run time error - non zero exception - c++

Question

my programming teacher gave me this problem to code it in c :
given array of N integers A and a number K. During a turn the maximal value over all Ai is chosen, let's call it MAX. Then Ai =
MAX - Ai is done for every 1 <= i <= N. Help Roman to find out how will the array look like after K turns.
Input
The numbers N and K are given in the first line of an input. Then N integers are given in the second line which denote the array A.
Output
Output N numbers on a single line. It should be the array A after K turns.
Constraints
* 1 <= N <= 10^5
* 0 <= K <= 10^9
* Ai does not exceed 2 * 10^9 by it's absolute value.
Example
Input:
4 1
5 -1 7 0
Output:
2 8 0 7
and my code to this problem is :
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
long int Max(long int *arr, int low, int high)
{
long int max,i;
max = arr[low];
for(i=0;i<=high;i++)
{
if(max<=arr[i])
max = arr[i];
}
return max;
}
/* Driver program to test above function */
int main()
{
long int max,*arr;
long int n,k,c1,c2,c3,i,j;
c1 = (long int)pow(10,5);
c2 = (long int)pow(10,9);
c3 = 2*c2;
scanf("%ld %ld",&n,&k);
if(n<1||n>c1)
exit(1);
else if(k<0||k>c2)
exit(1);
else
{
arr = (long int *)malloc(sizeof(int)*n);
for(i=0;i<n;i++)
{
scanf("%ld",&arr[i]);
if(abs(arr[i])>c3)
exit(1);
}
if(k%2 == 0)
{
for(i=0;i<2;i++)
{
max = Max(arr, 0, n-1);
for(j=0;j<n;j++)
{
arr[j] = max-arr[j];
if(abs(arr[j])>c3)
exit(1);
}
}
}
else if(k%2 != 0)
{
max = Max(arr, 0, n-1);
for(j=0;j<n;j++)
{
arr[j] = max-arr[j];
/*if(abs(arr[j])>c3)
exit(1);*/
}
}
/* for(m=0;m<n;m++)
printf("%ld ",arr[m]);
printf("\n");*/
for(i=0;i<n;i++)
printf("%ld ",arr[i]);
printf("\n");
}
return 0;
}
i executed this code on gcc compiler in ubuntu, it is working perfectly with all the constraints satisfied but when I uploaded this code on my teacher's portal which has a compiler and executed the code, it said Runtime error -
nzec which means a non-zero exception which is used to signify that main() does not have "return 0;" statement or exception thrown by c++ compiler.
Please, can anyone help me what is wrong in my code as there is a return 0; statement in my code. Please Help.
Everyone has pointed out multiple use of exits ... Can I reduce them using any other way in place of exit()?

Answer 1

My guess is that it has to do with the various exit(1) statements you have for error conditions.

Answer 2

As pointed out by Dave Costa, exit(1) could be the cause
Another possible problem is the size of the allocated array:
arr = (long int *)malloc(sizeof(int)*n);
should be:
arr = malloc(sizeof(long int)*n);
And note that you don't need to use pow for constants:
c1 = (long int)pow(10,5);
c2 = (long int)pow(10,9);
could be replaced with:
c1 = 1e5L;
c2 = 1e9L;