How can identify a blank line in C++? - c++

I'm reading in information from a file. I need a counter that counts how many text filled lines there are. I need that counter to stop if there is any blank line (even if there are text filled lines after that blank line).
How would I do this? Because I'm not exactly sure how to identify a blank line to stop the counter there.

If you are using std::getline then you can just detect an empty line by checking if the std::string you have just read is empty.
std::ifstream stream;
stream.open("file.txt");
std::string text;
while(std::getline(stream,text))
if(!text.size())
std::cout << "empty" << std::endl;

I'd suggest using std::getline for it:
#include <string>
#include <iostream>
int main()
{
unsigned counter = 0;
std::string line;
while (std::getline(std::cin, line) && line != "")
++counter;
std::cout << counter << std::endl;
return 0;
}
Since #Edward made a comment about handling whitespace and it might be important. When lines with only whitespaces are considered as "empty lines" too I'd suggest changing it to:
#include <string>
#include <iostream>
#include <algorithm>
#include <cctype>
int main()
{
unsigned counter = 0;
std::string line;
while (std::getline(std::cin, line) &&
std::find_if_not( line.begin(), line.end(), std::isspace != line.end()) {
++counter;
}
std::cout << counter << std::endl;
return 0;
}
It's quite verbose, but the advantage is that it uses std::isspace to handle all different kind of spaces (e.g. ' ', '\t', '\v', etc...) and you don't have to worry if you handle them correctly.

In C++ 11 you can use,
std::isblank

In a loop, read all lines, one-by-one, into a single string variable. You can use a std::getline function for that.
Each time after reading a line into that variable, check its length. If it's zero, then the line is empty, and in that case break the loop.
However, checking for empty lines like is not always really right thing. If you are sure that the lines will be empty, then it's OK. But if your "empty" lines can contain whitespaces,
123 2 312 3213
12 3123 123
// <--- Here are SPACEs. Is it "empty"?
123 123 213
123 21312 3
then you might need to not check for "zero-length", but rather whether "all characters are whitespaces".

No error checking, no protection, just a simple example... It is not tested, but you get the gist.
#incldue <iostream>
#include <string>
using namespace std;
int main()
{
string str = "";
int blank = 0, text = 0;
ifstream myfile;
myfile.open("pathToFile");
while(getline(myfile,str))
{
if(str == "")
{
++blank;
}
else
{
++text;
}
}
cout << "Blank: " << blank << "\t" << "With text: " << text;
return 0;
}

Simply check the string length and use a line counter. When the string length is zero (i.e., the string is blank) print the line counter. Sample code is provided for your reference:
// Reading a text file
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main () {
string line;
ifstream myfile ("example.txt");
int i = 0;
if (myfile.is_open())
{
while (getline (myfile, line))
{
i++;
// cout << line << '\n';
if (line.length() == 0)
break;
}
cout << "blank line found at line no. " << i << "\n";
myfile.close();
}
else
cout << "Unable to open file";
return 0;
}

Related

Having an issue passing an array to a Function as only first word is printed c++

I am new to passing values to functions, please guide me what I am doing wrong here, thanks!
The question: Write a C++ program in which, read a c-string sentence
one by one from a file “sentence .txt”. Now your task is to break each
word of sentence into another c-string word, now write that word into
a file “word.txt”. Note : You must create atleast 1 function to
separate the words from sentence, you cannot use strings.
#include <iostream>
#include <fstream>
using namespace std;
char sentence2word(char array[100])
{
ofstream fout2;
fout2.open("word.txt");
fout2 << array << endl;
return array[100];
}
int main()
{
ifstream fin;
fin.open("sentence.txt");
char array[100];
fin >> array;
cout << "Output successful!";
sentence2word(array);
return 0;
system("pause");
}
The following program show how to get started with reading and writing from/into text files in C++. This is just to get you started and in practice i use std::string and std::istringstream to do this but in your note it is written that we cannot use strings so i did not use std::string. The program reads line by line from an input.txt file and write word by word into an output.txt file.
#include <iostream>
#include <fstream>//needed to read/write files
#define MAX_NUMBER_OF_CHARACTERS 500
using namespace std;
//function that writes lines word by word into output.txt
void writeWordByWord(std::ofstream &m_outFile, char (&lineArg)[MAX_NUMBER_OF_CHARACTERS])
{ int i = 0;
while(lineArg[i] != '\0')
{
if(lineArg[i] != ' ')
{m_outFile << lineArg[i];
//std::cout<< lineArg[i]<<" wrote"<<std::endl;
++i;
}
else{
m_outFile << '\n';
++i;
}
}
//m_outFile << '\n';
}
int main()
{
cout << "Hello World" << endl;
char line[MAX_NUMBER_OF_CHARACTERS];
std::ifstream inFile("input.txt");
std::ofstream outFile("output.txt");
while(inFile.getline(line, MAX_NUMBER_OF_CHARACTERS, '\n'))
{
std::cout<<line<<std::endl;
writeWordByWord(outFile, line);
}
inFile.close();
outFile.close();
return 0;
}

