Read a file in django and find string in file - django

i am a new to django, and i'm trying to execute a django code in an html template, but it is showing the same error and i dont know how to make it work. I am trying to read some files and find the one that contains the string. This is the code in the template:
{% if documents %}
<ul>
{% for document in documents %}
{% if 'TheString' in open('document.docfile.url').read() %}
<li>{{ document.docfile.name }}</li>
{% else %}
<li></li>
{% endif %}
{% endfor %}
</ul>
{% else %}
<p>No documents available.</p>
{% endif %}
The error is the following:
TemplateSyntaxError at /subir/
Could not parse the remainder: '('document.docfile.url').read()' from 'open('document.docfile.url').read()'
What could it be, or am i doing it wrong? Thanks in advanced.

Your problem is you are trying to use Python code in the template, like your open() call.
Django templates don't work like that - you can only use a very limited set of syntax, and the syntax is not the same as Python.
Everything inside {{ }} and {% %} needs to be special Django template syntax, not Python code.
See the Django Template language documentation for the full details.

You can't use code like this in a template directly see the documentation for available template tags and filters. From what I can tell by the code you have posted in your view.py you'll need something like this:
docs=[]
for document in documents:
if 'TheString' in open('/path/to/document').read():
docs.append(document)
after passing docs to the template you could do this in the template:
{% for doc in docs %}
<li>{{ document.docfile.name }}</li>
{% empty %}
<p>No documents available.</p>
{% endfor %}
I'd need to look at what you are passing from the view to be sure of this, but I'd gladly assist in further help with further information if this doesn't help.

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Does django accept Jinja loop together with condintion in one line?

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However when trying to use similar approach in Django template it gives me error:
TemplateSyntaxError at /childminder/task-list/
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Point is that I list of links in a list of forms (so those links belongs to specific form only), and there's status and url in that list of links. IF all link statuses didn't match form statuses THEN search for link status Other and print it's link.
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Django check form error code in template

I am using Django 1.10 and trying to find a way to check the error code of a form inside of the template. So I tried a few things, like errors.as_data or errors.as_json, but I was unable to parse the different values (except by using javascript). Could it be something like this ?
<p>{% for key, value in form.errors.items %}
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But I don't know how to get this error code. Any suggestion ?
PS : I know that a solution would be to do it inside of the view, but since I am using a django already-made one, I would prefer not to do it.
The dictionary form.errors does not contain the ValidationError instances. You need to use the as_data method.
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{% for key, key_errors in form.errors.as_data.items %}
{{ key }}
{% for error in key_errors %}
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There's also other way to check for the error code.
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<input name="input_name" />
<div>{{ input_desc_html }}</div>
form.html
{% with input_name="test" input_desc_html=... %}
... should read {% for this in that %} {{ this }} {% endfor %}
{% include 'field.html' %}
{% endwith %}
Obvioulsy there is something missing at ... and I do not know how to advance from here. Is this approach even possible and if yes, how?
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I have a template tag located in catalog/templatetags/catalog_tags.py, which looks like this:
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I have a catalog.html which has {% load catalog_tags %}, to load that tag, and is followed by an inclusion tag for my navigation, {% include "tags/navigation.html" %}.
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.....
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Django template - set variable in for loop

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http://pastie.org/3530409
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Thanks a lot.
Instead of having to set the variable, you could just do:
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