C++: speeding up a for-loop using goto? - c++

In the following for-loop, I don't do anything if conditionA, conditionB, and conditionC all evaluate to true.
for (int i = 0; i < imax; ++i) {
bool conditionA;
// evaluate conditionA
bool conditionB;
// evaluate conditionB
bool conditionC;
// evaluate conditionC
if (conditionA && conditionB && conditionC) continue;
// do something
}
If conditonA evaluates to false, it becomes unnecessary to evaluate conditionB and conditionC. So it seems that I can speed up the loop by writing it in the following way.
for (int i = 0; i < imax; ++i) {
bool conditionA;
// evaluate conditionA
if (conditionA) {
bool conditionB;
// evaluate conditionB
if (conditionB) {
bool conditionC;
// evaluate conditionC
if (conditionC) continue;
}
}
// do something
}
Now this looks ugly and is not understood at first glance. It seems that using the infamous goto the code becomes much more elegant:
for (int i = 0; i < imax; ++i) {
bool conditionA;
// evaluate conditionA
if (!conditionA) goto doSomething;
bool conditionB;
// evaluate conditionB
if (!conditionB) goto doSomething;
bool conditionC;
// evaluate conditionC
if (conditionC) continue;
doSomething:
// do something
}
Does this work as a method for speeding up the loop or is the compiler smart enough that the first version of the code is actually as fast as the second and third version? In case it isn't, is there a better alternative than using goto?

I would move the evaluation of the conditions into separate functions and then do:
for (int i = 0; i < imax; ++i) {
if (conditionA() && conditionB() && conditionC()) continue;
// do something
}
If conditionA returns false, conditionB will never be called, and so on.
This will also make your function shorter and more concise, dividing responsibilities up among other functions.
If you have no good reason for doing an "early exit" like that, you can avoid using continue altogether:
for (int i = 0; i < imax; ++i) {
if (!(conditionA() && conditionB() && conditionC())) {
// do something
}
}
Or use De Morgan's law to get !conditionA() || !conditionB() || !conditionC - whichever you prefer.

Before you try to speed something up, consult your profiler if the loop is really the bottleneck. If it is not, leave the code readable and maintainable (as opposed to a maybe slightly faster, maybe slower but surely errorprone and unreadable mess) and leave it to your compiler's capability to speed things up.
If the loop is the bottleneck, try whatever comes to mind, profile it, and compare the results. Nobody can surely say what your compiler might optimize away.
Never trust anyone but your profiler when it comes to micro performance optimizations.
Compilers are different in what they optimize and how they optimize it, and humans are particularly bad in predicting the savings of those optimizations.
However, if the conditions are not too complicated, I bet the compiler will optimize the boolean variables away anyways and leave you with something like
for (int i = 0; i < imax; ++i) {
if(evalConditionA() && evalConditionB() && evalConditionC())
continue;
doSomething:
}
What you always can do is asess the probabilities to any of the conditions to become false and put the one first that is most likely to trigger short circuit evaluation, so the others wont need to be evaluated so often.

well, as always, if you're wondering about performances, just do a benchmark. Otherwise, I think the best solution really depends on your context. For example your first solution is the best if you can make your conditions in the valuation or as separate functions (or worst case as macros):
for (int i = 0; i < imax; ++i) {
if (! (evaluate conditionA) && (evaluate conditionB) && (evaluate conditionC)) {
// do something
}
}
then lazy evaluation will come to help, and depending on what you do, your compiler may be able to optimize your evaluation with some optimization options.
I also advice you not to use if (condition) continue; but instead if (!condition) { /* do something */ } which helps a better understanding of the algorithm. Don't forget that what you code will be read by someone one day, and that someone may be you!

C++ Compilers (at least Visual Studio) already done what you looking for.
if( bCondA && bCondB && bCondC )
If bCondA == false, the others are not verified.
Should be true for all compilers.