How to parse table of numbers in C++

I need to parse a table of numbers formatted as ascii text. There are 36 space delimited signed integers per line of text and about 3000 lines in the file. The input file is generated by me in Matlab so I could modify the format. On the other hand, I also want to be able to parse the same file in VHDL and so ascii text is about the only format possible.
So far, I have a little program like this that can loop through all the lines of the input file. I just haven't found a way to get individual numbers out of the line. I am not a C++ purest. I would consider fscanf() but 36 numbers is a bit much for that. Please suggest practical ways to get numbers out of a text file.
int main()
{
string line;
ifstream myfile("CorrOut.dat");
if (!myfile.is_open())
cout << "Unable to open file";
else{
while (getline(myfile, line))
{
cout << line << '\n';
}
myfile.close();
}
return 0;
}
Use std::istringstream. Here is an example:
#include <sstream>
#include <string>
#include <fstream>
#include <iostream>
using namespace std;
int main()
{
string line;
istringstream strm;
int num;
ifstream ifs("YourData");
while (getline(ifs, line))
{
istringstream strm(line);
while ( strm >> num )
cout << num << " ";
cout << "\n";
}
}
Live Example
If you want to create a table, use a std::vector or other suitable container:
#include <sstream>
#include <string>
#include <fstream>
#include <iostream>
#include <vector>
using namespace std;
int main()
{
string line;
// our 2 dimensional table
vector<vector<int>> table;
istringstream strm;
int num;
ifstream ifs("YourData");
while (getline(ifs, line))
{
vector<int> vInt;
istringstream strm(line);
while ( strm >> num )
vInt.push_back(num);
table.push_back(vInt);
}
}
The table vector gets populated, row by row. Note we created an intermediate vector to store each row, and then that row gets added to the table.
Live Example
You can use a few different approaches, the one offered above is probable the quickest of them, however in case you have different delimitation characters you may consider one of the following solutions:
The first solution, read strings line by line. After that it use the find function in order to find the first position o the specific delimiter. It then removes the number read and continues till the delimiter is not found anymore.
You can customize the delimiter by modifying the delimiter variable value.
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
int main()
{
string line;
ifstream myfile("CorrOut.dat");
string delimiter = " ";
size_t pos = 0;
string token;
vector<vector<int>> data;
if (!myfile.is_open())
cout << "Unable to open file";
else {
while (getline(myfile, line))
{
vector<int> temp;
pos = 0;
while ((pos = line.find(delimiter)) != std::string::npos) {
token = line.substr(0, pos);
std::cout << token << std::endl;
line.erase(0, pos + delimiter.length());
temp.push_back(atoi(token.c_str()));
}
data.push_back(temp);
}
myfile.close();
}
return 0;
}
The second solution make use of regex and it doesn't care about the delimiter use, it will search and match any integers found in the string.
#include <iostream>
#include <string>
#include <regex> // The new library introduced in C++ 11
#include <fstream>
using namespace std;
int main()
{
string line;
ifstream myfile("CorrOut.dat");
std::smatch m;
std::regex e("[-+]?\\d+");
vector<vector<int>> data;
if (!myfile.is_open())
cout << "Unable to open file";
else {
while (getline(myfile, line))
{
vector<int> temp;
while (regex_search(line, m, e)) {
for (auto x : m) {
std::cout << x.str() << " ";
temp.push_back(atoi(x.str().c_str()));
}
std::cout << std::endl;
line = m.suffix().str();
}
data.push_back(temp);
}
myfile.close();
}
return 0;
}

