I have a domain-class called option. There is an attribute called name.
The names are like:
abc.1
abc.2
xxx.1
xxx.2
xxx.3
I want all options that start with abc.
Normally I use Options.findByName("xyz")
But i want all that start with abc. So in that example:
abc.1
abc.2
The regex could be /abc(.).*/
But where I have to write that?
If you need only simple "startsWith" condition, you can use like:
Options.findAllByNameLike("abc%")
Consider using colusers inside the findAll /findByName method
Have u tried this one ?
Example
def result = ["abc1", "acb2", "abc3"].findAll { it ==~ /abc.*/ }
or in your case
def result = Options.findByName { it ==~ /abc.*/ }
Or refer this link for bunch of reference on regular expression http://groovy.codehaus.org/Regular+Expressions
Cheers!
Related
I've got a Node module file containing about 100 exported methods, which looks something like this:
exports.methodOne = async user_id => {
// other method contents
};
exports.methodTwo = async user_id => {
// other method contents
fooMethod();
};
exports.methodThree = async user_id => {
// other method contents
fooMethod();
};
Goal: What I'd like to do is figure out how to grab the name of any method which contains a call to fooMethod, and return the correct method names: methodTwo and methodThree. I wrote a regex which gets kinda close:
exports\.(\w+).*(\n.*?){1,}fooMethod
Problem: using my example code from above, though, it would effectively match methodOne and methodThree because it finds the first instance of export and then the first instance of fooMethod and goes on from there. Here's a regex101 example.
I suspect I could make use of lookaheads or lookbehinds, but I have little experience with those parts of regex, so any guidance would be much appreciated!
Edit: Turns out regex is poorly-suited for this type of task. #ctcherry advised using a parser, and using that as a springboard, I was able to learn about Abstract Syntax Trees (ASTs) and the recast tool which lets you traverse the tree after using various tools (acorn and others) to parse your code into tree form.
With these tools in hand, I successfully built a script to parse and traverse my node app's files, and was able to find all methods containing fooMethod as intended.
Regex isn't the best tool to tackle all the parts of this problem, ideally we could rely on something higher level, a parser.
One way to do this is to let the javascript parse itself during load and execution. If your node module doesn't include anything that would execute on its own (or at least anything that would conflict with the below), you can put this at the bottom of your module, and then run the module with node mod.js.
console.log(Object.keys(exports).filter(fn => exports[fn].toString().includes("fooMethod(")));
(In the comments below it is revealed that the above isn't possible.)
Another option would be to use a library like https://github.com/acornjs/acorn (there are other options) to write some other javascript that parses your original target javascript, then you would have a tree structure you could use to perform your matching and eventually return the function names you are after. I'm not an expert in that library so unfortunately I don't have sample code for you.
This regex matches (only) the method names that contain a call to fooMethod();
(?<=exports\.)\w+(?=[^{]+\{[^}]+fooMethod\(\)[^}]+};)
See live demo.
Assuming that all methods have their body enclosed within { and }, I would make an approach to get to the final regex like this:
First, find a regex to get the individual methods. This can be done using this regex:
exports\.(\w+)(\s|.)*?\{(\s|.)*?\}
Next, we are interested in those methods that have fooMethod in them before they close. So, look for } or fooMethod.*}, in that order. So, let us name the group searching for fooMethod as FOO and the name of the method calling it as METH. When we iterate the matches, if group FOO is present in a match, we will use the corresponding METH group, else we will reject it.
exports\.(?<METH>\w+)(\s|.)*?\{(\s|.)*?(\}|(?<FOO>fooMethod)(\s|.)*?\})
Explanation:
exports\.(?<METH>\w+): Till the method name (you have already covered this)
(\s|.)*?\{(\s|.)*?: Some code before { and after, non-greedy so that the subsequent group is given preference
(\}|(?<FOO>fooMethod)(\s|.)*?\}): This has 2 parts:
\}: Match the method close delimiter, OR
(?<FOO>fooMethod)(\s|.)*?\}): The call to fooMethod followed by optional code and method close delimiter.
