Convert from pointer to an object c++ - c++

Question

I have got a problem with understanding the following code where I am trying to convert from the pointer to an object class Passenger* passenger to class Passenger passenger. I am not sure how I can modify my code to do perform the same functionality without the pointers. I am particularly confused with setting and comparing to NULL. Do I need to keep those if statements if I am no longer using the pointers? Any advises or suggestions would be appreciated.
class Seat
{
private:
class Passenger* passenger;
public:
Seat()
{
passenger = NULL;
}
~Seat()
{
if (passenger)
{
delete passenger;
passenger = NULL;
}
}
bool insertSeat(class Passenger* p)
{
bool bsuccess = TRUE;
if ( p != NULL )
{
if (passenger == NULL)
passenger = p;
else
bsuccess = FALSE;
}
else
passenger = NULL;
return bsuccess;
}
bool outputSeat(int row,int seat)
{
if (passenger)
cout << (passenger->toString()) << endl;
else
cout << "Empty " << row << seat+'A' << endl;
return passenger != NULL;
}
};

Answer 1

The simplest way is :
class Seat
{
private:
Passenger passenger;
public:
Seat()
{ }
void insertSeat( const Passenger& p ) // pass by const reference
{
passenger = p;
}
bool outputSeat( int row, int seat )
{
cout << passenger.toString() << endl;
}
};
You can always implement checking; eg : you don't want an invalid or default constructed passenger when passing it to
insertSeat() function :
bool insertSeat( const Passenger& p ) // pass by const reference
{
if( /* p.empty() or p.invalid() or whatever*/ ) return false; // implement empty() method
passenger = p;
return true
}