I want to find all users with a first name that has an empty space at the beginning or ending.
It could look like: "Juliette " or " Juliette"
For now I only have the regex to match when the space is at the end of string:
^[ab]:[[:space:]]|$
I didn't find how to match the empty space at the beginning of the string and I don't know if it's possible to accomplish both of these conditions in one regex ?
Thanks for your help.
Test for Strippable Whitespace without Regexp
There's a little trick you can use with String#strip!, which returns nil if it can't find whitespace to strip. For example:
# return true if str has leading/trailing whitespace;
# otherwise returns false
def strippable? str
{ str => !!str.dup.strip! }
end
# leading space, trailing space, no space
test_values = [ ' foo', 'foo ', 'foo' ]
test_values.map { |str| strippable? str }
#=> [{" foo"=>true}, {"foo "=>true}, {"foo"=>false}]
This doesn't rely on a regular expression, but rather on properties of the String and the Boolean result of an inverted #strip!. Regardless of whether the Ruby engine uses regular expressions under the hood, these types of String methods are often faster than comparable Regexp matches, but your mileage and specific use cases may vary.
Alternatives with Regexp
Using the same test data as above, you could do something similar with a regular expression. For example:
# leading space, trailing space, no space
test_values = [ ' foo', 'foo ', 'foo' ]
# test start/end of string
test_values = [ ' foo', 'foo ', 'foo' ].grep /\A\s+|\s+\z/
#=> [" foo", "foo "]
# test start/end of line
test_values = [ ' foo', 'foo ', 'foo' ].grep /^\s+|\s+$/
#=> [" foo", "foo "]
Benchmarks
require 'benchmark'
ITERATIONS = 1_000_000
TEST_VALUES = [ ' foo', 'foo ', 'foo' ]
def regex_grep array
array.grep /^\s+|\s+$/
end
def string_strip array
array.map { |str| { str => !!str.dup.strip! } }
end
Benchmark.bmbm do |x|
n = ITERATIONS
x.report('regex') { n.times { regexp_grep TEST_VALUES } }
x.report('strip') { n.times { string_strip TEST_VALUES } }
end
user system total real
regex 1.539269 0.001325 1.540594 ( 1.541438)
strip 1.256836 0.001357 1.258193 ( 1.259955)
A quarter second over a million iterations may not seem like a big difference, but on significantly larger data sets or iterations it can add up. Whether or not it's enough for you to care for this particular use case is up to you, but the general pattern is that native String methods (regardless of how they're implemented by the interpreter under the hood) are generally faster than regular expression pattern matching. Of course there are edge cases, but that's what benchmarks are for!
You can use
/\A([a-zA-Z]+ | [a-zA-Z]+)\z/
/\A(?:[[:alpha:]]+[[:space:]]|[[:space:]][[:alpha:]]+)\z/
/\A(?:\p{L}+[\p{Z}\t]|[\p{Z}\t]\p{L}+)\z/
See the Rubular demo (with line anchors instead of string anchors used for the demo purposes)
Details:
\A - a string start anchor
(...) - a capturing group
(?:...) - a non-capturing group (it is preferred here since you are not extracting, just validating)
[a-zA-Z]+ - any one or more ASCII letters
\p{L}+ - any one or more Unicode letters
| - or
\z - end of string anchor.
I want to match a portion of a string using a regular expression and then access that parenthesized substring:
var myString = "something format_abc"; // I want "abc"
var arr = /(?:^|\s)format_(.*?)(?:\s|$)/.exec(myString);
console.log(arr); // Prints: [" format_abc", "abc"] .. so far so good.
console.log(arr[1]); // Prints: undefined (???)
console.log(arr[0]); // Prints: format_undefined (!!!)
What am I doing wrong?
I've discovered that there was nothing wrong with the regular expression code above: the actual string which I was testing against was this:
"date format_%A"
Reporting that "%A" is undefined seems a very strange behaviour, but it is not directly related to this question, so I've opened a new one, Why is a matched substring returning "undefined" in JavaScript?.
The issue was that console.log takes its parameters like a printf statement, and since the string I was logging ("%A") had a special value, it was trying to find the value of the next parameter.
