Char to char* C++ - c++

Question

I'm having an error with my constructor in my classes.
In my .cpp file I've got:
Player::Player()
{
m_name="Jane";
m_amt=100;
}
and in my .h file I've got:
// Default constructor, does nothing.
Player();
// Creates a Player. Player name and amount.
Player(const char &name, int amt);
I'm getting the error:
error: invalid conversion from ‘const char*’ to ‘char’ [-fpermissive]
m_name="Jane";
So I tried converting it to a *char but that still doesn't work. Can someone help please?

Answer 1

You can either take a pointer:
Player(const char* name, int amt) { ... }
and you could use std::string to store the name and use char* just to construct this string:
private:
std::string m_name;
public:
Player(const char* name, int amt) : m_name(name) { }
or just use std::string everywhere and pass by reference to avoid redundant copies being created:
private:
std::string m_name;
public:
Player(const std::string& name, int amt) : m_name(name) { }
Note that the last version is quite flexible and it's possible to also pass const char* to it, example:
#include <iostream>
#include <string>
class Player {
private:
std::string m_name;
public:
Player(const std::string& name) : m_name(name){}
void printName() { std::cout << m_name; }
};
int main() {
Player p("Liho");
p.printName();
}

Answer 2

Show your full class/code. Following compiles fine for me.
cpp file...
#include"player.h"
Player::Player()
{
m_name="Jane";
m_amt=100;
}
.h file...
class Player {
public:
// Default constructor, does nothing.
Player();
// Creates a Player. Player name and amount.
Player(const char *name, int amt);
private:
char* m_name;
int m_amt;
};