace:
\1C\2
Turn on Regular Expressions in Perl mode.
Screen shot of
UltraEdit Professional Text/HEX Editor
Version 21.30.0.1005
Trying it out.
Start with:
"This string is ok."|"This is example with a "C" double quoted grade in middle."|"Next line"
"This string is ok."|"This is example with a C double quoted grade in middle."|"Next line"
Ends with:
"This string is ok."|"This is example with a C double quoted grade in middle."|"Next line"
"This string is ok."|"This is example with a C double quoted grade in middle."|"Next line"
Breakdown of the regex FIND.
First part.
(["][^"]*)
from (["][^"]*)["]C["]([^"]*["])
This looks for a sequence of:
Double quote: ["].
Any number of characters that are not double quotes: [^"]*
The brackets that surround ["][^"]* indicate that the regex engine should store this sequence of characters so that the REPLACE part can refer back to it (as back references).
Note that this is repeated at the start and end - meaning that there are two sequences stored.
Second part.
["]C["]
from (["][^"]*)["]C["]([^"]*["])
This looks for a sequence of:
Double quote: ["].
The capital letter C (which may or may not stand for Cookies).
Double quote: ["].
Breakdown of the regex REPLACE.
\1C\2
\1 is a back reference that means replace this with the first sequence saved.
The capital letter C (which may or may not stand for Cookies).
\2 is a back reference that means replace this with the second sequence saved.
For the example you gave just "\w" works as the regex to find "C"
Try it here
The replacing mechanism is probably built into ultraedit
You really don't want to do this with regex. You should use a csv parser that can understand pipe delimiters. If I were to this with just regex, I would use multiple replacements like this:
Find and replace the good quotes with placeholder to text. Start/end quote:
s/(^"|"$)/QUOTE/g
Quotes near pipe delimiters:
s/"\|"/DELIMITER/g
Now only embedded double quotes remain. To delete all of them:
s/"//g
Now put the good quotes back:
s/QUOTE|DELIMITER/"/g
nanny posted a good solution, but for a Perl script, not for usage in a text editor like UltraEdit.
In general it is possible to have double quotes within a field value. But each double quote must be escaped with one more double quote. This is explained for example in Wikipedia article about comma-separated values.
This very simple escaping algorithm makes reading in a CSV file character by character coded in a programming language very easy. But double quotes, separators and line breaks included in a double quoted value are a nightmare for a regular expression find and replace in a CSV file.
I have recorded several replaces into an UltraEdit macro
InsertMode
ColumnModeOff
Top
PerlReOn
Find MatchCase RegExp "^"|"$"
Replace All "QuOtE"
Find MatchCase ""|"
Replace All "QuOtE|"
Find MatchCase "|""
Replace All "|QuOtE"
Find MatchCase """"
Replace All "QuOtEQuOtE"
Find MatchCase """
Replace All """"
Find MatchCase "QuOtE"
Replace All """
The first replace is a Perl regular expression replace. Each double quote at beginning or end of a line is replaced by the string QuOtE by this replace. I'm quite sure that QuOtE does not exist in the CSV file.
Each double quote before and after the pipe character is also replaced by QuOtE by the next 2 non regular expression replaces.
Escaped double quotes "" in the CSV file are replaced next by QuOtEQuOtE with a non regular expression replace.
Now the remaining single double quotes are replaced by two double quotes to make them valid in CSV file. You could of course also remove those single double quotes.
Finally, all QuOtE are replaced back to double quotes.
Note: This is not the ultimate solution. Those replaces could produce nevertheless a wrong result, for example for an already valid CSV line like this one
"first value with separator ""|"" included"|second value|"third value again with separator|"|fourth value contains ""Hello!"""|fifth value
as the result is
"first value with separator """|""" included"|second value|"third value again with separator|"|fourth value contains ""Hello!"""|fifth value
PS: The valid example line above should be displayed in a spreadsheet application as
first value with separator "|" included second value third value again with separator| fourth value contains "Hello!" fifth value
I have a file that is tab delimited. When exporting from Excel, if the cell has a comma in it, it will wrap the cell with double quotes.
To find the first double quote, I can look for a tab then double quote ex: \t"
The next double quote to remove is at the end of the line, so I would like to find double quote then newline ex: \n" but this is not working.
Example of the file format:
textTABtextTAB"moretextwithquotes"CRLF
First, you're searching for \n" instead of "\n, if I well understand your problem.
Secondly, you need to search for \r\n instead of \n, so your final result should be "\r\n.
If all your data is consistent where double quotes are matched and encapsulates fields,
I would just do a global find and replace just on quoted text.
Replacing the match with just the field data. This strips the quotes, leaves everything
else untouched.
Find: "([^"\\]*(?:\\.[^"\\]*)*)"
Replace: $1
I am using a program that pastes what is in the clipboard in a modified format according to what I specify.
I would like for it to paste paths (i.e. "C:\folder\My File") without the pair of double quotes.
This, which isn't using RegEx works: Find " (I simply enter than in one line) and replace with nothing. I enter nothing in the second field. I leave it blank.
Now, though that works, it will remove double quotes in this scenario: Bob said "What are you doing?"
I would like the program to remove the quotes only if the the words enclosed in the double quotes have a backslash.