Update: 2019-09-10
The old way to iterate over multiple matches was not very intuitive. This lead to the proposal of the String.prototype.matchAll method. This new method is in the ECMAScript 2020 specification. It gives us a clean API and solves multiple problems. It is in major browsers and JS engines since Chrome 73+ / Node 12+ and Firefox 67+.
The method returns an iterator and is used as follows:
const string = "something format_abc";
const regexp = /(?:^|\s)format_(.*?)(?:\s|$)/g;
const matches = string.matchAll(regexp);
for (const match of matches) {
console.log(match);
console.log(match.index)
}
As it returns an iterator, we can say it's lazy, this is useful when handling particularly large numbers of capturing groups, or very large strings. But if you need, the result can be easily transformed into an Array by using the spread syntax or the Array.from method:
function getFirstGroup(regexp, str) {
const array = [...str.matchAll(regexp)];
return array.map(m => m[1]);
}
// or:
function getFirstGroup(regexp, str) {
return Array.from(str.matchAll(regexp), m => m[1]);
}
In the meantime, while this proposal gets more wide support, you can use the official shim package.
Also, the internal workings of the method are simple. An equivalent implementation using a generator function would be as follows:
function* matchAll(str, regexp) {
const flags = regexp.global ? regexp.flags : regexp.flags + "g";
const re = new RegExp(regexp, flags);
let match;
while (match = re.exec(str)) {
yield match;
}
}
A copy of the original regexp is created; this is to avoid side-effects due to the mutation of the lastIndex property when going through the multple matches.
Also, we need to ensure the regexp has the global flag to avoid an infinite loop.
I'm also happy to see that even this StackOverflow question was referenced in the discussions of the proposal.
original answer
You can access capturing groups like this:
var myString = "something format_abc";
var myRegexp = /(?:^|\s)format_(.*?)(?:\s|$)/g;
var myRegexp = new RegExp("(?:^|\s)format_(.*?)(?:\s|$)", "g");
var matches = myRegexp.exec(myString);
console.log(matches[1]); // abc
And if there are multiple matches you can iterate over them:
var myString = "something format_abc";
var myRegexp = new RegExp("(?:^|\s)format_(.*?)(?:\s|$)", "g");
match = myRegexp.exec(myString);
while (match != null) {
// matched text: match[0]
// match start: match.index
// capturing group n: match[n]
console.log(match[0])
match = myRegexp.exec(myString);
}
Here’s a method you can use to get the nth capturing group for each match:
function getMatches(string, regex, index) {
index || (index = 1); // default to the first capturing group
var matches = [];
var match;
while (match = regex.exec(string)) {
matches.push(match[index]);
}
return matches;
}
// Example :
var myString = 'something format_abc something format_def something format_ghi';
var myRegEx = /(?:^|\s)format_(.*?)(?:\s|$)/g;
// Get an array containing the first capturing group for every match
var matches = getMatches(myString, myRegEx, 1);
// Log results
document.write(matches.length + ' matches found: ' + JSON.stringify(matches))
console.log(matches);
var myString = "something format_abc";
var arr = myString.match(/\bformat_(.*?)\b/);
console.log(arr[0] + " " + arr[1]);
The \b isn't exactly the same thing. (It works on --format_foo/, but doesn't work on format_a_b) But I wanted to show an alternative to your expression, which is fine. Of course, the match call is the important thing.
Last but not least, I found one line of code that worked fine for me (JS ES6):
let reg = /#([\S]+)/igm; // Get hashtags.
let string = 'mi alegría es total! ✌🙌\n#fiestasdefindeaño #PadreHijo #buenosmomentos #france #paris';
let matches = (string.match(reg) || []).map(e => e.replace(reg, '$1'));
console.log(matches);
This will return:
['fiestasdefindeaño', 'PadreHijo', 'buenosmomentos', 'france', 'paris']
In regards to the multi-match parentheses examples above, I was looking for an answer here after not getting what I wanted from:
var matches = mystring.match(/(?:neededToMatchButNotWantedInResult)(matchWanted)/igm);
After looking at the slightly convoluted function calls with while and .push() above, it dawned on me that the problem can be solved very elegantly with mystring.replace() instead (the replacing is NOT the point, and isn't even done, the CLEAN, built-in recursive function call option for the second parameter is!):
var yourstring = 'something format_abc something format_def something format_ghi';
var matches = [];
yourstring.replace(/format_([^\s]+)/igm, function(m, p1){ matches.push(p1); } );
After this, I don't think I'm ever going to use .match() for hardly anything ever again.
