As title stated I'm trying to create an IF expression that only lists true results. If false then move to the next cell.
This is what I have, right now it returns false as 0.
A1=if('Packet Input'!$E2="UG",'Packet Input'!D2, 0)
What I need is If E2="UG" then A1=D2. If false, move down to E3 and run the logic check again. If E3="UG" then A1=D3. If not then once again move down to E4 and run the logic check.
Change '0' to FALSE
User Filter function (https://support.google.com/drive/answer/3093197) on the results:
=filter(A1:A20,A1:A20<>FALSE)
It should be:
A1=if('Packet Input'!$E2="UG",'Packet Input'!D2, FALSE)
Related
I want to have the output of either true or false.
I have this syntax
.[] | (if (select(.displayName=="display")) then "yes" else "no" end)
This is the json source
[{"displayName":"display","message":"bla bla"}, {"displayName":"test","message":"bla bla"}]
I only need to query against the array and if the value im looking for exists in one of them I need the output to be "yes", and if it doesnt a "no". So a single output value is what I am looking for.
This evaluates to "yes", however, if the value display is not present in the json, it does not output "no", its just empty. Can anyone tell me why?
Here is a snippet to try: https://jqplay.org/s/WKcZh91hk8L
The idea is right, but you shouldn't be using select for this. The way select works is by evaluating the boolean expression provided inside (..) and returning the object, if the expression evaluates to true and skip the object from being considered/printed on false.
On your code, for the object that evaluates to false, select is evaluated as select(false) which as explained above returns nothing - this is not evaluated to boolean false condition. i.e. the return value of select is not a boolean value.
To use explicit boolean conditions, drop the select from expression and to summarise the result to a single value do something like below
if ( [ .[] | .displayName == "display" ] | any ) then "yes" else "no" end
Demo on jqplay
The way this works, is any can evaluate an array of boolean values and produces true as output if any of the elements of the array are true. We collect the match condition results to the array and apply any on it. i.e. [true, false] evaluates to true, thereby printing yes only once
A concise solution is possible with select:
select( any(.displayName=="display") ) | "yes" // "no"
Multiple IF statements are giving me a FALSE response instead of the requested BLANK.
I figured that the last of the IF statements that has a "" would give BLANK if none of the conditions are met.
I've tried isolating each IF to see if I'm missing a statement but I don't see it.
Here is my formula:
=IF((LEFT(D5,2))=H2,IF(C5="Yearly",G5,IF(C5="Fixed Monthly",G5/12,"")))
How can I modify this formula so that it does not give me a FALSE and instead gives me a BLANK as requested on the 3rd IF statement.
Thank you.
You may an else condition to the first if statement:
Here is my formula:
=IF(LEFT(D5,2)=H2, IF(C5="Yearly",
G5,
IF(C5="Fixed Monthly",G5/12,"")),
"") <-- add this
My guesd is that because you did not specify an explicit else condition, Excel is defaulting to showing FALSE.
I am currently in the course of learning Python 2.7 and have come across the Equality and Boolean operators
My question is:
Why False and 1 is False but True and 1 is 1
Likewise, False or 1 is 1 but True or 1 is True
Can someone kindly explain why this is happening
Many thanks
and returns the first 'falsy' (False, zero, empty string or list, etc.) value it sees, or the final value if none were falsy. Further values are not even evaluated, since they can't change the result.
or likewise returns the first 'truthy' (True, non-zero, non-empty string or list, etc.) value it sees (or the final one if there were none), and doesn't evaluate the rest.
This behavior is sometimes more convenient than strictly returning only True or False.
I have got an excel which has an formula and I am not able to understand how its working.
Here is the formula
=IF(C6=date1,0,IF(D6-endtime<=0,0,IF(D6-endtime>0,(D6-endtime)*1440)))
Can someone spends few minutes to post an explanation, how it works
Thanks,
Try looking at it like this:
=IF(C6=date1,
0,
IF(D6-endtime<=0,
0,
IF(D6-endtime>0,
(D6-endtime)*1440
#no "else statement" here!
)
)
)
So the first thing checked is if the cell C6 equals date1, which I think is a named range. If they are equal, then the whole equation resolves to the next line, 0
If they are not equal then D6-endtime is evaluated, if it is less than or equal to zero, then the equation resolves to zero.
If D6-endtime is greater than 0, then the next test is true and the whole equation resolves to (D6-endtime)*1440. There is no else in this last test because equation assumes D6-endtime will always be numeric.
