I want to get the ip address given url.
I am currently using this
std::string i;
std::string pingStr = (std::string)"nslookup " +"www.yahoo.com" ;
i = system (pingStr.c_str());
but the output is
Server: 127.0.1.1
Address: 127.0.1.1#53
Non-authoritative answer:
www.yahoo.com canonical name = atsv2-fp-shed.wg1.b.yahoo.com.
Name: atsv2-fp-shed.wg1.b.yahoo.com
Address: 106.10.250.10
Q: Is there anyway I can only get the Ip address?
Use the getaddrinfo(3) function to look up IP addresses, IPv4 or IPv6, in usable form.
you can use the folowing command.
nslookup www.yahoo.com | grep Address: | sed -n 2p
grep Address gives you all lines having "address" word in them
sed gets the 2nd line of those 2
You can truncate the "Address" part of output in c++.
I am just running the example on: https://docs.python.org/3/howto/ipaddress.html#ipaddress-howto
However, in the following example:
import ipaddress
net4 = ipaddress.ip_network("192.0.2.0/24")
for x in net4.hosts():
print(x)
I got the following error:
AddressValueErrorTraceback (most recent call last)
<ipython-input-18-256ed42a96d9> in <module>()
1 import ipaddress
2
----> 3 net4 = ipaddress.ip_network("192.0.2.0/24")
4 for x in net4.hosts():
5 print(x)
/usr/local/lib/python2.7/dist-packages/ipaddress.pyc in ip_network(address, strict)
197 '%r does not appear to be an IPv4 or IPv6 network. '
198 'Did you pass in a bytes (str in Python 2) instead of'
--> 199 ' a unicode object?' % address)
200
201 raise ValueError('%r does not appear to be an IPv4 or IPv6 network' %
AddressValueError: '192.0.2.0/24' does not appear to be an IPv4 or IPv6 network. Did you pass in a bytes (str in Python 2) instead of a unicode object?
Did I miss anything here (I am using python 2.7)? Thanks!
You can change second line to
net4 = ipaddress.ip_network(unicode("192.0.2.0/24"))
The complete code looks like
import ipaddress
net4 = ipaddress.ip_network(unicode("192.0.2.0/24"))
for x in net4.hosts():
print(x)
I resolved it by inputing a unicode string, similar to another question:
ValueError: '10.0.0.0/24' does not appear to be an IPv4 or IPv6 network
I have this :
# grab the internal ip [eg 10.5.20.2]
- name: Grab the internal ip to setup the sec group rule
local_action: shell /sbin/ip -o -4 addr list eth0 | awk '{print $4}' | cut -d/ -f1 # returns the ip
register: internal_ip # save the output of the above command in a var
- debug: var=internal_ip.stdout
I want to set this IP in the inbound rule of an AWS security group as single host IP.
Like this: 10.5.20.2/32
How do I concatenate the internal_ip registered var with the string /32 ??
I scratched and bled but found it... :]
"{{ internal_ip.stdout }}/32"
I have a string in a bash script that contains a line of a log entry such as this:
Oct 24 12:37:45 10.224.0.2/10.224.0.2 14671: Oct 24 2012 12:37:44.583 BST: %SEC_LOGIN-4-LOGIN_FAILED: Login failed [user: root] [Source: 10.224.0.58] [localport: 22] [Reason: Login Authentication Failed] at 12:37:44 BST Wed Oct 24 2012
To clarify; the first IP listed there "10.224.0.2" was the machine the submitted this log entry, of a failed login attempt. Someone tried to log in, and failed, from the machine at the 2nd IP address in the log entry, "10.224.0.58".
I wish to replace the first occurrence of the IP address "10.224.0.2" with the host name of that machine, as you can see presently is is "IPADDRESS/IPADDRESS" which is useless having the same info twice. So here, I would like to grep (or similar) out the first IP and then pass it to something like the host command to get the reverse host and replace it in the log output.
I would like to repeat this for the 2nd IP "10.224.0.58". I would like to find this IP and also replace it with the host name.
It's not just those two specific IP address though, any IP address. So I want to search for 4 integers between 1 and 3, separated by 3 full stops '.'
Is regex the way forward here, or is that over complicating the issue?
Many thanks.
Replace a fixed IP address with a host name:
$ cat log | sed -r 's/10\.224\.0\.2/example.com/g'
Replace all IP addresses with a host name:
$ cat log | sed -r 's/[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}/example.com/g'
If you want to call an external program, it's easy to do that using Perl (just replace host with your lookup tool):
$ cat log | perl -pe 's/(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})/`host \1`/ge'
Hopefully this is enough to get you started.
There's variou ways to find th IP addresses, here's one. Just replace "printf '<<<%s>>>' " with "host" or whatever your command name is in this GNU awk script:
$ cat tst.awk
{
subIp = gensub(/\/.*$/,"","",$4)
srcIp = gensub(/.*\[Source: ([^]]+)\].*/,"\\1","")
"printf '<<<%s>>>' " subIp | getline subName
"printf '<<<%s>>>' " srcIp | getline srcName
gsub(subIp,subName)
gsub(srcIp,srcName)
print
}
$
$ gawk -f tst.awk file
Oct 24 12:37:45 <<<10.224.0.2>>>/<<<10.224.0.2>>> 14671: Oct 24 2012 12:37:44.583 BST: %SEC_LOGIN-4-LOGIN_FAILED: Login failed [user: root] [Source: <<<10.224.0.58>>>] [localport: 22] [Reason: Login Authentication Failed] at 12:37:44 BST Wed Oct 24 2012
googled this one line command together. but was unable to pass the founded ip address to the ssh command:
sed -n 's/\([0-9]\{1,3\}\.\)\{3\}[0-9]\{1,3\}/\nip&\n/gp' test | grep ip | sed 's/ip//' | sort | uniq
the "test" is the file the sed command is searching for for the pattern
I am using the following code within a procedure in order to get an IP address of eth1 and use it as a gateway. Another thing I want is to use this variable (the IP address) outside, in the user scope.
global my_gw_ip_address
expect "# "
send "ifconfig eth1 | grep 'inet addr:' | cut -d: -f2 | awk '{print \$1}' > prod_ip_base.txt\r"
expect "# "
send " my_internal_gw=`cat prod_ip_base.txt`\r"
expect "# "
send " echo \$my_internal_gw\r"
expect "root#cnode-pp81:~ "
set checking_buffer_out $expect_out(buffer)
regexp {(?:\d+\.){3}\d+} $checking_buffer_out my_gw_ip_address
puts "internal gw: $my_gw_ip_address\n"
the output of the function is:
1. the line send " echo \$my_internal_gw\r" returns the correct IP address 192.168.138.50
2. the line puts "internal gw: $my_gw_ip_address\n" returns internal gw: 0.
can anyone please tell me what I do wrong? Why the variable $my_gw_ip_address is 0?
I solve the problem.
I should have added sleep 1 between the following commands.
change
set checking_buffer_out $expect_out(buffer)
regexp {(?:\d+\.){3}\d+} $checking_buffer_out my_gw_ip_address
to be:
set checking_buffer_out $expect_out(buffer)
sleep 1
regexp {(?:\d+\.){3}\d+} $checking_buffer_out my_gw_ip_address
Amigal