C++ multiple inheritance static function call ambiguity - c++

Question

I have the case where I am deriving a class from two different base classes both having a static function with the same name.
To resolve this ambiguity, I tried to use the scope operator - just as I would do for a member function. However This does not compile. Why? Wrong syntax?
I want to call the static function via the derived typename and not directly via base class name. Actually I would like prefer to prevent this case, but I have no idea how to do so.
The error (commented out) in the code below also occurs, when I leave the templates away:
#include <iostream>
template<class TDerived>
class StaticBaseA
{
public:
static void announce()
{
std::cout << "do something" << std::endl;
}
};
template<class TDerived>
class StaticBaseB
{
public:
static void announce()
{
std::cout << "do something else" << std::endl;
}
};
class Derived :
public StaticBaseA<Derived>
, public StaticBaseB<Derived>
{
using StaticBaseA<Derived>::announce;
};
class NonDerived {};
int main(int argc, char* argv[])
{
Derived::announce();
// What I want:
//Derived::StaticBaseB<Derived>::announce(); Error: "Undefined symbol 'StaticBaseB'
// What works, but what I don't want ...
StaticBaseB<Derived>::announce();
// ... because I would like to prevent this (however this is done):
StaticBaseB<NonDerived>::announce();
return 0;
}

Answer 1

Making "announce" protected in StaticBaseA and StaticBaseB might be part-way to doing what you want.
You then could not call StaticBaseB<NonDerived>::announce from main as it would be inaccessible. You could call it from a class derived from StaticBaseB.
In other words:
template<class TDerived>
class StaticBaseA
{
protected:
static void announce()
{
std::cout << "do something" << std::endl;
}
};
template<class TDerived>
class StaticBaseB
{
protected:
static void announce()
{
std::cout << "do something else" << std::endl;
}
};
In Derived you have to promote "announce" to public.
class Derived : public StaticA<Derived>, public StaticB<Derived >
{
public:
using StaticA<Derived>::announce;
};
int main()
{
Derived::announce(); // legal and calls StaticBaseA::announce
NotDerived::announce(); // no such function
StaticBaseA< Derived >::announce(); // not accessible
StaticBaseB< Derived >::announce(); // also not accessible
StaticBaseA< NotDerived >::announce(); // not accessible
StaticBaseB< NotDerived >::announce(); // also not accessible
}