Related

How to avoid use of goto and break nested loops efficiently

I'd say that it's a fact that using goto is considered a bad practice when it comes to programming in C/C++.
However, given the following code
for (i = 0; i < N; ++i)
{
for (j = 0; j < N; j++)
{
for (k = 0; k < N; ++k)
{
...
if (condition)
goto out;
...
}
}
}
out:
...
I wonder how to achieve the same behavior efficiently not using goto. What i mean is that we could do something like checking condition at the end of every loop, for example, but AFAIK goto will generate just one assembly instruction which will be a jmp. So this is the most efficient way of doing this I can think of.
Is there any other that is considered a good practice? Am I wrong when I say it is considered a bad practice to use goto? If I am, would this be one of those cases where it's good to use it?
Thank you
The (imo) best non-goto version would look something like this:
void calculateStuff()
{
// Please use better names than this.
doSomeStuff();
doLoopyStuff();
doMoreStuff();
}
void doLoopyStuff()
{
for (i = 0; i < N; ++i)
{
for (j = 0; j < N; j++)
{
for (k = 0; k < N; ++k)
{
/* do something */
if (/*condition*/)
return; // Intuitive control flow without goto
/* do something */
}
}
}
}
Splitting this up is also probably a good idea because it helps you keep your functions short, your code readable (if you name the functions better than I did) and dependencies low.
If you have deeply-nested loops like that and you must break out, I believe that goto is the best solution. Some languages (not C) have a break(N) statement that will break out of more than one loop. The reason C doesn't have it is that it's even worse than a goto: you have to count the nested loops to figure out what it does, and it's vulnerable to someone coming along later and adding or removing a level of nesting, without noticing that the break count needs to be adjusted.
Yes, gotos are generally frowned upon. Using a goto here is not a good solution; it's merely the least of several evils.
In most cases, the reason you have to break out of a deeply-nested loop is because you're searching for something, and you've found it. In that case (and as several other comments and answers have suggested), I prefer to move the nested loop to its own function. In that case, a return out of the inner loop accomplishes your task very cleanly.
(There are those who say that functions must always return at the end, not from the middle. Those people would say that the easy break-it-out-to-a-function solution is therefore invalid, and they'd force the use of the same awkward break-out-of-the-inner-loop technique(s) even when the search was split off to its own function. Personally, I believe those people are wrong, but your mileage may vary.)
If you insist on not using a goto, and if you insist on not using a separate function with an early return, then yes, you can do something like maintaining extra Boolean control variables and testing them redundantly in the control condition of each nested loop, but that's just a nuisance and a mess. (It's one of the greater evils that I was saying using a simple goto is lesser than.)
I think that goto is a perfectely sane thing to do here, and is one of it's exceptional use cases per the C++ Core Guidelines.
However, perhaps another solution to be considered is an IIFE lambda. In my opinion this is slightly more elegant than declaring a separate function!
[&] {
for (int i = 0; i < N; ++i)
for (int j = 0; j < N; j++)
for (int k = 0; k < N; ++k)
if (condition)
return;
}();
Thanks to JohnMcPineapple on reddit for this suggestion!
In this case you don't wan't to avoid using goto.
In general the use of goto should be avoided, however there are exceptions to this rule, and your case is a good example of one of them.
Let's look at the alternatives:
for (i = 0; i < N; ++i) {
for (j = 0; j < N; j++) {
for (k = 0; k < N; ++k) {
...
if (condition)
break;
...
}
if (condition)
break;
}
if (condition)
break;
}
Or:
int flag = 0
for (i = 0; (i < N) && !flag; ++i) {
for (j = 0; (j < N) && !flag; j++) {
for (k = 0; (k < N) && !flag; ++k) {
...
if (condition) {
flag = 1
break;
...
}
}
}
Neither of these is as concise or as readable as the goto version.
Using a goto is considered acceptable in cases where you're only jumping ahead (not backward) and doing so makes your code more readable and understandable.
If on the other hand you use goto to jump in both directions, or to jump into a scope which could potentially bypass variable initialization, that would be bad.
Here's a bad example of goto:
int x;
scanf("%d", &x);
if (x==4) goto bad_jump;
{
int y=9;
// jumping here skips the initialization of y
bad_jump:
printf("y=%d\n", y);
}
A C++ compiler will throw an error here because the goto jumps over the initialization of y. C compilers however will compile this, and the above code will invoke undefined behavior when attempting to print y which will be uninitialized if the goto occurs.
Another example of proper use of goto is in error handling:
void f()
{
char *p1 = malloc(10);