So, once again, just to make sure I am clear, I need the following:
1) RegEx Expression to find strings that have both double quotes and a backslash within those set of quotes.
2) A RegEx Expression that says: replace the backslashes with backslashes (i.e. leave them there).
Thank you for the fast response. This program has two fields. One for what to find and the other for what to replace. So, what would go in the 2nd field?
The program came with the Remove HTML entry, which has
<[^>]*> in the match pattern
and nothing (it's blank) in the Replacement field.
You didn't say which language you use, here's an example in Javascript:
> s = 'say "hello" and replace "C:\\folder\\My File" thanks'
"say "hello" and replace "C:\folder\My File" thanks"
> s.replace(/"([^"\\]*\\[^"]*)"/g, "$1")
"say "hello" and replace C:\folder\My File thanks"
This should work in .NET:
^".*?\\.*?"$
Often I find myself inverting quotes:
from double quotes "" to single quotes '' and
from single quotes '' to double quotes "".
I know there is a way to switch single quotes to double quotes:
:%s/'\(\([^']*\)\)'/"\1"/g
And a way to switch double quotes to single quotes:
:%s/"\(\([^"]*\)\)"/'\1'/g
but how do I do both operations together without including the first swapped quotes in the 2nd swapping?
Typically, when you want to swap A & B like this, you need an intermediate step where you replace A with something entirely different and very likely to be unique within the document, whether an unusual character or something longer and crazier like |x-monkeyz-x|.
You can then convert all the Bs to As, and finally all the |x-monkeyz-x| to Bs.
For example,
Replace all ' with !X!
Replace all " with '
Replace all !X! with "
EDIT
This is better: Easiest way to swap occurrences of two strings in Vim?
If there is no escaped quotes inside string literals and it is not needed to
ensure correct pairing of quotes, one can use the command
:%s/['"]/\="'\""[submatch(0)!='"']/g
I usually use an intermediate string like my name that's unlikely to appear in the text:
Change single quote to UNLIKELY_STRING
Change double quote to single quote
Change UNLIKELY_STRING to double quote
Use \=:
:%s/'\([^']*\)'/\='"'.tr(submatch(1), '"', "'").'"'/g
. This assumes that both characters only serve as quotes, but your initial code also does the same, except that my does not check for them being paired.
I've written a simple CSV file parser. But after looking at the wiki page on CSV formats I noticed some "extensions" to the basic format. Specifically embedded comma via double quotes. I've managed to parse those, however there is a second issue: embedded double quotes.
Example:
12345,"ABC, ""IJK"" XYZ" -> [1234] and [ABC, "IJK" XYZ]
I can't seem to find the correct way to distinguish between an enclosed double quote and none. So my question is what is the correct way/algorithm to parse CVS formats such as the one above?
The way I normally think about this is basically to look at the quoted value as a single, unquoted value or a sequence of double quoted values that form a value joined by quotes. That is,
to parse the next atom in the row:
read up to the first non whitespace character
if the current character is not a quote:
mark the current spot
read up to the next comma or newline
return the text between the mark and the character before the comma (strip spaces if appropriate)
if the current character is a quote:
create an empty string buffer
while the current character is not a quote
mark the current position +1 (skip the quote character)
read up to the next quote
if the buffer is not empty, append a quote to it
append to the buffer the text between the mark and the character before the current position (to strip both quotes)
advance one character (past the just read quote)
read up to the next comma or newline
return the buffer
essentially, split each double quoted segment of the quoted string and then catenate them together with quotes. thus: "ABC, ""IJK"" XYZ" becomes ABC, , IJK, XYZ, which in turn becomes ABC, "IJK" XYZ
I would do this using a single character look-ahead, so if you're scanning the string and find a double quote, look at the next character to see if it is also a double quote. If it is, then the pair represents a single doublequote character in the output. If it's any other character, you're looking at the end of the quoted string (and hopefully that next character is a comma!). Be sure to account for the end-of-line condition when looking at the next character, too.
If you find a double-quote, then you should look for a double-quote in the end of the word/string. If you can't find, then there is an error. The same for a quote.
I suggest you try Flex/Bison in order to write a parser for the CSV file. Both tools will help you to generate a parser and then you can use the C files with the parser and call it from your C++ program.
On Flex, you create a scanner that can find your tokens, like "word" or ""word"". On Bison, you define the syntax.
A double double-quote ("") is a literal double-quote, while a lone double-quote (") is used for enclosing text (including commas).
Here's a regex for a csv field, if that makes things easier:
([^",\n][^,\n]*)|"((?:[^"]|"")+)"
Group 1 will contain the field if it isn't in quotes, group 2 will contain the field if it is in quotes, minus the surrounding quotes. In that case, just replace all instances of "" with ".
I suggest reading: Stop Rolling Your Own CSV Parser and this CSV RFC. The first is really just someone who wants you to use their C# CSV parser, but still explains many issues.
Your parser should be examining a character at a time. I used a double bool strategy for my parser in D. Each quote toggles weather the string is quoted or not. When in a quoted Cell you flag when hit a quote, and turn off quoting. If the next character is a quote, quoting is turned on, a quote is added to the result and the flag is turned off. If the next character isn't a quote then the flag is turned off and so is quoting.