Here's how I understand IF statements work in excel
=if(logical test,value if test true,value if test false)
For logical test, you have to use something that resolves to TRUE or FALSE, or you can specify TRUE or FALSE directly(but then you don't need an IF statement)
value if test true, if the test resolves to TRUE(like 1=1), then the cell will display this value, and supply this value to other functions
value if test false, if the test resolves to FALSE(like 1=0), then the cell will display this value, and supply this value to other functions.
You can omit value if TRUE/FALSE, and excel will return TRUE or FALSE after evaluation of the statement.
So I've been trying to figure out what is wrong with my if-condition, but I am getting nowhere. I am still new to R, so maybe I am not understanding some very basic concept here?
I have a dataframe (dc) to which I appended a column with logical "FALSE". Now I want to change each FALSE into a TRUE based on the values in two columns of dc (dc$Probe and dc$Resp) that I specified using regexpr().
What it does so far is that, for both if-conditions, it changes each FALSE into TRUE regardless of the values in column 5 of dc. When I run the if-conditions seperately, I can see that they seem to be working fine on the OR-part of the condition, meaning the code only generates TRUE when the strings in dc$Probe match one of the strings specified in the OR-part. However, the AND-part seems to be ignored? Thus, when I run the complete code, I get a column with only TRUE, which is not what I want.
Edit: I should get a TRUE only if the string in Probe ends in a certain pattern (as specified in either of the two if conditions I wrote) and if the corresponding value in Resp is a "100" for the patterns specified in my first condition or a "200" for the patterns specified in my second condition. Thus, for strings ending in (sg|s|w1|w3|s1|s2), Resp must be "100" to get a TRUE and for strings ending in (\d\dg|\d\d), Resp must be "200" to get a TRUE. All other cases should be FALSE. For example, if a string ends in s1 and the corresponding value in Resp is 200, the code should return FALSE.
Edit: Some example data:
>dc<-data.frame(Subject=rep("SN",6), item.c=(1:6), Stim=c("XYZc02s03","XYZc01s30","XYZc02s29", "XYZc01s38", "XYZc02s11", "XYZc06w21"), Probe=c("XYzf02s03","XYZf01s30g","XYZf02s29w1","XYZf01s38sg","XYZf02s11s","XYZv06w21s1"), Resp=c(200, 100, 100, 100, 100, 200))
This is my code:
>dc$Resp<-as.character(dc$Resp) #column 5 in dc
dc$Probe<-as.character(dc$Probe)
dc$correct_response <- FALSE
for (i in 1:nrow(dc)) {
if (regexpr("^.*sg$", dc$Probe[i])==1 || regexpr("^.*s$", dc$Probe[i])==1 || regexpr("^.*w1$", dc$Probe[i])==1 || regexpr("^.*w3$", dc$Probe[i])==1 || regexpr("^.*s1$", dc$Probe[i])==1 || regexpr("^.*s2$", dc$Probe[i])==1 && dc[i,5]=="100") {(dc$correct_response[i]<- TRUE)}
if (regexpr("^.*\\d\\dg$", dc$Probe[i])==1 || regexpr("^.*\\d\\d$", dc$Probe[i])==1 && dc[i,5]=="200") {(dc$correct_response[i]<- TRUE)}
}
Is there something wrong with the regular expressions I am using? I checked them with glob2rx() and it seems like they are ok...Is my use of "OR" (||) or/and "AND" (&&) incorrect? How do I implement the AND-part properly? I have also tried the following code for the AND-part, but it didn't change anything:
regexpr("200", dc$Resp[i])==1
I read the R-help on regular expressions and control flow, but I still don't see what I am doing wrong. Consulting other webpages on logical expressions did not help me either.
Please help!
Im wondering if it can all be reduced to the following:
dc<- read.table(header=T,text="Subject item.c Stim Probe Resp
SN 1 XYZc02s03 XYzf02s03 200
SN 2 XYZc01s30 XYZf01s30g 100
SN 3 XYZc02s29 XYZf02s29w1 100
SN 4 XYZc01s38 XYZf01s38sg 100
SN 5 XYZc02s11 XYZf02s11s 100
SN 6 XYZc06w21 XYZv06w21s1 200")
cond1<-regexpr("^.*(sg|s|w1|w3|s1|s2)$", dc$Probe)==1 & dc$Resp==100
cond2<-regexpr("^.*(\\d\\dg|\\d\\d)$", dc$Probe)==1 & dc$Resp==200
dc$correct_response<-cond1|cond2
For one thing, you are missing a logical operator between the 2nd and 3rd clauses of your first if statement.