String#matchAll (see the Stage 3 Draft / December 7, 2018 proposal), simplifies acccess to all groups in the match object (mind that Group 0 is the whole match, while further groups correspond to the capturing groups in the pattern):
With matchAll available, you can avoid the while loop and exec with /g... Instead, by using matchAll, you get back an iterator which you can use with the more convenient for...of, array spread, or Array.from() constructs
This method yields a similar output to Regex.Matches in C#, re.finditer in Python, preg_match_all in PHP.
See a JS demo (tested in Google Chrome 73.0.3683.67 (official build), beta (64-bit)):
var myString = "key1:value1, key2-value2!!#key3=value3";
var matches = myString.matchAll(/(\w+)[:=-](\w+)/g);
console.log([...matches]); // All match with capturing group values
The console.log([...matches]) shows
You may also get match value or specific group values using
let matchData = "key1:value1, key2-value2!!#key3=value3".matchAll(/(\w+)[:=-](\w+)/g)
var matches = [...matchData]; // Note matchAll result is not re-iterable
console.log(Array.from(matches, m => m[0])); // All match (Group 0) values
// => [ "key1:value1", "key2-value2", "key3=value3" ]
console.log(Array.from(matches, m => m[1])); // All match (Group 1) values
// => [ "key1", "key2", "key3" ]
NOTE: See the browser compatibility details.
Terminology used in this answer:
Match indicates the result of running your RegEx pattern against your string like so: someString.match(regexPattern).
Matched patterns indicate all matched portions of the input string, which all reside inside the match array. These are all instances of your pattern inside the input string.
Matched groups indicate all groups to catch, defined in the RegEx pattern. (The patterns inside parentheses, like so: /format_(.*?)/g, where (.*?) would be a matched group.) These reside within matched patterns.
Description
To get access to the matched groups, in each of the matched patterns, you need a function or something similar to iterate over the match. There are a number of ways you can do this, as many of the other answers show. Most other answers use a while loop to iterate over all matched patterns, but I think we all know the potential dangers with that approach. It is necessary to match against a new RegExp() instead of just the pattern itself, which only got mentioned in a comment. This is because the .exec() method behaves similar to a generator function – it stops every time there is a match, but keeps its .lastIndex to continue from there on the next .exec() call.
Code examples
Below is an example of a function searchString which returns an Array of all matched patterns, where each match is an Array with all the containing matched groups. Instead of using a while loop, I have provided examples using both the Array.prototype.map() function as well as a more performant way – using a plain for-loop.
Concise versions (less code, more syntactic sugar)
These are less performant since they basically implement a forEach-loop instead of the faster for-loop.
// Concise ES6/ES2015 syntax
const searchString =
(string, pattern) =>
string
.match(new RegExp(pattern.source, pattern.flags))
.map(match =>
new RegExp(pattern.source, pattern.flags)
.exec(match));
// Or if you will, with ES5 syntax
function searchString(string, pattern) {
return string
.match(new RegExp(pattern.source, pattern.flags))
.map(match =>
new RegExp(pattern.source, pattern.flags)
.exec(match));
}
let string = "something format_abc",
pattern = /(?:^|\s)format_(.*?)(?:\s|$)/;
let result = searchString(string, pattern);
// [[" format_abc", "abc"], null]
// The trailing `null` disappears if you add the `global` flag
Performant versions (more code, less syntactic sugar)
// Performant ES6/ES2015 syntax
const searchString = (string, pattern) => {
let result = [];
const matches = string.match(new RegExp(pattern.source, pattern.flags));
for (let i = 0; i < matches.length; i++) {
result.push(new RegExp(pattern.source, pattern.flags).exec(matches[i]));
}
return result;
};
// Same thing, but with ES5 syntax
function searchString(string, pattern) {
var result = [];
var matches = string.match(new RegExp(pattern.source, pattern.flags));
for (var i = 0; i < matches.length; i++) {
result.push(new RegExp(pattern.source, pattern.flags).exec(matches[i]));
}
return result;
}
let string = "something format_abc",
pattern = /(?:^|\s)format_(.*?)(?:\s|$)/;
let result = searchString(string, pattern);
// [[" format_abc", "abc"], null]
// The trailing `null` disappears if you add the `global` flag
I have yet to compare these alternatives to the ones previously mentioned in the other answers, but I doubt this approach is less performant and less fail-safe than the others.