Here's a JavaScript code that demostrates this:
let p = /exports\.(?<METH>\w+)(\s|.)*?\{(\s|.)*?(\}|(?<FOO>fooMethod)(\s|.)*?\})/g
let input = `exports.methodOne = async user_id => {
// other method contents
};
exports.methodTwo = async user_id => {
// other method contents
fooMethod();
};
exports.methodThree = async user_id => {
// other method contents
fooMethod();
};';`
let match = p.exec( input );
while( match !== null) {
if( match.groups.FOO !== undefined ) console.log( match.groups.METH );
match = p.exec( input )
}
I would like to have a pipe which is detecting any url in a string and creating a link with it. At the moment I created this, which seems not working:
#Pipe({name:'matchUrl'})
export class MatchUrlPipe implements PipeTransform {
transform(value: string, arg?: any): any {
var exp = /https?:\/\/(www\.)?[-a-zA-Z0-9#:%._\+~#=]{2,256}\.[a-z]{2,4}\b([-a-zA-Z0-9#:%_\+.~#?&//=]*)/g;
return value.replace(exp, "<a href='$1'>$1</a>");
}
}
How can I fix it?
Seems like there are two problems with your implementation:
Your regex has the first capturing group ( $1 ) matching the 'www' part of the url. You want to change the regex like this for it to work (note the extra pair of parethesis at the start and end of the regex):
var exp = /(https?:\/\/(www\.)?[-a-zA-Z0-9#:%._\+~#=]{2,256}\.[a-z]{2,4}\b([-a-zA-Z0-9#:%_\+.~#?&//=]*))/g;
Pipes can't render html normally. You need a trick to do that as mentioned in other questione like this. You need to assign your 'piped value' to the attribute outerHTML of a span for example (the span will not be rendered).
Plunker example
I'm trying to do a 'like' query in mongodb. I see that's done with a regexp so I'm trying to set it like this:
$scope.clients = Client.query({
q:angular.toJson({
name: RegExp($routeParams.str)
})
});
The thing is angular.toJson function does not get any regexp:
http://plnkr.co/edit/idXMT1
Is there any other way to do that?
From my understanding of your question, you want your JSON object to contain the regular expression as a string?
In that case, you can manually convert it to a string in the declaration, i.e:
$scope.object = angular.toJson({
"param" : new RegExp(str).toString()
});
See updated plunk:
http://plnkr.co/edit/yLogI8
I finally found a solution.
The problem is using the toJon function as it does not allow any key starting with / or $ so the solution is avoiding the use of this function and just write the object as a string
$scope.clients = Client.query({
q:'{src:{$regex:"' + $routeParams.str + '"}}'
};
I am using GWT textBox and i want it to allow only alpha numeric characters.Is there any example somewhere where i can use the RegExp which is provided in GWT 2.1?
I would like to apply a regex for example ^[a-zA-Z0-9_]*$ .Please provide example code for making this working.Also i cannot use a third party library like the GWT-VL or something like that.
I am using GWT 2.1.
Thanks
You can simply use the matches method of the class String.
Here an example of an email validation:
if(!email.matches("^([a-zA-Z0-9_.\\-+])+#(([a-zA-Z0-9\\-])+\\.)+[a-zA-Z0-9]{2,4}$")) {
setErrorText("wrong mail");
}
Note that email is a String object.
HI you can use GWT-Validator framnework to do this GWT-Validator
Or you can use javascript method through JSNI and the method is mentioned below.
function validate(var string){
var alphanum=/^[0-9a-bA-B]+$/; //This contains A to Z , 0 to 9 and A to B
if(string.match(alphanum)){
return true;
}else{
alert(Put a Valid Userid Name);
return false;
}
}
I have a HTML with the following content:
... some text ...
link ... some text ...
... some text ...
link ... some text ...
... some text ...
I would like to parse that and get a match with named groups:
match 1
group["user"]=123
group["section"]=2
match 2
group["user"]=678
group["section"]=5
I can do it if parameters always go in order, first User and then Section, but I don't know how to do it if the order is different.
Thank you!
