Throwing from before a try...catch - c++

Question

If I have something like this:
if(condition1)
{
cout<<"ERROR: Expected an identifier \n.";
throw std::invalid_argument("");
}
if(condition2)
{
moveToken();
cout<<"ERROR: Expected a ' ( ' after Identifier \n.";
throw std::invalid_argument("");
}
moveToken();
try
{
try
{
newPosition = position;
fcNode->addChild(actual_params());
}
catch(exception &e)
{
position=newPosition;
if(condition3)
{
moveToken();
cout<<"ERROR: Expected a ' ) ' \n.";
throw std::invalid_argument("");
}
moveToken();
return fcNode;
}
if(condition4)
{
moveToken();
cout<<"ERROR: Expected a ' ) ' \n.";
throw std::invalid_argument("");
}
}
catch (exception &e)
{
moveToken();
throw std::invalid_argument("");
}
Would the exception thrown from the condition1 block be caught by any catch block or do I need to put the whole code in another try block and do a catch for it? (do throws get caught by first encountered catch blocks?) Thanks

Answer 1

If you have the following code:
try{
// block 1
}catch(exception){
// block 2
}
Every exception ONLY from block 1 will be caught and processed by block 2; catch block cannot catch any exception outside of block 1, so yes, you have to make one more try-catch

Answer 2

The execption will be caught by a type-matching catch block attached to whatever try block is enclosing the throw. If no try block is enclosing the throw in the current scope, or none of the attached catch blocks match the exception's type, then the exception will be sent up the call chain (i.e. to whatever function called this one). Repeat until we reach main, where the program will be terminated if the exception is not caught.
In the code you highlighted, there is no enclosing try block around that throw, so the exception will be handled further up the call chain, if at all.

Answer 3

Yes, you will have to put your hole code into a catch block since exception are only catch insde de surrounding try.
try {
//(.inside here can be catched.)
} catch(const std::exception& ex){
// here goes you catched exception
}

Answer 4

In C++, any type can be used for catching exceptions unlike in JAVA.
Ex:
try {
int integer_ = 11;
throw integer_;
} catch(int e) {
std::cout<<e<<"\n";//Displays 11
}
You can use a multi catch block like:
try {
int integer_ = 11;
std::string string_ = "thrown exception";
throw string_;
} catch(const std::string& e) {
std::cout<<e<<"\n";//Displays thrown exception
} catch(int e) {//This block is not treated, beacause no integer is thrown as an exception
std::cout<<e<<"\n";
}