C++ set a char value to a string? - c++

Question

This outputs upper case 'S' or 'P' regardless of the users choice to type lower case or not.
The output works when I cout with the other statements in my code
HOWEVER... I want to display STANDARD or PREMIUM in my final cout statement.
How can I change the value of the char to output either STANDARD or PREMIUM???
#include <string>
#include <iostream>
char meal;
cout << endl << "Meal type: standard or premium (S/P)? ";
cin >> meal;
meal = toupper(meal);
if (meal == 'S'){
meal = 'S';
}
else{
meal = 'P';
}
I've tried meal = 'Standard' and meal = 'Premium'
It doesn't work.

Answer 1

#include<iostream>
#include<string>
using namespace std;
int main(int argc, char* argv)
{
char meal = '\0';
cout << "Meal type: standard or premium (s/p)?" << endl;;
string mealLevel = "";
cin >> meal;
meal = toupper(meal);
if (meal == 'S'){
mealLevel = "Standard";
}
else{
mealLevel = "Premium";
}
cout << mealLevel << endl;
return 0;
}

Answer 2

declare extra variable string mealTitle;, then do if (meal == 'P') mealTitle = "Premium"
#include <string>
#include <cstdio>
#include <iostream>
using namespace std;
int main(void) {
string s = "Premium";
cout << s;
}

Answer 3

You cannot change the variable meal to be a string, because its type is a char. Just use another object with a different name:
std::string meal_type;
switch (meal) {
case 'P':
meal_type = "Premium";
break;
case 'S':
default:
meal_type = "Standard";
break;
}

Answer 4

#include <string>
#include <iostream>
std::string ask() {
while (true) {
char c;
std::cout << "\nMeal type: standard or premium (S/P)? ";
std::cout.flush();
if (!std::cin.get(c)) {
return ""; // error value
}
switch (c) {
case 'S':
case 's':
return "standard";
case 'P':
case 'p':
return "premium";
}
}
}
int main() {
std::string result = ask();
if (!result.empty()) {
std::cout << "\nYou asked for " << result << '\n';
} else {
std::cout << "\nYou didn't answer.\n";
}
return 0;
}