Convert Comma Separated Hex (String) Array to either integer or float - c++

Question

The array is set up like so:
string * str = new string[11];
Where the content of the string looks like:
str[0]=AAAAAAAA,BBBBBBBB,CCCCCCCC,DDDDDDDD,EEEE,FFFFFFFF,GGGGGGGG,HHHH,IIII,JJJJ,KKKK
str[1]=AAAAAAAA,BBBBBBBB,CCCCCCCC,DDDDDDDD,EEEE,FFFFFFFF,GGGGGGGG,HHHH,IIII,JJJJ,KKKK
str[2]=AAAAAAAA,BBBBBBBB,CCCCCCCC,DDDDDDDD,EEEE,FFFFFFFF,GGGGGGGG,HHHH,IIII,JJJJ,KKKK
...
str[12]=AAAAAAAA,BBBBBBBB,CCCCCCCC,DDDDDDDD,EEEE,FFFFFFFF,GGGGGGGG,HHHH,IIII,JJJJ,KKKK
Another array looks like:
string * type = new string[11];
Where the content is:
type[0]="1";
type[1]="1";
type[2]="1";
type[3]="1";
type[4]="2";
type[5]="1";
type[6]="1";
type[7]="2";
type[8]="2";
type[9]="2";
type[10]="2";
These types correspond to each value in the string, so, for the first string:
1=float , 2=integer
AAAAAAAA would be 1; or an float
BBBBBBBB would be 1; or an float
CCCCCCCC would be 1; or an float
DDDDDDDD would be 1; or an float
EEEE would be 2; or a integer
FFFFFFFF would be 1; or an float
GGGGGGGG would be 1; or an float
HHHH would be 2; or a integer
IIII would be 2; or a integer
JJJJ would be 2; or a integer
KKKK would be 2; or a integer
In addition the single type array works for all strings in the str array.
Now for my question:
How do i use the above information to extract each individual values from the string and convert it to an integer or a float based on the value in the type array.
BE AWARE:
Boost is not available to me
The conversion functions look like: (The other is formatted similarly except for an integer)
unsigned int BinaryParser::hexToFloat(std::string hexInput)
{
std::stringstream ss (hexInput);
unsigned int floatOutput;
ss >> hex >> floatOutput;
return reinterpret_cast<float&>(floatOutput);
}

Answer 1

OK, first part: extract the comma-separated strings. One way would be:
std::vector<std::string> split( std::string s ){
std::vector<std::string> vec;
int pos = 0;
while( std::string::npos != (pos = s.find( ',', pos ) ) ){
vec.push_back( s.substr( 0, pos ) );
s = s.substr( pos + 1 );
}
vec.push_back( s );
return vec;
}
Depends on the input string being "well-behaved".
This converts an int from hex digits:
int convInt( std::string hexInput ){
std::istringstream iss (hexInput);
uint16_t intOutput;
iss >> std::hex >> intOutput;
return intOutput;
}
Float cannot be read using std::hex, so we assume the HHHHHHHH is a float's bytes interpreted as an int32_t.
float convFloat( std::string & hexInput ){
std::istringstream iss (hexInput);
uint32_t intOutput;
iss >> std::hex >> intOutput;
return reinterpret_cast<float&>(intOutput);
}
For storing the results we can use:
enum TypeTag { eInt, eFloat };
class IntOrFloat {
public:
IntOrFloat( int i ) : typeTag(eInt),integer(i),floating(0) { }
IntOrFloat( float f ) : typeTag(eFloat),integer(0),floating(f) { }
virtual ~IntOrFloat(){}
int getInt() const { return integer; }
float getFloat() const { return floating; }
TypeTag getTypeTag() const { return typeTag; }
private:
TypeTag typeTag;
int integer;
float floating;
};
std::ostream& operator<< (std::ostream& os, const IntOrFloat& iof){
switch( iof.getTypeTag() ){
case eInt:
os << iof.getInt();
break;
case eFloat:
os << iof.getFloat();
break;
}
return os;
}
To convert one comma-separated string according to the type vector:
std::vector<IntOrFloat> convert( const std::vector<std::string> t, const std::string s ){
std::vector<IntOrFloat> results;
std::vector<std::string> hexes = split( s );
for( int i = 0; i < hexes.size(); i++ ){
if( t[i] == "1" ){
results.push_back( IntOrFloat( convFloat( hexes[i] ) ) );
} else {
results.push_back( IntOrFloat( convInt( hexes[i] ) ) );
}
}
return results;
}
That's it, then. - I've been using vector instead of the arrays. You can easily convert, e.g.
std::vector<std::string> fromArray( std::string strs[], int n ){
std::vector<std::string> strings;
for( int i = 0; i < n; i++ ) strings.push_back( std::string( strs[i] ) );
return strings;
}
#define fromArray(a) fromArray( a, (sizeof(a)/sizeof(a[0])) )
And here is my test program:
#define LENGTH(a) (sizeof(a)/sizeof(a[0]))
int main(){
std::string t[] = {"2","1","1","2"};
std::string s[] = {
"8000,4048f5c3,bf000000,FFFF",
"0001,42f6e979,c44271ba,7FFF",
"1234,00000000,447a0000,5678"
};
std::vector<std::string> types = fromArray( t );
std::vector<std::string> strings = fromArray( s );
for( std::vector<std::string>::iterator it = strings.begin() ; it != strings.end(); ++it ){
std::vector<IntOrFloat> results = convert( types, *it );
std::cout << "converting string " << *it << ", " << results.size() << " values:" << std::endl;
for( std::vector<IntOrFloat>::iterator iof = results.begin() ; iof != results.end(); ++iof ){
std::cout << " " << *iof << std::endl;
}
}
}