if (!p1) {
goto end1;
}
char *p2 = malloc(10);
if (!p2) {
goto end2;
}
char *p3 = malloc(10);
if (!p3) {
goto end3;
}
// do something with p1, p2, and p3
end3:
free(p3);
end2:
free(p2);
end1:
free(p1);
}
This performs all of the cleanup at the end of the function. Compare this to the alternative:
void f()
{
char *p1 = malloc(10);
if (!p1) {
return;
}
char *p2 = malloc(10);
if (!p2) {
free(p1);
return;
}
char *p3 = malloc(10);
if (!p3) {
free(p2);
free(p1);
return;
}
// do something with p1, p2, and p3
free(p3);
free(p2);
free(p1);
}
Where the cleanup is done in multiple places. If you later add more resources that need to be cleaned up, you have to remember to add the cleanup in all of these places plus the cleanup of any resources that were obtained earlier.
The above example is more relevant to C than C++ since in the latter case you can use classes with proper destructors and smart pointers to avoid manual cleanup.
Lambdas let you create local scopes:
[&]{
for (i = 0; i < N; ++i)
{
for (j = 0; j < N; j++)
{
for (k = 0; k < N; ++k)
{
...
if (condition)
return;
...
}
}
}
}();
if you also want the ability to return out of that scope:
if (auto r = [&]()->boost::optional<RetType>{
for (i = 0; i < N; ++i)
{
for (j = 0; j < N; j++)
{
for (k = 0; k < N; ++k)
{
...
if (condition)
return {};
...
}
}
}
}()) {
return *r;
}
where returning {} or boost::nullopt is a "break", and returning a value returns a value from the enclosing scope.
Another approach is:
for( auto idx : cube( {0,N}, {0,N}, {0,N} ) {
auto i = std::get<0>(idx);
auto j = std::get<1>(idx);
auto k = std::get<2>(idx);
}
where we generate an iterable over all 3 dimensions and make it a 1 deep nested loop. Now break works fine. You do have to write cube.
In c++17 this becomes
for( auto[i,j,k] : cube( {0,N}, {0,N}, {0,N} ) ) {
}
which is nice.
Now, in an application where you are supposed to be responsive, looping over a large 3 dimensional range at primiary control flow level is often a bad idea. You can thread it off, but even then you end up with problem that the thread runs too-long. And most 3 dimensional large iterations I've played with can benefit from using sub-task threading themselves.
To that end, you'll end up wanting to categorize your operation based on what kind of data it accesses, then pass your operation to something that schedules the iteration for you.
auto work = do_per_voxel( volume,
[&]( auto&& voxel ) {
// do work on the voxel
if (condition)
return Worker::abort;
else
return Worker::success;
}
);
then the control flow involved goes into the do_per_voxel function.
do_per_voxel isn't going to be a simple naked loop, but rather a system to rewrite the per-voxel tasks into per-scanline tasks (or even per-plane tasks depending on how large the planes/scanlines are at runtime (!)) then dispatch them in turn to a thread pool managed task scheduler, stitch up the resulting task handles, and return a future-like work that can be awaited on or used as a continuation trigger for when the work is done.
And sometimes you just use goto. Or you manually break out functions for subloops. Or you use flags to break out of deep recursion. Or you put the entire 3 layer loop in its own function. Or you compose the looping operators using a monad library. Or you can throw an exception (!) and catch it.
The answer to almost every question in c++ is "it depends". The scope of problem and the number of techniques you have available is large, and the details of the problem change the details of the solution.
Alternative - 1
You can do something like follows:
Set a bool variable in the beginning isOkay = true
All of your forloop conditions, add an extra condition isOkay == true
When your your custom condition is satisfied/ fails, set isOkay = false.
This will make your loops stop. An extra bool variable would be sometimes handy though.
bool isOkay = true;
for (int i = 0; isOkay && i < N; ++i)
{
for (int j = 0; isOkay && j < N; j++)
{
for (int k = 0; isOkay && k < N; ++k)
{
// some code
if (/*your condition*/)
isOkay = false;
}
}
}
Alternative - 2
Secondly. if the above loop iterations are in a function, best choice is to return result, when ever the custom condition is satisfied.
bool loop_fun(/* pass the array and other arguments */)
{
for (int i = 0; i < N ; ++i)
{
for (int j = 0; j < N ; j++)
{
for (int k = 0; k < N ; ++k)
{
// some code
if (/* your condition*/)
return false;
}
}
}
return true;
}
Break your for loops out into functions.
It makes things significantly easier to understand because now you can see what each loop is actually doing.
bool doHerpDerp() {
for (i = 0; i < N; ++i)
{
if (!doDerp())
return false;
}
return true;
}
bool doDerp() {
for (int i=0; i<X; ++i) {
if (!doHerp())
return false;
}
return true;
}
bool doHerp() {
if (shouldSkip)
return false;
return true;
}
Is there any other that is considered a good practice? Am I wrong when
I say it is considered a bad practice to use goto?
goto can be misused and overused, but I dont see any of the two in your example. Breaking out of a deeply nested loop is most clearly expressed by a simple goto label_out_of_the_loop;.
