I have a notepad file in my PC with path D:/example.txt,how can i display this file using my python code.
If you mean open the file with notepad:
Using os.startfile (only available in Windows):
import os
os.startfile(r'd:\example.txt')
Using subprocess.Popen or subprocess.call:
import subprocess
subprocess(['notepad', r'd:\example.txt'])
To print to console
import sys
with open(r'D:\example.txt') as f:
sys.stdout.writelines(f)
with open(r'D:\example.txt') as f:
for line in f:
print line.rstrip('\n')
Related
So I've made a script that would delete files with a specific file extension, but how would I go about adding secure deletion of the file?
import sys
import os
from os import listdir
dir_name = "storage/emulated/0/Download/"
test = os.listdir(dir_name)
for file in test:
if file.endswith(".zip"):
os.remove(os.path.join(dir_name, file))
I am very new to Python and am trying to append some functionality to an existing Python program. I want to read values from a config INI file like this:
[Admin]
AD1 = 1
AD2 = 2
RSW = 3
When I execute the following code from IDLE, it works as ist should (I already was able to read in values from the file, but deleted this part for a shorter code snippet):
#!/usr/bin/python
import ConfigParser
# buildin python libs
from time import sleep
import sys
def main():
print("Test")
sleep(2)
if __name__ == '__main__':
main()
But the compiled exe quits before printing and waiting 2 seconds. If I comment out the import of ConfigParser, exe runs fine.
This is how I compile into exe:
from distutils.core import setup
import py2exe, sys
sys.argv.append('py2exe')
setup(
options = {'py2exe': {'bundle_files': 1}},
zipfile = None,
console=['Test.py'],
)
What am I doing wrong? Is there maybe another way to read in a configuration in an easy way, if ConfigParser for some reason doesnt work in a compiled exe?
Thanks in advance for your help!
I am testing below python code to export content from one txt file to another but in destination contents are getting copied with some different language (may be chinese) with improper
# - *- coding: utf- 8 - *-
from sys import argv
from os.path import exists
script,from_file,to_file = argv
print "Does the output file exist ? %r" %exists(to_file)
print "If 'YES' hit Enter to proceed or terminate by CTRL+C "
raw_input('?')
infile=open(from_file)
file1=infile.read()
outfile=open(to_file,'w')
file2=outfile.write(file1)
infile.close()
outfile.close()
try this code to copy 1 file to another :
with open("from_file") as f:
with open("to_file", "w") as f1:
for line in f:
f1.write(line)
I just have a python file:
#!/usr/bin/python
import os
print os.path.dirname(__file__)
but when I execute it, the terminal displays a dot, instead of the absolute path to the script.
Perhaps,
#!/usr/bin/python
import os
print os.path.realpath(__file__)
gives you what you're looking for?
I have been experimenting with python by creating some programs .The thing is, I have no idea how to import something OUT of the default python directory.
OK
So I did some heavy research and the conclusion is
if u want to access a file saved at different location
use
f = open('E:/somedir/somefile.txt', 'r')
r = f.read()
NOTE: Dont use '\' that were I went wrong.Our system addresses uses '\' So be careful
If you need to just read in a file and not import a module the documentation covers this extensively.
https://docs.python.org/2/tutorial/inputoutput.html#reading-and-writing-files
Specifically for Windows file systems you will need to do one of the following:
1.) Use forwardslashes vs backslashes. This should work with most OSes.
f = open("c:/somedir/somefile.txt", "r")
2.) Use a raw string.
f = open(r"c:\somedir\somefile.txt", "r")
3.) Escape the backslashes.
f = open("c:\\somedir\\somefile.txt", "r")
If you need to import a module to use in your program from outside your programs directory you can use the below information.
Python looks in the sys.path to see if the module exists there and if so does the import. If the path where you files/modules are located is not in the sys.path, Python will raise an ImportError. You can update the path programmatically by using the sys module.
import sys
dir = "path to mymodule"
if dir not in sys.path:
sys.path.append(dir)
import mymodule
You can check the current sys.path by using:
print(sys.path)
Example:
>>> print(sys.path)
['', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python34.zip', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/plat-darwin', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/lib-dynload', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages']
>>> sys.path.append("/Users/ddrummond/pymodules")
>>> print(sys.path)
['', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python34.zip', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/plat-darwin', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/lib-dynload', '/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages', '/Users/ddrummond/pymodules']
>>>
You can see that sys.path now contains '/Users/ddrummond/pymodules'.