Read a file of strings with quotes and commas into string array

Let's say I have a file of names such as:
"erica","bosley","bob","david","janice"
That is, quotes around each name, each name separated by a comma with no space in between.
I want to read these into an array of strings, but can't seem to find the ignore/get/getline/whatever combo to work. I imagine this is a common problem but I'm trying to get better at file I/O and don't know much yet. Here's a basic version that just reads in the entire file as one string (NOT what I want, obviously):
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
fstream iFile("names.txt", ios::in);
string names[5];
int index = 0;
while(iFile)
{
iFile >> names[index];
index++;
}
for(int i = 0; i < 5; i++)
{
cout << "names[" << i << "]: " << names[i] << endl;
}
Output:
names[0]: "erica","bosley","bob","david","janice"
names[1]:
names[2]:
names[3]:
names[4]:
Also, I understand why it all gets read as a single string, but then why are the remaining elements not filled with garbage?
To be clear, I want the output to look like:
names[0]: erica
names[1]: bosley
names[2]: bob
names[3]: david
names[4]: janice
The easiest way to handle this:
Read the entire file and place it into a string, Here is an example of how to do it.
Split the string that you got from number 1. Here is an example of how to do that.
Stream extraction delimits by a space. Therefore the entire file gets read as one string. What you want instead is to split the string by commas.
#include <iostream>
#include <fstream>
#include <algorithm>
#include <sstream>
fstream iFile("names.txt", ios::in);
string file;
iFile >> file;
std::istringstream ss(file);
std::string token;
std::vector<std::string> names;
while(std::getline(ss, token, ',')) {
names.push_back(token);
}
To remove the quotes, use this code:
for (unsigned int i = 0; i < names.size(); i++) {
auto it = std::remove_if(names[i].begin(), names[i].end(), [&] (char c) { return c == '"'; });
names[i] = std::string(names[i].begin(), it);
}
remove_if returns the end iterator for the transformed string, which is why you construct the new string with (s.begin(), it).
Then output it:
for (unsigned int i = 0; i < names.size(); i++) {
std::cout << "names["<<i<<"]: " << names[i] << std::endl;
}
Live Example

how do I use ' string::find ' to find a word in file using C++

I'm creating a program that will open a file and search for a desired word within the text.
I created the following word bank...
Lawyer
Smith Janes
Doctor
Michael Zane
Teacher
Maria Omaha
#include <iostream>
#include <string>
#include <fstream>
#include <stdlib.h>
#include <string>
#include <sstream>
using namespace std;
int main ()
{
// Declarations
string reply;
string inputFileName;
ifstream inputFile;
char character;
cout << "Input file name: ";
getline(cin, inputFileName);
// Open the input file.
inputFile.open(inputFileName.c_str());
// Check the file opened successfully.
if ( ! inputFile.is_open())
{
cout << "Unable to open input file." << endl;
cout << "Press enter to continue...";
getline(cin, reply);
return 1;
}
Now that I save the whole file into a string how could I search inside that string
for a specific word I'm looking for...
I'm learning C++ from this Website http://www.cprogramming.com/tutorial/lesson10.html
I think you use string::find but I couldn't find much reference on how to search beside this wesite..
http://www.cplusplus.com/reference/string/string/find/
This section will display the whole file.
string original;
getline(inputFile, original, '\0');
cout << original << endl;
cout << "\nEnd of file reached\n" << endl;
// Close the input file stream
inputFile.close();
cout << "Press enter to continue...";
return 0;
}
This is how I think the program should act...
Please enter a word: Smith Janes
Smith Janes Lawyer
another example....
Please enter a word: Doctor
Michael Zane Doctor
find returns the position (zero based offset) in the string where the word is found. If the word is not found it returns npos.
#include <string>
#include <iostream>
int main()
{
std::string haystack("some string with words in it");
std::string::size_type pos = haystack.find("words");
if(pos != std::string::npos)
{
std::cout << "found \"words\" at position " << pos << std::endl;
}
else
{
std::cout << "\"words\" not found" << std::endl;
}
}
#include <string>
#include <iostream>
#include <cstdlib>
int main() {
std::string haystack = "Lawyer\nSmith Janes\nDoctor\nMichael Zane\nTeacher\nMaria Omaha\n";
std::string needle = "Janes";
auto res = haystack.find(needle);
if (std::string::npos == res) {
std::cout << "Not found\n";
std::exit(EXIT_FAILURE);
}
std::cout << res << '\n';
}
res is an index into the string at the point where "Janes" is (Should be 13).
The functionality you appear to be asking for is more complex than just finding some content in a string. The output you show has a user input either a name or a profession and the output is the related profession or name.
It's simple to write a program that shows the line the 'needle' is on, or to show always show the previous line, or always show the next line. But what you're asking for is to show one or the other depending on what was searched for.
One simple way we could implement this is to find if the needle is on an even or odd line and base what we show on that.
First we get the line number.
auto line_num = std::count(std::begin(haystack), std::begin(haystack) + res, '\n');
Based on the content you showed, professions are on even lines and names are on odd lines. We can easily get the line numbers we want:
auto profession_line_num = line_num/2*2;
auto name_line_num = line_num/2*2 + 1;
Next, we can split the text up into lines since we need to work with whole lines and get lines by index. The method I show below makes a copy of the text and is inefficient, but it's easy.
Here's a split function:
std::vector<std::string> split(std::string const &s, std::string const &delims) {
std::vector<std::string> res;
std::string::size_type i = 0;
auto found = s.find_first_of(delims, i);
while (std::string::npos != found) {
res.emplace_back(s, i, found-i);
i = found+1;
found = s.find_first_of(delims, i);
}
res.emplace_back(s, i);
return res;
}
And we use the split function like so:
auto lines = split(haystack, '\n');
Now, we can show the lines we want.
std::cout << lines[name_line_num] << ' ' << lines[profession_line_num] << '\n';
Which once you put the program together prints:
Smith Janes Lawyer
I think this has all the information you need.
http://www.cplusplus.com/reference/string/string/find/