In my case I had to parse an Url because the utility HttpUtility.ParseQueryString is not available in WP7. So, I created a extension method like this:
public static class UriExtensions
{
private static readonly Regex queryStringRegex;
static UriExtensions()
{
queryStringRegex = new Regex(#"[\?&](?<name>[^&=]+)=(?<value>[^&=]+)");
}
public static IEnumerable<KeyValuePair<string, string>> ParseQueryString(this Uri uri)
{
if (uri == null)
throw new ArgumentException("uri");
var matches = queryStringRegex.Matches(uri.OriginalString);
for (int i = 0; i < matches.Count; i++)
{
var match = matches[i];
yield return new KeyValuePair<string, string>(match.Groups["name"].Value, match.Groups["value"].Value);
}
}
}
Then It's matter of using it, for example
var uri = new Uri(HttpUtility.UrlDecode(#"file.aspx?userId=123§ion=2"),UriKind.RelativeOrAbsolute);
var parameters = uri.ParseQueryString().ToDictionary( kvp => kvp.Key, kvp => kvp.Value);
var userId = parameters["userId"];
var section = parameters["section"];
NOTE: I'm returning the IEnumerable instead of the dictionary directly just because I'm assuming that there might be duplicated parameter's name. If there are duplicated names, then the dictionary will throw an exception.
Why use regex to split it out?
You could first extrct the query string. Split the result on & and then create a map by splitting the result from that on =
You didn't specify what language you are working in, but this should do the trick in C#:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Text.RegularExpressions;
namespace RegexTest
{
class Program
{
static void Main(string[] args)
{
string subjectString = #"... some text ...
link ... some text ...
... some text ...
link ... some text ...
... some text ...";
Regex regexObj =
new Regex(#"<a href=""file.aspx\?(?:(?:userId=(?<user>.+?)§ion=(?<section>.+?)"")|(?:section=(?<section>.+?)&user=(?<user>.+?)""))");
Match matchResults = regexObj.Match(subjectString);
while (matchResults.Success)
{
string user = matchResults.Groups["user"].Value;
string section = matchResults.Groups["section"].Value;
Console.WriteLine(string.Format("User = {0}, Section = {1}", user, section));
matchResults = matchResults.NextMatch();
}
Console.ReadKey();
}
}
}
Using regex to first find the key value pairs and then doing splits... doesn't seem right.
I'm interested in a complete regex solution.
Anyone?
Check this out
\<a\s+href\s*=\s*["'](?<baseUri>.+?)\?(?:(?<key>.+?)=(?<value>.+?)[&"'])*\s*\>
You can get pairs with something like Groups["key"].Captures[i] & Groups["value"].Captures[i]
Perhaps something like this (I am rusty on regex, and wasn't good at them in the first place anyway. Untested):
/href="[^?]*([?&](userId=(?<user>\d+))|section=(?<section>\d+))*"/
(By the way, the XHTML is malformed; & should be & in the attributes.)
Another approach is to put the capturing groups inside lookaheads:
Regex r = new Regex(#"<a href=""file\.aspx\?" +
#"(?=[^""<>]*?user=(?<user>\w+))" +
#"(?=[^""<>]*?section=(?<section>\w+))";
If there are only two parameters, there's no reason to prefer this way over the alternation-based approaches suggested by Mike and strager. But if you needed to match three parameters, the other regexes would grow to several times their current length, while this one would only need another lookahead like just like the two existing ones.
By the way, contrary to your response to Claus, it matters quite a bit which language you're working in. There's a huge variation in capabilities, syntax, and API from one language to the next.
You did not say which regex flavor you are using. Since your sample URL links to an .aspx file, I'll assume .NET. In .NET, a single regex can have multiple named capturing groups with the same name, and .NET will treat them as if they were one group. Thus you can use the regex
userID=(?<user>\d+)§ion=(?<section>\d+)|section=(?<section>\d+)&userID=(?<user>\d+)
This simple regex with alternation will be far more efficient than any tricks with lookaround. You can easily expand it if your requirements include matching the parameters only if they're in a link.
a simple python implementation overcoming the ordering problem
In [2]: x = re.compile('(?:(userId|section)=(\d+))+')
In [3]: t = 'href="file.aspx?section=2&userId=123"'
In [4]: x.findall(t)
Out[4]: [('section', '2'), ('userId', '123')]
In [5]: t = 'href="file.aspx?userId=123§ion=2"'
In [6]: x.findall(t)
Out[6]: [('userId', '123'), ('section', '2')]