Your syntax probably isn't the best to keep. FF/Gecko defines RegExp as an extension of Function.
(FF2 went as far as typeof(/pattern/) == 'function')
It seems this is specific to FF -- IE, Opera, and Chrome all throw exceptions for it.
Instead, use either method previously mentioned by others: RegExp#exec or String#match.
They offer the same results:
var regex = /(?:^|\s)format_(.*?)(?:\s|$)/;
var input = "something format_abc";
regex(input); //=> [" format_abc", "abc"]
regex.exec(input); //=> [" format_abc", "abc"]
input.match(regex); //=> [" format_abc", "abc"]
There is no need to invoke the exec method! You can use "match" method directly on the string. Just don't forget the parentheses.
var str = "This is cool";
var matches = str.match(/(This is)( cool)$/);
console.log( JSON.stringify(matches) ); // will print ["This is cool","This is"," cool"] or something like that...
Position 0 has a string with all the results. Position 1 has the first match represented by parentheses, and position 2 has the second match isolated in your parentheses. Nested parentheses are tricky, so beware!
With es2018 you can now String.match() with named groups, makes your regex more explicit of what it was trying to do.
const url =
'https://stackoverflow.com/questions/432493/how-do-you-access-the-matched-groups-in-a-javascript-regular-expression?some=parameter';
const regex = /(?<protocol>https?):\/\/(?<hostname>[\w-\.]*)\/(?<pathname>[\w-\./]+)\??(?<querystring>.*?)?$/;
const { groups: segments } = url.match(regex);
console.log(segments);
and you'll get something like
{protocol: "https", hostname: "stackoverflow.com", pathname: "questions/432493/how-do-you-access-the-matched-groups-in-a-javascript-regular-expression", querystring: "some=parameter"}
A one liner that is practical only if you have a single pair of parenthesis:
while ( ( match = myRegex.exec( myStr ) ) && matches.push( match[1] ) ) {};
Using your code:
console.log(arr[1]); // prints: abc
console.log(arr[0]); // prints: format_abc
Edit: Safari 3, if it matters.
function getMatches(string, regex, index) {
index || (index = 1); // default to the first capturing group
var matches = [];
var match;
while (match = regex.exec(string)) {
matches.push(match[index]);
}
return matches;
}
// Example :
var myString = 'Rs.200 is Debited to A/c ...2031 on 02-12-14 20:05:49 (Clear Bal Rs.66248.77) AT ATM. TollFree 1800223344 18001024455 (6am-10pm)';
var myRegEx = /clear bal.+?(\d+\.?\d{2})/gi;
// Get an array containing the first capturing group for every match
var matches = getMatches(myString, myRegEx, 1);
// Log results
document.write(matches.length + ' matches found: ' + JSON.stringify(matches))
console.log(matches);
function getMatches(string, regex, index) {
index || (index = 1); // default to the first capturing group
var matches = [];
var match;
while (match = regex.exec(string)) {
matches.push(match[index]);
}
return matches;
}
// Example :
var myString = 'something format_abc something format_def something format_ghi';
var myRegEx = /(?:^|\s)format_(.*?)(?:\s|$)/g;
// Get an array containing the first capturing group for every match
var matches = getMatches(myString, myRegEx, 1);
// Log results
document.write(matches.length + ' matches found: ' + JSON.stringify(matches))
console.log(matches);
Your code works for me (FF3 on Mac) even if I agree with PhiLo that the regex should probably be:
/\bformat_(.*?)\b/
(But, of course, I'm not sure because I don't know the context of the regex.)
