Converting binary to ASCII - c++

Question

I have a text full of binary values(0-1) and i'm trying to convert it to ASCII , I made a code but it didn't work well and it takes too long time and writing, this is a part of it:
#include <iostream>
#include <fstream>
#include <string>
#include <stdio.h>
#include <stdlib.h>
using namespace std;
int main()
{
ofstream fout("C:\\test.txt",ios :: binary);
ifstream file("E:\\mnmn.txt");
string content;
while(file >> content)
{
for (size_t i = 0; i < content.size(); i++)
{
while((content[i] == '0')
&& (content[i+1] == '0')
&& (content[i+2] == '0')
&& (content[i+3] == '0')
&& (content[i+4] == '0')
&& (content[i+5] == '0')
&& (content[i+6] == '0')
&& (content[i+7] == '0')
{
char *data = "00000000";
char c = strtol(data, 0, 2);
fout<<c;
}
}
}
}
i have to do the same for all values and even if i did the program repeats the values because the zeros and ones is connected without any spaces between , isn't there a better way to convert it?
the text contains:
00001111101010001001010101110
etc..

Answer 1

GCC 4.8.2: g++ -Wall -Wextra -std=c++11 read-01.cpp
#include <bitset>
#include <fstream>
int main() {
std::ofstream fout("test.txt");
std::ifstream fin("mnmn.txt");
char ic;
std::bitset<8> oc;
int i = 8;
while (fin >> ic) {
oc[--i] = ic - '0';
if (0 == i) {
fout << static_cast<char>(oc.to_ulong());
i = 8; } }
return 0; }

Answer 2

You can read the contents of the file character by character and accumulate the characters in a variable. After reading 8 characters, you have the ASCII value. The core of your function can be changed to:
int inChar = 0;
int outChar = 0;
int count = 0;;
while( (inChar = file.get()) != EOF )
{
int x = inChar - '0';
// Ignore newlines and other characters that are not '0' or '1'.
if ( x == 0 || x == 1 )
{
// Accumulate the bit into the output char.
outChar = (outChar << 1) + x;
++count;
if ( count == 8 )
{
fout.put(outChar);
outChar = 0;
count = 0;
}
}
}
// Deal with unused outChar.
if ( count > 0 )
{
cout << "There are " << count << " bits that were not used.\n";
}

Answer 3

If you want to get eight characters (bits) at a time from the input you read, then you should use the std::string::substr function, and you can use the resulting string directly, either in std::stoi (or if you don't have it std::strtol).
Something like
while (file >> content)
{
do
{
std::string byte = content.substr(0, 8); // Get eight "bits"
fout << std::stoi(byte, nullptr, 2); // Convert and output to file
content = content.substr(8); // The remaining bits
} while (!content.empty());
}