It is bad practice to use many gotos that jump to different labels, but in such cases it isnt the keyword goto itself that makes your code bad. It is the fact that you are jumping around in the code making it hard to follow that makes it bad. If however, you need a single jump out of nested loops then why not use the tool that was made for exactly that purpose.
To use a made up out of thin air analogy: Imagine you live in a world where in the past it was hip to hammer nails into walls. In recent times it became more fashinable to drill screws into walls using screwdrivers and hammers are completely out of fashion. Now consider you have to (despite being a bit old-fashinoned) get a nail into a wall. You should not refrain from using a hammer to do that, but maybe you should rather ask yourself if you really need a nail in the wall instead of a screw.
(Just in case it isnt clear: The hammer is goto and the nail in the wall is a jump out of a nested loop while the screw in the wall would be using functions to avoid the deep nesting alltogether ;)
One possible way is to assign a boolean value to a variable that represents the state. This state can later be tested using an "IF" conditional statement for other purposes later on in the code.
as far as your comment on efficiency compiling the both options in release mode on visual studio 2017 produces the exact same assembly.
for (int i = 0; i < 5; ++i)
{
for (int j = 0; j < 5; ++j)
{
for (int k = 0; k < 5; ++k)
{
if (i == 1 && j == 2 && k == 3) {
goto end;
}
}
}
}
end:;
and with a flag.
bool done = false;
for (int i = 0; i < 5; ++i)
{
for (int j = 0; j < 5; ++j)
{
for (int k = 0; k < 5; ++k)
{
if (i == 1 && j == 2 && k == 3) {
done = true;
break;
}
}
if (done) break;
}
if (done) break;
}
both produce..
xor edx,edx
xor ecx,ecx
xor eax,eax
cmp edx,1
jne main+15h (0C11015h)
cmp ecx,2
jne main+15h (0C11015h)
cmp eax,3
je main+27h (0C11027h)
inc eax
cmp eax,5
jl main+6h (0C11006h)
inc ecx
cmp ecx,5
jl main+4h (0C11004h)
inc edx
cmp edx,5
jl main+2h (0C11002h)
so there is no gain. Another option if your using a modern c++ compiler is to wrap it in a lambda.
[](){
for (int i = 0; i < 5; ++i)
{
for (int j = 0; j < 5; ++j)
{
for (int k = 0; k < 5; ++k)
{
if (i == 1 && j == 2 && k == 3) {
return;
}
}
}
}
}();
again this produces the exact same assembly. Personally I think using goto in your example is perfectly acceptable. It is clear what is happening to anyone else, and makes for more concise code. Arguably the lambda is equally as concise.
Specific
IMO, in this specific example, I think it is important to notice a common functionality between your loops. (Now I know that your example isn't necessarily literal here, but just bear with me for a sec) as each loop iterates N times, you can restructure your code like the following:
Example
int max_iterations = N * N * N;
for (int i = 0; i < max_iterations; i++)
{
/* do stuff, like the following for example */
*(some_ptr + i) = 0; // as opposed to *(some_3D_ptr + i*X + j*Y + Z) = 0;
// some_arr[i] = 0; // as oppose to some_3D_arr[i][j][k] = 0;
}
Now, it is important to remember that all loops, while for or otherwise, are really just syntatic sugar for the if-goto paradigm. I agree with the others that you ought to have a function return the result, however I wanted to show an example like the above in which that may not be the case. Granted, I'd flag the above in a code review but if you replaced the above with a goto I'd consider that a step in the wrong direction. (NOTE -- Make sure that you can reliably fit it into your desired datatype)
General
Now, as a general answer, the exit conditions for your loop may not be the same everytime (like the post in question). As a general rule, pull as many unneeded operations out of your loops (multiplications, etc.) as far out as you can as, while compilers are getting smarter everyday, there is no replacement for writing efficient and readable code.
Example
/* matrix_length: int of m*n (row-major order) */
int num_squared = num * num;
for (int i = 0; i < matrix_length; i++)
{
some_matrix[i] *= num_squared; // some_matrix is a pointer to an array of ints of size matrix_length
}
rather than writing *= num * num, we no longer have to rely on the compiler to optimize this out for us (though any good compiler should). So any doubly or triply nested loops which perform the above functionality would also benefit not only your code, but IMO writing clean and efficient code on your part. In the first example, we could have instead had *(some_3D_ptr + i*X + j*Y + Z) = 0;! Do we trust the compiler to optimize out i*X and j*Y, so that they aren't computed every iteration?
bool check_threshold(int *some_matrix, int max_value)
{
for (int i = 0; i < rows; i++)
{
int i_row = i*cols; // no longer computed inside j loop unnecessarily.
for (int j = 0; j < cols; j++)
{
if (some_matrix[i_row + j] > max_value) return true;
}
}
return false;
}
