Django ORM most occuring value - django

Question

I have a model where basically i am Tracking users' activities. I want to know what is the page the user have accessed MOST.
Here are my modals.
class Visitor(models.Model):
session_key = models.CharField(max_length=40, primary_key=True)
user = models.ForeignKey(User, related_name='visit_history', null=True, editable=False)
....
class Pageview(models.Model):
visitor = models.ForeignKey(Visitor, related_name='pageviews')
url = models.CharField(max_length=500)
method = models.CharField(max_length=20, null=True)
view_time = models.DateTimeField()
Here is my query.
Pageview.objects.values('visitor__user__first_name', 'visitor__user__last_name', 'visitor__user').annotate(url_count=Count('url')).annotate(url_count_unique=Count('url', distinct=True))
Here i am getting users number of urls visited, and number of unique urls visited.
Here i also want to know which is the url user have visited the most?
EDIT
Translation of my query.
Goto PageViews and count the occurring of unique URLS.(how many times a url have occurred.) and give me the one that have most visited count against each user.
I hope the question is clear, if not let me know.

Answer 1

IMHO you're better off with a many-to-many relationship. You would have something like:
class VisitedURLs(models.Model):
page = models.ForeignKey(Visitor, ....)
user = models.ForeignKey(User, ....)
timestamp = models.DateTimeField(auto_now_add=True)
and the original models become something like:
class Visitor(models.Model):
members = models.ManyToManyField(PageView, through='VisitedURLs')
class PageView(models.Model):
url = models.CharField(max_length=500)
method = models.CharField(max_length=20, null=True)
In this case, you can use the count/distinct on the visitedURLs model and when you get an object of that type you'll have a FK to a Visitor object (which would give you the user...) and a FK to the URL.
Another way is to explicitly count each unique visitor/url combination and store it somewhere. Depending on usage (e.g. if you want to compute/display this often) you may be better off with the dedicated storage.

Answer 2

Here is the solution that i have come up with.
Pageview.objects.filter(visitor__user_id=user['visitor__user_id']).values(
'url').annotate(page_count=Count('id')).order_by('-page_count')
if max_visited_node:
user['max_visited_node'] = max_visited_node[0]
by this way i can get the count of the all the pages the user have visited. then i order them by that count and then i get the top first element which contains the URL and page_count.
This is what i was looking for. the suggestion of Laur lvan is worth considerable.