Same average function c++ [closed] - c++

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I'm trying to compare averages of an array and to detect if there is any similar averages,
for example if I have these averages 25,30,70,30,60 so the function should return true because 30 is twice there ,but it seems what I'm doing is wrong
bool sameAverage(Student Array[],int size)
{
bool isSame=false;
for (int i=0;i<size;i++)
{
for (int j=0;j<size;j++)
{
if (Array[i].getAverageGrade==Array[j].getAverageGrade)
isSame=true;
}
}
return isSame;
}
it is showing me a red line under the dot operator

Answer 1

Array[i].getAverageGrade is a function. You can compare that function to another function (like Array[j].getAverageGrade) but what you really want is to
call that function
compare the result to the result of calling the other function:
Array[i].getAverageGrade() == Array[j].getAverageGrade()
BTW: Please keep in mind what others have told you about comparing double values.

Answer 2

What I understand is that, you are looking for duplicates in the array.
First sort your array.
Then, Use a single loop to iterate through the array. Two loops are not needed.
bool sameAverage(Student Array[],int size)
{
for(int i = 0; i < size - 1; i++) {
//Use your favorite way to compare floating point numbers for equality
if ((Array[i].getAverageGrade() - Array[i + 1].getAverageGrade()) < 0.0001) {
return true;
}
}
return false;
}