C++ Subscript operator - c++

Question

I have written a code but it doesn't seems to work. Every time I execute the program, I get this error
Run-Time Check Failure #2 - Stack around the variable 'ary' was
corrupted
anyway here is my code(it is a small code)
#include <iostream>
using namespace std;
class Arrayz{
private:
int arry[5];
public:
Arrayz(){}
void setInf(){
for(int i = 0; i < 5; ++i){
cout << "Enter age of your friends: ";
cin >> arry[5];
}
}
const int& operator [](const int pos){
return arry[pos];
}
};
int main(){
Arrayz ary;
ary.setInf();
cout << "Here are your friend's age: " << endl;
for (int i = 0; i < 5; ++i){
cout << ary[i] << endl;
}
return 0;
}
also can you also help in subscript operator, I just don't seem to understand how to declare and use them. Also it seems pretty foolish to write a program without first understanding it first but anyway help would be appreciated :)

Answer 1

You probably mean cin >> arry[i]; – i, not 5.

Answer 2

You made a typo in member function setInf. Instead of cin >> arry[5]; there shall be cin >> arry[i];
void setInf(){
for(int i = 0; i < 5; ++i){
cout << "Enter age of your friends: ";
cin >> arry[i];
}
}
As for the subscript operator then you defined it correctly
const int& operator [](const int pos){
return arry[pos];
}
though there is no need to declare the parameter with qualifier const. Also the operator itself should have qualifier const You could write simply
const int& operator [](int pos) const {
return arry[pos];
}
Or
int operator [](int pos) const {
return arry[pos];
}
Also you could define its non-const version when the user could change elements of the array arry.
int & operator []( int pos) {
return arry[pos];
}
Also it is a good idea that your class had a member function that would return the size of the array. For example
class Arrayz{
private:
static const size_t N = 5;
int arry[N];
public:
Arrayz(){}
void setInf(){
for(int i = 0; i < N; ++i){
cout << "Enter age of your friends: ";
cin >> arry[i];
}
}
int operator [](int pos) const {
return arry[pos];
}
int & operator []( int pos) {
return arry[pos];
}
size_t size() const { return N; }
};
And in main you could write
for (int i = 0; i < ary.size(); ++i){
cout << ary[i] << endl;
}