How do i print each line here in a for loop - python-2.7

Question

thanks for the follow :)
hii... if u want to make a new friend just add me on facebook! :) xx
Just wanna say if you ever feel lonely or sad or bored, just come and talk to me. I'm free anytime :)
I hope she not a spy for someone. I hope she real on neautral side. Because just her who i trust. :-)
not always but sometimes maybe :)
\u201c Funny how you get what you want and pray for when you want the same thing God wants. :)
Thank you :) can you follow me on Twitter so I can DM you?
RT dj got us a fallin in love and yeah earth number one m\u00fcsic listen thank you king :-)
found a cheeky weekend for \u00a380 return that's flights + hotel.. middle of april, im still looking pal :)
RT happy birthday mary ! Hope you have a good day :)
Thank god twitters not blocked on the school computers cause all my data is gone on my phone :(
enjoy tmrro. saw them earlier this wk here in tokyo :)
UPDATE:
Oki, maybe my question was wrong. I have to do this:
Open file and read from it
Remove some links, names and stuff from it (I have used regex, but don't know if it the right way to do
After i got clean code (only tweets with sad face or happy face) i have to print each line out, cause i have to loop each like this:
for line in tweets:
if '' in line:
cl.train(line,'happy')
else if '' in line:
cl.train(line,'sad')
My code so far you see here, but it doesn't work yet.
import re
from pprint import pprint
tweets = []
tweets = open('englishtweet.txt').read()
regex_username = '#[^\s]*' # regex to detect username in file
regex_url = 'http[^\s]*' # regex to detect url in file
regex_names = '#[^\s]*' # regex to detect # in file
for username in re.findall(regex_username, tweets):
tweets = tweets.replace(username, '')
for url in re.findall(regex_url, tweets):
tweets = tweets.replace(url, '')
for names in re.findall(regex_names, tweets):
tweets = tweets.replace(names, '')

Answer 1

If you want to read the first line, use next
with open("englishtweet.txt","r") as infile:
print next(infile).strip()
# this prints the first line only, and consumes the first value from the
# generator so this:
for line in infile:
print line.strip()
# will print every line BUT the first (since the first has been consumed)
I'm also using a context manager here, which will automatically close the file once you exit the with block instead of having to remember to call tweets.close(), and also will handle in case of error (depending on what else you're doing in your file, you may throw a handled exception that doesn't allow you to get to the .close statement).
If your file is very small, you could use .readlines:
with open("englishtweet.txt","r") as infile:
tweets = infile.readlines()
# tweets is now a list, each element is a separate line from the file
print tweets[0] # so element 0 is the first line
for line in tweets[1:]: # the rest of the lines:
print line.strip()
However that's not really suggested to read a whole file object into memory, as with some files it can simply be a huge memory waster, especially if you only need the first line -- no reason to read the whole thing to memory.
That said, since it looks like you may be using these for more than just one iteration, maybe readlines IS the best approach

Answer 2

You almost have it. Just remove the .read() when you originally open the file. Then you can loop through the lines.
tweets = open('englishtweet.txt','r')
for line in tweets:
print line
tweets.close()