Hello I have problems trying to overload the assignment operator in my generic linked-queue class.
Here is the code in question:
template<typename T>
class Queue : public IQueue<T>
{
(...)
public:
Queue();
Queue(const Queue<T> &origQueue);
virtual~Queue();
Queue& operator=(const Queue<T> &origQueue);
void enqueue(const T& element);
T dequeue();
T peek() const;
int size() const;
};
template<typename T>
Queue& Queue<T>::operator=(const Queue<T> &origQueue)
{
(...)
return *this;
}
Any ideas of where I'm going wrong?
Since your class is templated, you wanna return a Queue object, so the return value needs to be templated too:
template<typename T>
Queue<T>& Queue<T>::operator=(const Queue<T> &origQueue)
//...^
{
return *this;
}
Related
According to Why isn't argument deduction allowed in function return type?
When specifying a return type in a template class member function we have to be specific, for example: "the type std::vector isn't a type, std::vector<int> is."
So why do both of these examples compile? If I don't include the <T> in the first example, it shouldn't even be considered a type right?
template<typename T>
Queue<T>::Queue(const Queue& st) {}
template<typename T>
Queue<T>::Queue(const Queue<T>& st) {}
Given this template class
template<typename T>
class Queue {
private:
struct Node {
Node (T value) : value(value), next(nullptr) {}
Node (T value, Node* next) : value(value), next(next) {}
T value;
Node* next;
};
Node* head;
size_t sz;
void cleanList();
public:
Queue();
Queue(const Queue& st);
Queue& operator=(const Queue& st);
~Queue();
size_t size() const noexcept;
bool isEmpty() const noexcept;
T& front();
const Tt& front() const;
void enqueue(const T& elem);
void dequeue();
};
The reason these examples work is because of the injected class name. When you have
template<typename T>
some_type<T> some_type<T>::some_func(some_type)
the return type is not in scope of the class so you need to provide the template parameter. In the function parameter you are in the scope of the class and in the scope of the class some_type is injected as a name for some_type<T> so you don't need to use some_type<T>.
I have an assignment in which I need to make template classes LinkedList and Traversible. Class Traversible needs to be a interface which declares functions for indexing and iteration of some collection class. I don't exactly know how to make an interface for iterator so LinkedList can use it. I was thinking something like
template <class T, class U>
class ITraversible {
public:
virtual U begin() noexcept = 0;
virtual U end() noexcept = 0;
virtual T& operator[](int) = 0;
};
and then in LinkedList header file I would do:
template <class T>
class LinkedList : public ITraversible<T,typename LinkedList<T>::iterator> {
struct node {
T data;
node* next, *prev;
explicit node(const T&);
void connect(node*);
};
node *head, *tail;
int n;
public:
/*************************ITERATOR************************/
class iterator : public std::iterator<std::bidirectional_iterator_tag, node*> {
typename LinkedList<T>::node* itr;
explicit iterator(node*) noexcept;
friend class LinkedList;
public:
iterator& operator++();
iterator operator++(int);
iterator& operator--();
iterator operator--(int);
bool operator==(const iterator&) const noexcept;
bool operator!=(const iterator&) const noexcept;
T& operator*() const noexcept;
T& operator->() const noexcept;
};
/**********************************************************/
LinkedList() noexcept;
LinkedList(std::initializer_list<T>);
LinkedList(const LinkedList&);
LinkedList(LinkedList&&) noexcept;
~LinkedList() noexcept;
LinkedList& operator=(LinkedList) noexcept;
template <class A>
friend void swap(LinkedList<A>&, LinkedList<A>&);
void add(const T&);
void removeAt(int);
int size() const noexcept;
bool operator==(const LinkedList&) const noexcept;
bool operator!=(const LinkedList&) const noexcept;
virtual T& operator[](int) override;
virtual iterator begin() noexcept override;
virtual iterator end() noexcept override;
};
But then Traversable template has two parameters and it should have only one.
Is this what I am supposed to do? Keep in mind I am new to templates and iterators.
When creating an interface you'll need to nail down the static types of what is being returned. These may behave dynamically different but you can't change the type other than using a subtype relation when returning pointers or references.
Personally, I think this exercise is ill-advised for a C++ context. It may make some sense when using Java or C#. However, similar behavior can be obtained. A rought sketch would be something like this (although this should work it will be rather slow):
template <typename T>
struct iterator_base {
virtual iterator_base() {}
virtual iterator_base<T>* do_clone() = 0;
virtual T& do_value() = 0;
virtual void do_next() = 0;
virtual bool do_equal() = 0;
// other operations to implement operator--, operator[], ...