Yuck! Why aren't we using classes provided by the STL or a library like Boost? (we must be doing some low level/high performant code here). I couldn't even write a 3D version, due to the complexity. Even though we have hand optimized something, it may even be better to use #pragma unroll or similar preprocessor hints if your compiler allows.
Conclusion
Generally, the higher the abstraction level you can use, the better, however if say aliasing a 1-Dimensional row-major order matrix of integers to a 2-Dimensional array makes your code-flow harder to understand/extend, is it worth it? Likewise, that also may be an indicator to make something into its own function. I hope that, given these examples, you can see that different paradigms are called for in different places, and its your job as the programmer to figure that out. Don't go crazy with the above, but make sure you know what they mean, how to use them, and when they are called for, and most importantly, make sure the other people using your codebase know what they are as well and have no qualms about it. Good luck!
bool meetCondition = false;
for (i = 0; i < N && !meetCondition; ++i)
{
for (j = 0; j < N && !meetCondition; j++)
{
for (k = 0; k < N && !meetCondition; ++k)
{
...
if (condition)
meetCondition = true;
...
}
}
}
There are already several excellent answers that tell you how you can refactor your code, so I won’t repeat them. There isn’t a need to code that way for efficiency any more; the question is whether it’s inelegant. (Okay, one refinement I’ll suggest: if your helper functions are only ever intended to be used inside the body of that one function, you might help the optimizer out by declaring them static, so it knows for certain that the function does not have external linkage and will never be called from any other module, and the hint inline can’t hurt. However, previous answers say that, when you use a lambda, modern compilers don’t need any such hints.)
I’m going to challenge the framing of the question a bit. You’re correct that most programmers have a taboo against using goto. This has, in my opinion, lost sight of the original purpose. When Edsger Dijkstra wrote, “Go To Statement Considered Harmful,” there was a specific reason he thought so: the “unbridled” use of go to makes it too hard to reason formally about the current program state, and what conditions must currently be true, compared to control flow from recursive function calls (which he preferred) or iterative loops (which he accepted). He concluded:
The go to statement as it stands is just too primitive; it is too much an invitation to make a mess of one's program. One can regard and appreciate the clauses considered as bridling its use. I do not claim that the clauses mentioned are exhaustive in the sense that they will satisfy all needs, but whatever clauses are suggested (e.g. abortion clauses) they should satisfy the requirement that a programmer independent coordinate system can be maintained to describe the process in a helpful and manageable way.
Many C-like programming languages, for example Rust and Java, do have an additional “clause considered as bridling its use,” the break to a label. An even more restricted syntax might be something like break 2 continue; to break out of two levels of the nested loop and resume at the top of the loop containing them. This presents no more of a problem than a C-style break to what Dijkstra wanted to do: defining a concise description of the program state that programmers can keep track of in their heads or a static analyzer would find tractable.
Restricting goto to constructions like this makes it simply a renamed break to a label. The remaining problem with it is that the compiler and the programmer don’t necessarily know you’re only going to use it this way.
If there’s an important post-condition that holds after the loop, and your concern with goto is the same as Dijkstra’s, you might consider stating it in a short comment, something like // We have done foo to every element, or encountered condition and stopped. That would alleviate the problem for humans, and a static analyzer should do fine.
The best solution is to put the loops in a function and then return from that function.
This is essentially the same thing as your goto example, but with the massive benefit that you avoid having yet another goto debate.
Simplified pseudo code:
bool function (void)
{
bool result = something;
for (i = 0; i < N; ++i)
for (j = 0; j < N; j++)
for (k = 0; k < N; ++k)
if (condition)
return something_else;
...
return result;
}
Another benefit here is that you can upgrade from bool to an enum if you come across more than 2 scenarios. You can't really do that with goto in a readable way. The moment you start to use multiple gotos and multiple labels, is the moment you embrace spaghetti coding. Yes, even if you just branch downwards - it will not be pretty to read and maintain.
Notably, if you have 3 nested for loops, that may be an indication that you should try to split your code up in several functions and then this whole discussion might not even be relevant.

