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I have a string which represents a file name, and I want to remove the extension, so erasing everything after the ".". What would be the best way ? Thanks.
Below code can be used for the same..
int npos = str.find_last_of('.');
str = str.substring(0,npos);
If you're on Windows, the following function will do the trick:
std::wstring StripFileExtension(std::wstring fileName)
{
WCHAR tempBuffer[MAX_PATH];
if (fileName.empty())
{
return TEXT("");
}
wcscpy(tempBuffer, fileName.c_str());
PathRemoveExtension(tempBuffer);
return tempBuffer;
}
you can use std::string , and copy each character to new string
std::string name = "filename.jpg", newname ="";
int thelength = 0;
for(int i=name.length();i>0;i--){
if( name[i] != '.'){
thelength++;
}
else{
break;
}
}
for(int i=0;i<(name.length()-thelength);i++){
newname+=name[i];
}
Related
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I've asked to write code that gets a char array(sentence), if the there is an 'i' in the sentence I need to add the letter 'b' the letter 'i' again like this example:
pig -> pibig
I tried to use string.h functions but I didn't succeed to make it right.
Use std::string in string header file, and std::string::insert whenever you need to insert a char in string:
std::string my_string = "my satringa";
for (size_t i = 0; i < my_string.length(); ++i)
{
if (my_string.at(i) == 'a')
{
my_string.insert(i + 1, "b");
}
}
std::clog << my_string << std::endl;
Output:
> my sabtringab
If you are forced to use C-style strings, don't worry do all of your operations on std::string and then take the underlying stored string with std::string::c_str() as a C-style string (and don't forget to take a copy).
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This is part of a c++ code that writes value of a vector of strings into a file.
int main () {
//freopen ("out.txt", "w+", stdout);
ofstream data;
data.open("data.txt");
BinaryTree<string>* bt = new BinaryTree<string>;
LoadBinaryTree(bt);
fillArrayOfNodes(bt);
for (int i = 0; drawArray[i] != "\0"; i++)
data << drawArray[i] << endl;
data.close();
delete bt;
return 0;
}
First, I couldn't write into the file. I mean after running the program and checking the output file, it was empty. after that, I noticed that my output format wasn't right. I changed it and now I can write into the file. (the code shown above is the modified code)
The problem is the way you're attempting to iterate through the array. The Standard C++ string class std::string should not be handled like a regular char array. That is, you shouldn't base your condition upon finding the null character. The correct way would be to iterate until you reach the length of the string.
Moreover, you should be using a vector of strings and inserting strings using push_back():
std::vector<std::string> v;
// fill vector with push_back()
for (int i = 0; i < v.size(); ++i)
data << v[i] << endl;
You need to include the right headers like <fstream>.
Try this example: http://www.cplusplus.com/doc/tutorial/files/
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I need to parse the following, which is stored in a variable, and extract only Names. These names should be placed in a new variable (all together separated by dot (.)). Any ideas?
Name : Mike Anderson\n
Age : 43\n
Name : Andie Jameson\n
Age : 35\n
The expected output should be a variable with content: Mike Anderson.Andie Jameson
Thank you.
There will be many useful methods for your situation.
This code is just one of them. I used std::istringstream, string::find().
int main()
{
//Originally, each data is from your source.
//but, this is just sample.
std::istringstream input;
input.str("Name : Mike Anderson\nAge : 43\nName : Andie Jameson\nAge : 35\n");
//to find pattern
std::string name_pattern = "Name : ";
std::size_t found = std::string::npos;
for (std::string line; std::getline(input, line); ) {
found = line.find(name_pattern);
if (found!=std::string::npos)
{
//write on file for 'directory'
std::string only_name(line, found + name_pattern.length() );
std::cout << "\nName : " << only_name;
continue;
}
}
getchar();
}
This code will print below like,
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I have a string like below:
std::string myString = "This is string\r\nIKO\r\n. I don't exp\r\nO091\r\nect some characters.";
Now I want to get rid of the characters between \r\n including \r\n.
So the string must look like below:
std::string myString = "This is string. I don't expect some characters.";
I am not sure, how many \r\n's going to appear.
And I have no idea what characters are coming between \r\n.
How could I use regex in this string?
Personally, I'd do a simple loop with find. I don't see how using regular expressions helps much with this task. Something along these lines:
string final;
size_t cur = 0;
for (;;) {
size_t pos = myString.find("\r\n", cur);
final.append(myString, cur, pos - cur);
if (pos == string::npos) {
break;
}
pos = myString.find("\r\n", pos + 2);
if (pos == string::npos) {
// Odd number of delimiters; handle as needed.
break;
}
cur = pos + 2;
}
Regular expressions are "greedy" by default in most regex libaries.
Just make your regex say "\r\n.*\r\n" and you should be fine.
EDIT
Then split your input using the given regex. That should yield two strings you can combine into the desired result.
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How can I parse a string given by a user and swap all occurrences of the old substring with the new string. I have a function to work with but I am really uncertain when it comes to strings.
void spliceSwap( char* inputStr, const char* oldStr, const char* newStr )
The simplest solution is to use google (First link) here. Also be aware that in C++ we prefer std::string over const char *. Do not write your own std::string, use the built-in one. Your code seems to be more C than C++!
// Zammbi's variable names will help answer your question
// params find and replace cannot be NULL
void FindAndReplace( std::string& source, const char* find, const char* replace )
{
// ASSERT(find != NULL);
// ASSERT(replace != NULL);
size_t findLen = strlen(find);
size_t replaceLen = strlen(replace);
size_t pos = 0;
// search for the next occurrence of find within source
while ((pos = source.find(find, pos)) != std::string::npos)
{
// replace the found string with the replacement
source.replace( pos, findLen, replace );
// the next line keeps you from searching your replace string,
// so your could replace "hello" with "hello world"
// and not have it blow chunks.
pos += replaceLen;
}
}