How to get one picture from YUV frame in C++ - c++

Question

In C++ i have an
LPBYTE pYUV;
It's contains a YUV data. I used this code to save it to an image file named Original.bmp
BITMAPINFOHEADER* bi = new BITMAPINFOHEADER;
bi->biSize = sizeof(BITMAPINFOHEADER);
bi->biWidth = pVSI->nWidth;
bi->biHeight = pVSI->nHeight;
bi->biPlanes = 1;
bi->biBitCount = 24;
bi->biCompression = 0;
bi->biSizeImage = 0;
bi->biXPelsPerMeter = 2835;
bi->biYPelsPerMeter = 2835;
bi->biClrUsed = 0;
bi->biClrImportant = 0;
BITMAPINFO* bmi = (BITMAPINFO*)bi;
HDC dc = ::GetDC(NULL);
HBITMAP bmp = CreateDIBitmap(dc, bi, CBM_INIT, pYUV, bmi, DIB_RGB_COLORS);
::ReleaseDC(NULL, dc);
CBitmapEx bitmap;
bitmap.Load(bmp);
bitmap.Save(_T("Original.bmp"));
When i open the Original.bmp, it's look like this
It's have too many same picture in the image.How do i process the LPBYTE pYUV to make one picture in the Original.bmp file ?
ps: I can do this by draw it to DirectX by this code.
But i don't know how to write it to image file
LPBYTE apDst[3] = { 0 };
apDst[0] = (LPBYTE)pSurface; // Y
apDst[1] = (LPBYTE)pSurface + nPitch*nH; // U
apDst[2] = (LPBYTE)pSurface + nPitch*nH * 5 / 4; //V
LPBYTE apSrc[3] = { 0 };
apSrc[0] = pYUV; // Y
apSrc[1] = pYUV + nW*nH * 5 / 4; // V
apSrc[2] = pYUV + nW*nH; // U
int anPch[3] = { 0 };
anPch[0] = nW; // Y
anPch[1] = nW / 2; // V
anPch[2] = nW / 2; // U
LPBYTE pDst, pSrc;
int i, k;
int w, h, p;
int div[3] = { 1, 2, 2 };
for (k = 0; k < 3; k++)
{
pSrc = apSrc[k];
pDst = apDst[k];
w = nW / div[k]; // w means the width of one row
h = nH / div[k]; // h means the rows
p = nPitch / div[k];
for (i = 0; i < h; i++)
{
memcpy(pDst, pSrc, w);
pDst += p;
pSrc += anPch[k];
}
}
and It work like this
Thanks in advance.