Is there a way of doing a "post switch" like operation with bool?

I have a condition like the following where I just want to have the second bool be the trigger for a single time, since this condition is invoked relatively often I don't like the idea of doing the assignment of it being false every time the condition is true so, I tried to take advantage of the order of logical AND and OR and the post increment operator. But it appears to work don't do what I expected it to do. So is there a way to make a post state switch for this line?
where firstTitleNotSet is:
bool firstTitleNotSet;
if (titleChangedSinceLastGet() || (p_firstTitleNotSet && p_firstTitleNotSet++))
The idea is that the first part is the primary trigger and the second is the trigger that only has to trigger the first time.
While I easily could do
if (titleChangedSinceLastGet() || p_firstTitleNotSet)
{
firstTitleNotSet = false;
//...
}
I don't like this as it is reassigning false when ever the conditional block is invoked.
So is there some way of "post change" the value of a bool from true to false? I know that this would work the other way around but this would negate the advantage of the method most time being the true trigger and therefor skipping the following check.
Note: The reasons for me making such considerations isntead of just taking the second case is, that this block will be called frequently so I'm looking to optimize its consumed runtime.
Well, you could do something like:
if (titleChangedSinceLastGet() ||
(p_firstTitleNotSet ? ((p_firstTitleNotSet=false), true):false))
An alternative syntax would be:
if (titleChangedSinceLastGet() ||
(p_firstTitleNotSet && ((p_firstTitleNotSet=false), true)))
Either one looks somewhat ugly. Note, however, that this is NOT the same as your other alternative:
if (titleChangedSinceLastGet() || p_firstTitleNotSet)
{
p_firstTitleNotSet = false;
//...
}
With your proposed alternative, pontificate the fact that p_firstTitleNotSet gets reset to false no matter what, even if the conditional was entered because titleChangedSinceLastGet().
A more readable way than the assignment inside a ternary operator inside an or inside an if would be just moving the operations to their own statements:
bool needsUpdate = titleChangedSinceLastGet();
if(!needsUpdate && firstTitleSet)
{
needsUpdate = true;
firstTitleSet = false;
}
if(needsUpdate)
{
//...
}
This is likely to produce very similar assembly than the less readable alternative proposed since ternary operators are mostly just syntactic sugar around if statements.
To demonstrate this I gave GCC Explorer the following code:
extern bool first;
bool changed();
int f1()
{
if (changed() ||
(first ? ((first=false), true):false))
return 1;
return 0;
}
int f2()
{
bool b = changed();
if(!b && first)
{
b = true;
first = false;
}
return b;
}
and the generated assembly had only small differences in the generated assembly after optimizations. Certainly have a look for yourself.
I maintain, however, that this is highly unlikely to make a noticeable difference in performance and that this is more for interest's sake.
In my opinion:
if(titleChangedSinceLastUpdate() || firstTitleSet)
{
firstTitleSet = false;
//...
}
is an (at least) equally good option.
You can compare the assembly of the above functions with this one to compare further.
bool f3()
{
if(changed() || first)
{
first = false;
return true;
}
return false;
}
In this kind of situation, I usually write:
bool firstTitleNotSet = true;
if (titleChangedSinceLastGet() || firstTitleNotSet)
{
if (firstTileNotSet) firstTitleNotSet = false;
//...
}
That second comparison will likely be optimized by the compiler.
But if you have a preference for a post-increment operator:
int iterationCount = 0;
if (titleChangedSinceLastGet() || iterationCount++ != 0)
{
//...
}
Note that this will be a problem if iterationCount overflows, but the same is true of the bool firstTitleNotSet that you were post-incrementing.
In terms of code readability and maintainability, I would recommend the former. If the logic of your code is sound, you can probably rely on the compiler to do a very good job optimizing it, even if it looks inelegant to you.
That should work:
int firstTitleSet = 0;
if (titleChangedSinceLastGet() || (!firstTitleSet++))
If you wish to avoid overflow you can do:
int b = 1;
if (titleChangedSinceLastGet() || (b=b*2%4))
at the first iteration b=2 while b=0 at the rest of them.

