Looking for a way to use radio buttons in the Django admin. I would like to have 3 or 4 hard coded options the user can select from and I will use that selection to know what to do with the next text field. The options never need to change. Can anyone point me in the right direction? Google is not cooperating on this one...
I'm going to assume you want this on the change page for a Foo model object. Let's call the extra field my_option.
First, you'll need to use a custom form in your FooAdmin class so you can get the extra field in there:
class FooAdmin:
...
form FooForm
fields = (..., 'my_option', ...)
...
Then, just create the form with the extra option:
class FooForm(forms.ModelForm):
class Meta:
model = Foo
my_option = ChoiceField(
label = 'Options',
choices = (
(0, 'Don\'t change anything.'),
(1, 'Do some crazy stuff.'),
(2, 'Do other stuff.'),
),
initial = 0,
widget = RadioSelect,
)
ChoiceField defaults to using a select box, which is why you also need to override the widget type in the field's constructor. You can also check out TypedChoiceField if that serves your needs better.
Finally, you'll need to handle the field somewhere. I suggest overriding the clean() method in FooForm to get the value and set values in self.cleaned_data depending on what you want the option to do.
Related
I have a form (ModelForm) in Django, where I am adding a field for users in the init method as so:
self.fields["users"] = forms.ModelMultipleChoiceField(
queryset=users, widget=forms.CheckboxSelectMultiple, required=False,label="Add Designer(s)"
)
In the save method how I can iterate over the queryset for this field, however, I do not know how I can test if the particular model has been selected/checked. Help, please.
EDIT:
Let's say that you have a form where you want to be able to add users to a certain project, I set the users field as above (also usedMultipleChoiceField) but my real question is how do you determine the state of those checkboxes (which users should be added)?
Managed to fix it using MultipleChoiceField instead of ModelMultipleChoiceField. Then populated the choices with existing event IDs and passed it to the template.
In forms:
choices = forms.MultipleChoiceField(widget = forms.CheckboxSelectMultiple())
In views:
form.fields['choices'].choices = [(x.eventID, "Event ID: " + x.eventID) for x in unapproved]
Had to change some of the logic for finding and editing Event objects too.
The Django documentation states that a ModelMultipleChoiceField normalizes to a QuerySet of model instances. That means in your example, it will only return the users that have been checked. If none have been checked, it will return an empty QuerySet.
If you are overriding your ModelForm save method, you could include something like this:
selected_users = self.cleaned_data.get('users')
for user in selected_users:
project_users.add(user)
I want to show different fields (a html-option-field who gets Mymodel.object.all and a textfield) and save it to one model field.
How can I build this?
MultiValueField (https://docs.djangoproject.com/en/2.1/ref/forms/fields/) doesn't help with different fields?
Has someone an example? How can I define which kind of field it is?
EDIT:
How can I determine which field I want to save in the model-field? I use a ModelForm.
You should use forms.ModelChoiceField(choices=ModelClass.objects.all()) for the choicefield, you can also set the widget to be widget=forms.CheckboxSelectMultiple.
your form can be like
class SuperForm(forms.Form):
cool_field = forms.ModelChoiceField(
choices=ModelClass.objects.all(),
widget=forms.CheckboxSelectMultiple,
)
text_area = forms.CharField(widget=forms.Textarea)
I'm trying to create a form consisting of a multiple select field which is used to select multiple instances of my Person model.
class MyForm(forms.Form):
choices = [(p.id, str(p)) for p in Person.objects.all()]
my_field = forms.ChoiceField(widget=forms.SelectMultiple, choices=choices)
The widget looks exactly like I want, but when I submit the form, it fails with the message
Select a valid choice. ['2', '3'] is not one of the available choices.
What am I doing wrong? When removing the widget=forms.SelectMultiple, from the third line, it works, but then it's only a single select field.
You are getting the error because ChoiceField expects a single choice.
If you want to allow multiple choices, use a MultipleChoiceField.
my_field = forms.MultipleChoiceField(choices=choices)
Note you don't have to specify the widget, as it's forms.SelectMultiple by default.
I have a model and a form like this:
class MyModel(models.Model):
param = models.CharField()
param1 = models.CharField()
param2 = models.CharField()
class MyForm(forms.ModelForm):
class Meta:
model = MyModel
fields = ('param', 'param1', 'param2')
Then I have one drop down menu with different values and based on what value is selected I'm hiding and showing fields of MyForm. Now I have to take one step further and render param2 as a CheckboxInput widget if user selects a certain value from a drop down but in other cases it should be standard text field. So how would I do that?
I know this post is almost a year old, but it took me multiple hours to even find a post related to this topic (this is the only one I found, which came up as related when submitting my own question), so I felt the need to share my solution.
I wanted to have a form that would show and require a text field if an option from a dropdown menu matched a value stored in another model. I had a foreignKey relation between two models and I passed an instance of Model1 into the ModelForm for Model2. If a value chosen for a variable in Model2 matched a variable already set in Model1, I wanted to show and require a textfield. It was basically a "choose Other and then enter your own description" scenario.
I did not want the page to reload (I was trying to have this work in both mobile and desktop browsers with the least delay/reloads and using the same code for both), so I could not use the mentioned multiple forms loading in a view option. I started trying to do it with AJAX as suggested above when I realized I was over thinking the problem.