Trying to read from a file and skip punctuation in C++, tips?

I'm trying to read from a file, and make a vector of all the words from the file. What I tried to do below is have the user input the filename, and then have the code open the file, and skip characters if they aren't alphanumeric, then input that to a file.
Right now it just closes immediately when I input the filename. Any idea what I could be doing wrong?
#include <vector>
#include <string>
#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;
int main()
{
string line; //for storing words
vector<string> words; //unspecified size vector
string whichbook;
cout << "Welcome to the book analysis program. Please input the filename of the book you would like to analyze: ";
cin >> whichbook;
cout << endl;
ifstream bookread;
//could be issue
//ofstream bookoutput("results.txt");
bookread.open(whichbook.c_str());
//assert(!bookread.fail());
if(bookread.is_open()){
while(bookread.good()){
getline(bookread, line);
cout << line;
while(isalnum(bookread)){
words.push_back(bookread);
}
}
}
cout << words[];
}
I think I'd do the job a bit differently. Since you want to ignore all but alphanumeric characters, I'd start by defining a locale that treats all other characters as white space:
struct digits_only: std::ctype<char> {
digits_only(): std::ctype<char>(get_table()) {}
static std::ctype_base::mask const* get_table() {
static std::vector<std::ctype_base::mask>
rc(std::ctype<char>::table_size,std::ctype_base::space);
std::fill(&rc['0'], &rc['9']+1, std::ctype_base::digit);
std::fill(&rc['a'], &rc['z']+1, std::ctype_base::lower);
std::fill(&rc['A'], &rc['Z']+1, std::ctype_base::upper);
return &rc[0];
}
};
That makes reading words/numbers from the stream quite trivial. For example:
int main() {
char const test[] = "This is a bunch=of-words and 2#numbers#4(with)stuff to\tseparate,them, I think.";
std::istringstream infile(test);
infile.imbue(std::locale(std::locale(), new digits_only));
std::copy(std::istream_iterator<std::string>(infile),
std::istream_iterator<std::string>(),
std::ostream_iterator<std::string>(std::cout, "\n"));
return 0;
}
For the moment, I've copied the words/numbers to standard output, but copying to a vector just means giving a different iterator to std::copy. For real use, we'd undoubtedly want to get the data from an std::ifstream as well, but (again) it's just a matter of supplying the correct iterator. Just open the file, imbue it with the locale, and read your words/numbers. All the punctuation, etc., will be ignored automatically.
The following would read every line, skip non-alpha numeric characters and add each line as an item to the output vector. You can adapt it so it outputs words instead of lines. I did not want to provide the entire solution, as this looks a bit like a homework problem.
#include <vector>
#include <sstream>
#include <string>
#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;
int _tmain(int argc, _TCHAR* argv[])
{
string line; //for storing words
vector<string> words; //unspecified size vector
string whichbook;
cout << "Welcome to the book analysis program. Please input the filename of the book you would like to analyze: ";
cin >> whichbook;
cout << endl;
ifstream bookread;
//could be issue
//ofstream bookoutput("results.txt");
bookread.open(whichbook.c_str());
//assert(!bookread.fail());
if(bookread.is_open()){
while(!(bookread.eof())){
line = "";
getline(bookread, line);
string lineToAdd = "";
for(int i = 0 ; i < line.size(); ++i)
{
if(isalnum(line[i]) || line[i] == ' ')
{
if(line[i] == ' ')
lineToAdd.append(" ");
else
{ // just add the newly read character to the string 'lineToAdd'
stringstream ss;
string s;
ss << line[i];
ss >> s;
lineToAdd.append(s);
}
}
}
words.push_back(lineToAdd);
}
}
for(int i = 0 ; i < words.size(); ++i)
cout << words[i] + " ";
return 0;
}