C++ Passing pointer to non-static member function - c++

Question

Hi everyone :) I have a problem with function pointers
My 'callback' function arguments are:
1) a function like this: int(*fx)(int,int)
2) an int variable: int a
3) another int: int b
Well, the problem is that the function I want to pass to 'callback' is a non-static function member :( and there are lots of problems
If someone smarter than me have some time to spent, he can look my code :)
#include <iostream>
using namespace std;
class A{
private:
int x;
public:
A(int elem){
x = elem;
}
static int add(int a, int b){
return a + b;
}
int sub(int a, int b){
return x - (a + b);
}
};
void callback( int(*fx)(int, int), int a, int b)
{
cout << "Value of the callback: " << fx(a, b) << endl;
}
int main()
{
A obj(5);
//PASSING A POINTER TO A STATIC MEMBER FUNCTION -- WORKS!!
// output = 'Value of the callback: 30'
callback(A::add, 10, 20);
//USING A POINTER TO A NON-STATIC MEMBER FUNCTION -- WORKS!!
int(A::*function1)(int, int) = &A::sub;
// output = 'Non static member: 3'
cout << "Non static member: " << (obj.*function1)(1, 1) << endl;
//PASSING A POINTER TO A NON-STATIC MEMBER FUNCTION -- aargh
// fallita! tutto quello sotto non funziona --> usa i funtori???
// puoi creare una classe wrapper ma non riuscirai mai a chiamare da callback
int(A::*function2)(int, int) = &A::sub;
int(*function3)(int, int) = obj.*function2; //[error] invalid use of non-static member function
callback(function3, 1, 1);
}
There's a way to create my pointer in the way I tried to wrote, like int(*fx)(int, int) = something? I searched a lot but no-one could gave me an answer (well, there was an answer: "NO", but I still think I can do something)
I heard also about functors, may them help me in this case?
Thanks to anyone
PS: sorry for my bad english
EDIT1:
I can use something like this:
template <class T>
void callback2( T* obj, int(T::*fx)(int, int), int a, int b)
{
cout << "Value of the callback: " << (obj->*fx)(a, b) << endl;
}
void callback2( void* nullpointer, int(*fx)(int, int), int a, int b)
{
cout << "Value of the callback: " << fx(a, b) << endl;
}
and in my main:
callback2(NULL, &mul, 5, 3); // generic function, it's like: int mul(int a, int b){return a*b;}
callback2(NULL, &A::add, 5, 3); //static member function
callback2(&obj, &A::sub, 1, 1); //non static member function
I'm not completely sadisfied, because I don't want to pass my 'callback2' the first parameter (the object)...
The question, for people that didn't understand my (bad) explanation, is: can I delete the first parameter in my callback2 function?
the prototype will be
void callback2(int(*fx)(int, int), int a, int b)<br>
and I will call like this:
callback2(&obj.sub, 1, 3);

Answer 1

Functions cannot be referenced this way:
int (*function3)(int, int) = obj.*function2;
You have to pass the address of the function like this:
int (*function3)(int, int) = std::mem_fn(&A::sub, obj);
// ^^^^^^^^^^^^^^^^^^^^^^^^^
The expression function2 decays into a pointer-to-function which allows it to work.

Answer 2

I would do it with std functors, here is a simple example based off of your code:
#include <iostream>
#include <functional>
using namespace std;
class A{
private:
int x;
public:
A(int elem){
x = elem;
}
static int add(int a, int b){
return a + b;
}
int sub(int a, int b) const{
return x - (a + b);
}
};
void callback( std::function<int(const A& ,int,int )> fx, A obj, int a, int b)
{
cout << "Value of the callback: " << fx( obj, a, b) << endl;
}
int main()
{
A obj(5);
std::function<int(const A& ,int,int )> Aprinter= &A::sub;
callback(Aprinter,obj,1,2);
}