Regex to "ignore" not "exclude" - regex

Question

I'm totally lost. I need a regular expression that
can detect any of the 4 starting urls like below
^(.*http://.*|.*http%3A%2F%2F.*|.*https://.*|.*https%3A%2F%2F.*)$
And ... .
should detect:
(any punctuation or space or backspace)(3 times the letter w in upper or lower case)(one dot)(anything)
And ... . which is important
Should Ignore, but NOT Exclude... . the following exact string (either it's present in the page or not)
http://www.w3.org
Which is complicated for me, because i still need to include it in the regex line
even if it's ignored, otherwise, it will match & be found in
(.*http://.*|.*http%3A%2F%2F.*|.*https://.*|.*https%3A%2F%2F.*)
And my aim is to find/match any url besides
http://www.w3.org
even if it's in the page, Or if it's not present.
so if there's only this in the page:
http://www.w3.org
& no other url.. then it shouldn't match.
Thanks Tyler but my regex knowledge is almost zero, i can only know what commands do when i right click on them to chose actions like in regulazy or regexr ((
So i updated my command according to the url i provided to you:
href%3D%22http%3A%2F%2Fwww%2Edommermuth%2D1%2Ecom
& it works:
https?(://|%3A%2F%2F)(?!www.w3.org)(.*)
But because of my lack of knowledge, i don't understand how to do that below
"What you could do is make the http part optional, or must match http or www or both. This type of regex came up in another question I answered recently - Multiple preg_replace RegEx for different URLs"
I tried to add this, but it doesn't work:
(www.)
All i'm missing now is detection of urls starting with www
(any punctuation or space or backspace)(3 times the letter w in upper or lower case)(one dot)(anything till it reaches a space or the end of a line)

Answer 1

OK so try this:
/\bhttps?(://|%3A%2F%2F)(?!www\.w3\.org)(.*)\b/g
Test here: http://regexr.com?38jp5
That test link uses javascript-style regex, but should work elsewhere.
The important part is the second half - a negative lookahead, that checks what follows is not the exact text www.w3.org
I compressed what you had: mine matches http then an optional s then either :// or %3A%2F%2F.
I wrapped the whole thing in word boundaries, you could change that to quotes or whatever you need. The global flag lets you match multiple items.
In regards to OP's questions:
D%22
could appear before http or https
this one is missing & should match:
href%3D%22http%3A%2F%2Fwww%2Edommermuth%2D1%2Ecom
If this matters, just remove the word boundary \b before and after the regex, so the http can match anywhere.
The regex command should detect: (any punctuation or space or backspace)(3 times the letter w in upper or lower case)(one dot)(anything)
This regex would fail to match a link like http://google.com - looking for www is really not a good way to check for a link on its own. What you could do is make the http part optional, or must match http or www or both. This type of regex came up in another question I answered recently - Multiple preg_replace RegEx for different URLs
Edit #2:
(any punctuation or space or backspace)(3 times the letter w in upper or lower case)(one dot)(anything till it reaches a space or the end of a line)
As I mention above, what you are describing will not match a url like http://google.com - but if that is what you want, use this:
(\W|^)[wW]{3}\.[^\s$]+
Instead of that, what I think you want is this, which is a combination of my first answer, and the link to a different post above.
((https?(://|%3A%2F%2F))(www\.)|(https?(://|%3A%2F%2F))|(www\.))(?!(www\.)?w3\.org)([^</\?\s]+)[^<\s]*
You'll want to use this regex with the Global and Insensitive flags