The answer was using JS and clean methods in the form. I added a non-required field (field1) that was not in Model2 to my Model2Form. I then hid this using jQuery and only displayed it (using jQuery) if the value of another field (field2) matched the value of the variable from Model1. To make that work, I did decide to have a hidden < span > in my template with the pk of the variable so I could easily grab it with jQuery. This jQuery worked perfectly for hiding and showing the field correctly so the user could choose the "other" value and then decided to choose a different one instead (and go back and forth endlessly).
I then used a clean method in my Model2Form for field1 that raised a ValidationError if no value was entered when the value in field2 matched my Model1 variable. I accessed that variable by using "self.other = Model1.variable" in my __ init __ method and then referencing that in the clean_field1 method.
I would have liked to have been able to accomplish this without having to hide and show a field with JS, but I think the only solutions for doing so with views or ajax caused delays/reloads that I did not want. Also, I liked the general simplicity of the method I used, rather than having to figure out how to pass partial forms back and forth through the HTTPRequest.
Update:
In my situation, I was creating entries for lost and found items and if the location where the item was found was not a provided option, then I wanted to show a textbox for the user to enter the location. I created a location object that was set as the "other" location and then displayed the textbox when that object was selected as the "found" location.
In forms.py, I added an extra CharField and use a clean method to check if the field is required and then throw a ValidationError if it wasn't filled in:
class Model2Form(forms.ModelForm):
def __init__(self, Model1, *args, **kwargs):
self.other = Model1.otherLocation
super(Model2Form, self).__init__(*args, **kwargs)
...
otherLocation = forms.CharField(
label="Location Description",
max_length=255,
required=False
)
def clean_otherLocation(self):
if self.cleaned_data['locationFound'] == self.other and not self.cleaned_data['otherLocation']:
raise ValidationError("Must describe the location.")
return self.cleaned_data['otherLocation']
Then in my JavaScript, I checked if the value of the "found" location was the "other" location (the value of which I had in a hidden span on my html page). I then used .show() and .hide() on the textbox's parent element as necessary:
$("#id_locationFound").change( function(){
if ($("#id_locationFound").val() == $("#otherLocation").attr("value")){ //if matches "other" location, display textbox; otherwise, hide textbox
$("#id_otherLocation").parent().show();
}else
$("#id_otherLocation").parent().hide();
});
Your best guess would be to trigger a "POST" request when you select something from your drop down menu.
The Value of that "POST" has to correspond your values you use to determine which field you would like to output.
Now you will actually need two forms:
class MyBaseForm(forms.ModelForm):
class Meta:
model = MyModel
fields = ('param', 'param1', 'param2')
class MyDropDownForm(MyBaseForm):
class Meta:
widgets = {
'param2': Select(attrs={...}),
}
So as you can see the DropDownForm has been derived from MyBaseForm to make sure it will have all the same properties. But we have modified the widget of one of the fields.
Now you can update your view. Please note, this is untested Python + Pseudocode
views.py
def myFormView(request):
if request.method == 'POST': # If the form has been submitted...
form = MyBaseForm(request.POST)
#submit button has not been pressed, so the dropdown has triggered the submission.
#Hence we won't safe the form, but reload it
if 'my_real_submitbotton' not in form.data:
if 'param1' == "Dropdown":
form = MyDropDownForm(request.POST)
else:
#do your normal form saving procedure
else:
form = ContactForm() # An unbound form
return render(request, 'yourTemplate.html', {
'form': form,
})
This mechanism does the following:
When the form is submitted it checks if you have pressed the "submit" button or have used a dropdown onChange to trigger a submission. My solution doesn't contain the javascript code you need to trigger the submission with an onChange. I just like to provide a way to solve it.
To use the 'my_real_submitbutton' in form.data construct you will be required to name your submit button:
<input type="submit" name="my_real_submitbutton" value="Submit" />
Of course you can choose any string as Name. :-)
In case of a submit by your dropdown field you must check which value has been selected in this drop down menu. If this value satisfies the condition you want to return a Dropdown Menu you create an instance of DropDownForm(request.POST) otherwise you can leave everything as it is and rerender your template.
On the downside this will refresh your page.
On the upside it will keep all the already entered field values. So no harm done here.
If you would like to avoid the page refresh you can keep my proposed idea but you need to render the new form via AJAX.
i have a form with a ChoiceField and a CharField. Now i want to enable the CharField just when i select a specific choice of the ChoiceField (e.g. choice 3). Otherwise the CharField should be disabled.
My ChoiceField
choices = (('1', 'some text',),
('2', 'some text',),
('3', 'some text',))
host = forms.ChoiceField(choices = choices)
And a simple CharField
hostAdress = forms.CharField()
Do you have any ideas to get it this way?
you can start with the char field disabled/hidden and use javascript to catch change event on the select box and change the charfield on that event. For example:
$("#id_choice").change(function(eObj) {
$("#id_char").removeAttr("disabled");
this is just an example (using jQuery), you need to make sure to disable the charfield again if the select box is unselected (not sure if you allow this behaviour) and you also need to handle the display of form errors properly if you hide the field and not enable/disable it.
I would use jQuery for this.
$('your-select-input-selector').change(function() {
var bDisable = true;
if ($(this).val() == '3'):
bDisable = !bDisabled;
$('your-text-input-selector').prop('disabled', bDisable);
});
You also need to handle the case where the select input is already set on the value 3 when you first load the page.