};
template <typename It>
class iterator: iterator_base<typename std::iterator_traits<It>::value_type> {
typedef typename std::iterator_traits<It>::value_type> type;
It it;
iterator_base<type>* do_clone() { return new iterator<It>(*this); }
type& do_value() { return *this->it; }
void do_next() { ++this->it; }
bool do_equal(iterator_base<type>* other) {
return this->it == static_cast<iterator<It>>(other)->it;
}
};
template <typename T>
class poly_iterator {
std::unique_ptr<iterator_base<T>> ptr;
public:
poly_iterator(iterator_base<T>* ptr): ptr(ptr) {}
poly_iterator(poly_iterator const& other): ptr(other.ptr->clone()) {}
poly_iterator& operator= (poly_iterator other) {
other.swap(this);
return *this;
}
void swap(poly_iterator& other) { swap(this->ptr, other.ptr); }
T& operator*() { return this->ptr->value(); }
T* operator->() { return &this->operator*(); }
poly_iterator& operator++() { this->ptr->next(); return *this; }
poly_iterator operator++(int) {
poly_iterator rc(*this);
this->operator++();
return rc;
}
bool operator== (poly_iterator const& other) {
return this->ptr->equal(other.ptr.ptr());
}
bool operator!= (poly_iterator const& other) {
return !(*this == other);
}
// other operations
};
// define a suitable specialization of std::iterator_traits<poly_iterator<T>>
template <typename T>
class ITraversible {
virtual iterator_base<T>* do_begin() = 0;
virutal iterator_base<T>* do_end() = 0;
public:
poly_iterator<T> begin() { return this->do_begin(); }
poly_iterator<T> end() { return this->do_end(); }
// other operations
};
template <typename T>
class List: public ITraversible<T> {
std::list<T> list;
iterator_base<T>* do_begin() {
return iterator<std::list<T>::iterator>(list.begin());
}
iterator_base<T>* do_end() {
return iterator<std::list<T>::iterator>(list.end());
}
public:
// whatever is needed to fill the list
};
I have the following code:
template <class T>
class List {
public:
class Iterator;
class ConstIterator;
//Constructors and Destructors.
List() : head(NULL), tail(NULL), size(0) {}
List(const List& list);
~List();
//Methods
Iterator begin();
Iterator end();
void insert(const T& data);
void insert(const T& data, const Iterator& iterator);
void remove(const Iterator& iterator);
int getSize() const;
Iterator find();
void sort();
//Operators
List operator = (const List& list);
private:
class Node;
Node* head;
Node* tail;
int size;
};
template <class T>
class List<T>::Node
{
public:
//Constructors and destructors
Node(const T& _data, const Node* _next) : data(_data), next(_next) {}
~Node(); //Destructor
//Methods
//Operators
Node operator = (const Node& node);
private:
T data;
Node* next;
};
template<class T>
class List<T>::Iterator
{
public:
Iterator() : list(NULL), node(NULL){} //Constructor
Iterator(const Iterator& it) : list(it.list), node(it.node) {}
~Iterator(); //Destructor
Iterator& operator=(const Iterator& it);
T& operator * ();
T& operator ++ ();
T operator ++ (int);
T& operator -- ();
T operator -- (int);
bool operator == (const Iterator& iterator) const;
bool operator != (const Iterator& iterator) const;
private:
List<T>* list;
Node* node;
};
template<class T>
class List<T>::ConstIterator
{
public:
ConstIterator() : list(NULL), node(NULL){}
ConstIterator(const ConstIterator& it) : list(it.list), node(it.node) {}
~ConstIterator(); //Destructor
ConstIterator& operator=(const ConstIterator& it);
T& operator * ();
T& operator ++ ();
T operator ++ (int);
T& operator -- ();
T operator -- (int);
bool operator == (const ConstIterator& iterator) const;
bool operator != (const ConstIterator& iterator) const;
private:
const List<T>* list;
const Node* node;
};
template<class T>
Iterator List<T>::begin() {
return Iterator(this, head);
}
When I try to compile I get the following error:
error: expected constructor, destructor, or type conversion before ‘List’
On line:
Iterator List<T>::begin() {
I'm not sure what I'm doing wrong.