As #cms said in ECMAScript (ECMA-262) you can use matchAll. It return an iterator and by putting it in [... ] (spread operator) it converts to an array.(this regex extract urls of file names)
let text = `File1 File2`;
let fileUrls = [...text.matchAll(/href="(http\:\/\/[^"]+\.\w{3})\"/g)].map(r => r[1]);
console.log(fileUrls);
/*Regex function for extracting object from "window.location.search" string.
*/
var search = "?a=3&b=4&c=7"; // Example search string
var getSearchObj = function (searchString) {
var match, key, value, obj = {};
var pattern = /(\w+)=(\w+)/g;
var search = searchString.substr(1); // Remove '?'
while (match = pattern.exec(search)) {
obj[match[0].split('=')[0]] = match[0].split('=')[1];
}
return obj;
};
console.log(getSearchObj(search));
You don't really need an explicit loop to parse multiple matches — pass a replacement function as the second argument as described in: String.prototype.replace(regex, func):
var str = "Our chief weapon is {1}, {0} and {2}!";
var params= ['surprise', 'fear', 'ruthless efficiency'];
var patt = /{([^}]+)}/g;
str=str.replace(patt, function(m0, m1, position){return params[parseInt(m1)];});
document.write(str);
The m0 argument represents the full matched substring {0}, {1}, etc. m1 represents the first matching group, i.e. the part enclosed in brackets in the regex which is 0 for the first match. And position is the starting index within the string where the matching group was found — unused in this case.
We can access the matched group in a regular expressions by using backslash followed by number of the matching group:
/([a-z])\1/
In the code \1 represented matched by first group ([a-z])
I you are like me and wish regex would return an Object like this:
{
match: '...',
matchAtIndex: 0,
capturedGroups: [ '...', '...' ]
}
then snip the function from below
/**
* #param {string | number} input
* The input string to match
* #param {regex | string} expression
* Regular expression
* #param {string} flags
* Optional Flags
*
* #returns {array}
* [{
match: '...',
matchAtIndex: 0,
capturedGroups: [ '...', '...' ]
}]
*/
function regexMatch(input, expression, flags = "g") {
let regex = expression instanceof RegExp ? expression : new RegExp(expression, flags)
let matches = input.matchAll(regex)
matches = [...matches]
return matches.map(item => {
return {
match: item[0],
matchAtIndex: item.index,
capturedGroups: item.length > 1 ? item.slice(1) : undefined
}
})
}
let input = "key1:value1, key2:value2 "
let regex = /(\w+):(\w+)/g
let matches = regexMatch(input, regex)
console.log(matches)
One line solution:
const matches = (text,regex) => [...text.matchAll(regex)].map(([match])=>match)
So you can use this way (must use /g):
matches("something format_abc", /(?:^|\s)format_(.*?)(?:\s|$)/g)
result:
[" format_abc"]
JUST USE RegExp.$1...$n th group
eg:
1.To match 1st group RegExp.$1
To match 2nd group RegExp.$2
if you use 3 group in regex likey(note use after string.match(regex))
RegExp.$1 RegExp.$2 RegExp.$3
var str = "The rain in ${india} stays safe";
var res = str.match(/\${(.*?)\}/ig);
//i used only one group in above example so RegExp.$1
console.log(RegExp.$1)
//easiest way is use RegExp.$1 1st group in regex and 2nd grounp like
//RegExp.$2 if exist use after match
var regex=/\${(.*?)\}/ig;
var str = "The rain in ${SPAIN} stays ${mainly} in the plain";
var res = str.match(regex);
for (const match of res) {
var res = match.match(regex);
console.log(match);
console.log(RegExp.$1)
}
Get all group occurrence
let m=[], s = "something format_abc format_def format_ghi";
s.replace(/(?:^|\s)format_(.*?)(?:\s|$)/g, (x,y)=> m.push(y));
console.log(m);
I thought you just want to grab all the words containing the abc substring and store the matched group/entries, so I made this script:
s = 'something format_abc another word abc abc_somestring'
console.log(s.match(/\b\w*abc\w*\b/igm));
\b - a word boundary
\w* - 0+ word chars
abc - your exact match
\w* - 0+ word chars
\b - a word boundary
References: Regex: Match all the words that contains some word
https://javascript.info/regexp-introduction
I don't know regular expression at all. Can anybody help me with one very simple regular expression which is,
extracting 'word:word' from a sentence. e.g "Java Tutorial Format:Pdf With Location:Tokyo Javascript"?