Removing code dynamically?

I'm in a for loop in C++ and i want an "if" clause inside of it to disappear in the next iteration (for the sake of performance) after it checks the value as true once. Is that possible in C++ or in any other language?
There is no magic to change to code dynamically. Executing an if clause in a loop is probably not super-expensive if the if condition is cheap to execute.
If the condition is expensive to evaluate, you may want to protect it with an extra boolean variable:
bool mustCheck = true;
size_t const n = ...; // number of iterations
for (size_t i = 0; i < n; ++i) {
if (mustCheck && theExpensiveCheck(...)) {
mustCheck = false; // turn off the check now
....
}
...
}
If the goal is to execute the check on the first iteration only, you could test if the loop index is 0:
for (size_t i = 0; i < n; ++i) {
if (i == 0 && theExpensiveCheck(...)) {
....
}
...
}
Another option that does not have an if inside the loop is to pull out the if completely, and execute it before the loop if the loop has at least one iteration:
size_t const n = ...; // number of iterations
if (n > 0) {
// do check and execute loop body for first item
if (theExpensiveCheck()) {
....
}
}
// start regular loop, starting at index 1
for (size_t i = 1; i < n; ++i) {
// execute loop body for other items
...
}
The modifications above add extra complexity (and thus potential bugs) to your code. I would recommend to not perform any of these modifications if it's unclear whether there actually is a perform problem with the loop or the if condition. Often enough, applying the above modifications will not result in substantial performance gains, but clearly it depends on the if condition.
Compilers nowadays also provide several powerful loop optimization techniques, so you should make sure you're compiling with all these optimizations turned on.
This is not possible in C++. Once it is compiled, that's it. But, you shouldn't worry about checking a value once. The performance impact is insignificant.
I suppose if the value check was pretty involved (ie more than simple checking if it is T or F), you could add some sort of flag to check first and then skip the rest of the check if it is true. This obviously requires its own check/assignment and is most likely not worth doing.

