Regex - how to get time and date and get ISO8601 timestamp - regex

Question

I have this text
2014-01-30 10:15 some text here
2014-01-30 10:20 some other text here
I need a regex that matches a timestamp group in ISO 8601 format.
Required output:
2014-01-30T10:15Z
2014-01-30T10:20Z
With this REGEX I can't get what I want, replace the space with 'T' and append a 'Z at the end.
^(?<timestamp>\S+ \S+)
Does anyone know how to solve this problem?
--- UPDATE ---
BTW, I'm using http://rubular.com/ to test my regex

Answer 1

You could perhaps modify your current regex a bit to:
^(\S+) (\S+).*
And replace with $1T$2Z
regex101 demo

Answer 2

\d{4}-\d{2}-\d{2} \d{2}:\d{2} will match the required format – validation is another story though (if you need it).
You can do something like if (regex match) { replace " " with "T"; append "Z" }
If this doesn't help you or it is unclear it is because your question was vague.
Edit: you didn't specify what language you're writing this in. That is how you would do your replacements.

Answer 3

In php:
preg_replace('/^(\S+) (\S+).*/', "$1T$2Z", $str);
In perl:
$str =~ s/^(\S+) (\S+).*/$1T$2Z/;
In notepad++
Find what: ^(\S+) (\S+).*
Replace with: $1T$2Z

Answer 4

With:
(\d{4}-\d{2}-\d{2})( \d{2}:\d{2} )(?:.*)
You can capture 2014-01-30 10:15 in groups (and ignore the text in another group).
Then you use the second group (10:15) to add 'T' at the beginning and 'Z' at the end.
See demo at:
http://rubular.com/r/4icGfcIixa

Answer 5

Regex is a bit different from language to language, it could help if you told us what language you are using.
For example, in javascript, you can do something like this:
"2014-01-30 10:15 some text here".replace(/(\d{4}-\d{2}-\d{2})\s(\d{2}:\d{2})\s?.*/,"$1T$2Z")
Where the string can be a variable.
If you have a multiple line text them you should add a g at the end of the regex:
"2014-01-30 10:15 some text here\n2014-01-30 10:20 some other text here".replace(/.*(\d{4}-\d{2}-\d{2})\s(\d{2}:\d{2})\s?.*/g,"$1T$2Z")