Little modification:
the first 'word' is from a list but second is anything. "word1 in [ABC, FGR, HTY]"
guys situation demands a little more
modification.
The matching form can be "word11:word12 word13 .. " till the next "word21: ... " .
things are becoming complex with sec.....i have to learn reg ex :(
thanks in advance.
You can use the regex:
\w+:\w+
Explanation:
\w - single char which is either a letter(uppercase or lowercase), digit or a _.
\w+ - one or more of above char..basically a word
so \w+:\w+
would match a pair of words separated by a colon.
Try \b(\S+?):(\S+?)\b. Group 1 will capture "Format" and group 2, "Pdf".
A working example:
<html>
<head>
<script type="text/javascript">
function test() {
var re = /\b(\S+?):(\S+?)\b/g; // without 'g' matches only the first
var text = "Java Tutorial Format:Pdf With Location:Tokyo Javascript";
var match = null;
while ( (match = re.exec(text)) != null) {
alert(match[1] + " -- " + match[2]);
}
}
</script>
</head>
<body onload="test();">
</body>
</html>
A good reference for regexes is https://developer.mozilla.org/en/Core_JavaScript_1.5_Reference/Global_Objects/RegExp
Use this snippet :
$str=" this is pavun:kumar hello world bk:systesm" ;
if ( preg_match_all ( '/(\w+\:\w+)/',$str ,$val ) )
{
print_r ( $val ) ;
}
else
{
print "Not matched \n";
}
Continuing Jaú's function with your additional requirement:
function test() {
var words = ['Format', 'Location', 'Size'],
text = "Java Tutorial Format:Pdf With Location:Tokyo Language:Javascript",
match = null;
var re = new RegExp( '(' + words.join('|') + '):(\\w+)', 'g');
while ( (match = re.exec(text)) != null) {
alert(match[1] + " = " + match[2]);
}
}
I am currently solving that problem in my nodejs app and found that this is, what I guess, suitable for colon-paired wordings:
([\w]+:)("(([^"])*)"|'(([^'])*)'|(([^\s])*))
It also matches quoted value. like a:"b" c:'d e' f:g
Example coding in es6:
const regex = /([\w]+:)("(([^"])*)"|'(([^'])*)'|(([^\s])*))/g;
const str = `category:"live casino" gsp:S1aik-UBnl aa:"b" c:'d e' f:g`;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Example coding in PHP
$re = '/([\w]+:)("(([^"])*)"|\'(([^\'])*)\'|(([^\s])*))/';
$str = 'category:"live casino" gsp:S1aik-UBnl aa:"b" c:\'d e\' f:g';
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
// Print the entire match result
var_dump($matches);
You can check/test your regex expressions using this online tool: https://regex101.com
Btw, if not deleted by regex101.com, you can browse that example coding here
here's the non regex way, in your favourite language, split on white spaces, go through the element, check for ":" , print them if found. Eg Python
>>> s="Java Tutorial Format:Pdf With Location:Tokyo Javascript"
>>> for i in s.split():
... if ":" in i:
... print i
...
Format:Pdf
Location:Tokyo
You can do further checks to make sure its really "someword:someword" by splitting again on ":" and checking if there are 2 elements in the splitted list. eg
>>> for i in s.split():
... if ":" in i:
... a=i.split(":")
... if len(a) == 2:
... print i
...
Format:Pdf
Location:Tokyo
([^:]+):(.+)
Meaning: (everything except : one or more times), :, (any character one ore more time)
You'll find good manuals on the net... Maybe it's time for you to learn...