How to infinite loop or loop up to a limit without an if-else

I'm wondering if there's a way to write a function that takes one input, a max count for the number of times to loop, that will do an infinite loop if the number is negative, without using an if-else
i.e.
void func(int nAttempts) // if nAttempts <= 0, do an infinite loop
{
if ( nAttempts <= 0 )
{ // do an infinite loop
}
else
{ // do a loop up to nAttemtps
}
}
I'd like to know if there's a way to do that without an if-else
while ((nAttempts < 0) || (nAttempts-- > 0)) {...}
but... why? This makes your code less readable, where an if/else makes it pretty clear what your intentions are.
I take it this is some sort of a trick question? Here's my take:
void f(int n)
{
n < 0 ? []{ while(true); }() : [&]{ while(n--); }() ;
}
The loop itself has a conditional inside of it, it is not an explicit if, but it is a branch. The actual evaluation of that expression is turing complete as well due to lazy evaluation. As a result, this question is kind of nonsensical since even without an if statement, there is still a conditional statement taking place. However, the answer to your question is the following:
void optionalInfiniteLoop(int nAttempts){
while(nAttempts < 0 || nAttempts-- != 0){
...
}
}
Looking at this and understanding lazy evaluation, nAttempts < 0 is evaluated first. If it is true, the || does not need to run, and so it will never wrap the int around by subtracting too far. If it is false, then the second part of the while loop evaluates until nAttempts becomes 0. I don't think you'd save anything by doing this, and indeed, you may be forcing the computer to do slightly more work every iteration by checking nAttempts < 0 instead of just doing that once.
The performance is almost definitely not going to be measurable in the context of an application, and I think the above looks cleaner, but it's really more of a stylistic approach than a technical one.
void func( int nAttempts )
{
while (nAttempts)
{
// do stuff
--nAttempts;
}
}
Basically at the end of every iteration, you subtract one 'try'. When it hits 0 you stop. If it was already negative to begin with, it will become increasingly negative (though I suppose eventually it would overflow).

Why are empty expressions legal in C/C++?

int main()
{
int var = 0;; // Typo which compiles just fine
}
How else could assert(foo == bar); compile down to nothing when NDEBUG is defined?
This is the way C and C++ express NOP.
You want to be able to do things like
while (fnorble(the_smurf) == FAILED)
;
and not
while (fnorble(the_smurf) == FAILED)
do_nothing_just_because_you_have_to_write_something_here();
But! Please do not write the empty statement on the same line, like this:
while (fnorble(the_smurf) == FAILED);
That’s a very good way to confuse the reader, since it is easy to miss the semicolon, and therefore think that the next row is the body of the loop. Remember: Programming is really about communication — not with the compiler, but with other people, who will read your code. (Or with yourself, three years later!)
I'm no language designer, but the answer I'd give is "why not?" From the language design perspective, one wants the rules (i.e. the grammar) to be as simple as possible.
Not to mention that "empty expressions" have uses, i.e.
for (i = 0; i < INSANE_NUMBER; i++);
Will dead-wait (not a good use, but a use nonetheless).
EDIT: As pointed out in a comment to this answer, any compiler worth its salt would probably not busy wait at this loop, and optimize it away. However, if there were something more useful in the for head itself (other than i++), which I've seen done (strangely) with data structure traversal, then I imagine you could still construct a loop with an empty body (by using/abusing the "for" construct).
OK, I’ll add this to the worst case scenario that you may actually use:
for (int yy = 0; yy < nHeight; ++yy) {
for (int xx = 0; xx < nWidth; ++xx) {
for (int vv = yy - 3; vv <= yy + 3; ++vv) {
for (int uu = xx - 3; uu <= xx + 3; ++uu) {
if (test(uu, vv)) {
goto Next;
}
}
}
Next:;
}
}
I honestly don't know if this is the real reason, but I think something that makes more sense is to think about it from the standpoint of a compiler implementer.
Large portions of compilers are built by automated tools that analyze special classes of grammars. It seems very natural that useful grammars would allow for empty statements. It seems like unnecessary work to detect such an "error" when it doesn't change the semantics of your code. The empty statement won't do anything, as the compiler won't generate code for those statements.
It seems to me that this is just a result of "Don't fix something that isn't broken"...
Obviously, it is so that we can say things like
for (;;) {
// stuff
}
Who could live without that?
When using ;, please also be aware about one thing. This is ok:
a ? b() : c();
However this won't compile:
a ? b() : ; ;
There are already many good answers but have not seen the productive-environment sample.
Here is FreeBSD's implementation of strlen:
size_t
strlen(const char *str)
{
const char *s;
for (s = str; *s; ++s)
;
return (s - str);
}
The most common case is probably
int i = 0;
for (/* empty */; i != 10; ++i) {
if (x[i].bad) break;
}
if (i != 10) {
/* panic */
}
while (1) {
; /* do nothing */
}
There are times when you want to sit and do nothing. An event/interrupt driven embedded application or when you don't want a function to exit such as when setting up threads and waiting for the first context switch.
example:
http://lxr.linux.no/linux+v2.6.29/arch/m68k/mac/misc.c#L523