Iterator is not defined, but List<T>::Iterator is. You will also need to add typename:
template<class T>
typename List<T>::Iterator List<T>::begin() { ... };
Here, typename is required as an ambiguitator to tell the compiler that List<T>::Iterator is a type (rather than a static member). This is always required in the templated context (see here).
if you write the body of the function outside the class declaration, it should be:
typename List<T>::Iterator List<T>::begin() { ... }
edit: typename added
so thats what i got going.
template<class T>
class List{
Node<T> head;
int size;
public:
class Iterator;
template <class T>
class List<T>::Iterator{
public:
Iterator& operator++();
i'm trying to implement like so:
template<class T>
typename List<T>::Iterator& List<T>::Iterator::operator++()
but it keeps telling me "Member declaration not found"
EDIT:
thats the entire relevent code:
template <class T>
class Node {
T data;
Node<T>* next;
public:
Node () : next(0){};
Node (const T& info, Node<T>* next = 0) : data(info), next(next){};
friend class List<T>;
friend class Iterator;
friend class ConstIterator;
};
template<class T>
class List{
Node<T> head;
int size;
void listSwap(Node<T>* node1, Node<T>* node2);
public:
class Iterator;
class ConstIterator;
List ();
List(const List<T>& list);
List& operator=(const List<T>& list);
ConstIterator begin() const;
Iterator begin();
ConstIterator end() const;
Iterator end();
void insert(const T& t);
void insert(const T& t,const Iterator& it);
void remove(const Iterator& it);
// template<class Function>
// ConstIterator find(Function f);
template<class Function>
Iterator find(Function f);
template<class Function>
void sort(Function f);
int getSize();
bool operator==(const List<T>& list2) const;
bool operator!=(const List<T>& list2) const;
~List();
};
template <class T>
class List<T>::Iterator{
List<T>* list;
Node<T>* index;
public:
Iterator(List<T> list);
Iterator(List<T> list, Iterator& it);
Iterator& operator++();
Iterator operator++(int);
T operator*();
bool operator==(const Iterator& iterator2);
bool operator!=(const Iterator& iterator2);
~Iterator();
friend class List<T>;
};
thought I think it is ok :/
so frustrating sometimes....
Thank you guys for the help!
You don't need template<class T> class List<T>::Iterator in the Iterator class definition if iterator is a nested class. Just class Iterator.
template<class T>
class List{
Node<T> head;
int size;
public:
class Iterator
{
public:
Iterator& operator++();
....
};
....
};
Either that, or you are missing the closing }; of your List class:
template<class T>
class List{
Node<T> head;
int size;
public:
class Iterator;
};
^^ HERE!
I see some obvious bugs, as the class List is not closed before you define List<T>::Iterator, but I presume it is so because you cut off some portion of your code.
Unfortunately, I was unable to reproduce your case. The following code:
class List {
int size;
public:
class Iterator;
};
template <class T>
class List<T>::Iterator {
public:
Iterator& operator++();
};
template <class T>
typename List<T>::Iterator& List<T>::Iterator::operator++() {
return *this;
}
int main() {
}
And it compiles just fine under g++ (4.6.3) and clang++ (3.1), so the problem is somewhere else which you are not showing us.
You first code sample seems to be shreeded beyond recognition.
As for your second (longer) section of code, I don't see anthing wrong with it aside from one suspect area. Your friend declarations inside Node will refer to some non-template Iterator and ConstIterator classes from global namespace. Meanwhile, Iterator and ConstIterator from List are templates that do not belong to global namespace. Were those friend declarations in Node supposed to refer to Iterator and ConstIterator from List or not?
Here is the .hpp file:
template<typename T>
LinkedQueue<T> operator=(const LinkedQueue<T> & lhs, const LinkedQueue<T> & rhs)
{
m_data = rhs.m_data;
m_next = rhs.m_next;
}
The error says that first line must be a nonstatic member function. Here is the class it is in:
template<typename T>
class LinkedQueue:public AbstractQueue<T>
{
public:
T m_data;
LinkedQueue *m_next;
LinkedQueue<T> operator=(const LinkedQueue<T> & rhs);
LinkedQueue();
void clear();
void enqueue(T x);
void dequeue();
const T& front() const;
bool isEmpty() const;
};
Any idea as to what silly thing I am doing wrong?
You should add a class qualifier to the function definition, and remove the unused lhs parameter:
template<typename T>
LinkedQueue<T>& LinkedQueue::operator=(const LinkedQueue<T> & rhs)
// ^--- & should be added to the declaration, too
{
m_data = rhs.m_data;
m_next = rhs.m_next;
return *this;
}
you should write look like this;
template<typename T>
class LinkedQueue:public AbstractQueue<T>
{
public:
T m_data;
LinkedQueue *m_next;
LinkedQueue<T> & operator=(const LinkedQueue<T> & rhs)
{
if (this != &rhs)
{
m_data = rhs.m_data;
m_next = rhs.m_next;
}
return *this;
}
LinkedQueue();
void clear();
void enqueue(T x);
void dequeue();
const T& front() const;
bool isEmpty() const;
};