Edit css files from django admin - django

My client wants to edit the css files of the site from django admin.
Is there any way to do it ? .
Basically what they want is,to be able to change the color,font etc of the data in the front end from django admin interface.

The best thing would be to just let him edit the css file itself. CSS is, in essence, a rather flexible tool, so writing a way to manage it is rather tough (and really, overkill). It's already easy to pick-up, and any nice editor like sublime or notepad++ would probably be easier and more natural than whatever you'll build using the admin site. Also, by building a simple way to control css, your client will probably start asking for more and more flexibility until you find yourself building an entire cms (trust me, I've been there myself).
What's more, your client probably only wants to manage small aspects or details of the site. Recently I had a project where I allowed my users to style their display of my application. The way I did it was to create a UserDesign model which extended the base User model and kept very specific css data. Something like this:
class UserDesign(models.Model):
user = models.OneToOneField(User)
background_color = models.CharField(max_length=15)
font_color = models.CharField(max_length=20, choices=COLORS)
theme = models.CharField(max_length=20, choices=THEMES)
Meaning, they didn't control the entirety of the css, but they did get to choose the background color and some other information. It's a very neat addition to any website. However, if you are bent over doing it the hard way, I'd do something like this:
class Selector(models.Model):
name = models.CharField(max_length=30)
def get_template(self):
attrs = [a.join() for a in self.attr_set.all()]
return """ %s { %s } """ % ( self.name, ';'.join(attrs) )
class Attr(models.Model):
key = models.CharField(max_length=30)
value = models.CharField(max_length=30)
selector = models.ForeignKey(Selector)
def join(self):
return ': '.join(self.key, self.value)
I chose 30 as the max_length completely arbitrarily (you might need it longer), and you can use a TabularInline to make each selector easy to manage. Then you can easily use different css definitions inside your templates themselves:
<style>
{% for selector in selectors %}
{{ selector.get_template }}
{% endfor %}
</style>
Of course, the Selector model would probably need another field called 'template' or 'view' or something, to link it to a certain html file, though at this point it quickly start devolving into building your own cms (which, as mentioned before, is quite a headache that not wanting to edit a text file just doesn't justify)
A third viable option is to create a view with a code-editor, and just let your client edit his css through the web page. There's more than enough client-side plugins out there, like ace or codemirror (and of course, limit that view to administrators, which very simple to do).

Related

Illustrated texts in Django model

I am trying to make one Blog using Django 2.0 and I have already created a primitive one. It has a Post model which is as follows:
class Post(models.Model):
PriKey = models.CharField(max_length=255,primary_key=True)
Heading = models.CharField(max_length=100)
DateOfPost = models.DateField(default=datetime.date.today())
Content = models.TextField()
As it can be seen, the content area is only textual and as of now, I can't add any special style or pictures inside my content.
I thought of using HTML tags inside the text content but they are appearing unchanged when the web page is rendered.
So my question is, is there any way of storing pictures along with the text in the content field of the Post model? I want to make something like this
Is there any way of showing the pictures in their respective positions using Django model? If no, is there any other way of doing this?
Also, is there any way of storing HTML codes inside django models and render them as it is when the website is run?
You can store html tags inside the field.
while rendering, to template mark it as safe
{{ post.content|safe }}
This will render all the html tags.
But this is not a good way as it makes you vullerable to cross site scripting attacks
A better method is to use something like a ckeditor
It provides a RichTextField and RichTextUploading Field and using this you can upload pictures, videos, code snippets, style your text and a lot more inside one field.
There are many other optons, but I prefer ckeditor
Ckeditor is a cross platform editor, django-ckeditor is a library containing django implementation of ckeditor which gives you full backend and frontend combined
ckeditor
django-ckeditor
django-pagedown A django app that allows the easy addition of Stack Overflow's "PageDown" markdown editor to a django form field, whether in a custom app or the Django Admin
I think you should give it a try
Cheers :)

adding line breaks and headers in django's admin interface

EDIT: If you are going to give a downvote, at least explain why -.-
Also, read comments if my post is still unclear. I tried to explain it a bit more in the comments but if it is still unclear about what I'm saying, let me know and I will take printscreens and explain using images.
I have created a model like so
class Post(models.Model):
title_of_post = models.CharField(max_length=100)
actual_post = models.TextField()
and I put this model in the admin interface and enabled the admin interface. Now, when I go to 127.0.0.1/admin/ and sign in, I can add this model. The posts created in the Post model can be seen on the homepage (127.0.0.1) so say my "title_of_post" is "title" and my "actual_post" is "the actual post", if I go to 127.0.0.1 I can see both the title and actual post on the homepage. The problem is, when I am in the admin interface and in the actual_post text box / TextField section, suppose I write this.
Something.
else
It would not recognize that I pushed the enter key after the period. I tried
Something. <br>
else
but that also didn't work. It does not go on a new line after the period. Is there any way to go to the next line when inputting information from the text box / TextField in the django admin interface? Is there any way to put headers from the admin interface, not from the template? Essentially, I want to be able to create this html from the admin interface.
<h1>Something.</h1> <br>
else
in order to show html inside a property, you need to place like this in your template:
{{ post.actual_post|safe }}
the safe template filter its good for not escaping html tags inside your template.
And this will print as:
Something
else
intead of:
Something <br /> else

Django app to "switch on" other apps for specyfic user

I am new to django and I really like its modular construction so I decided to take advantage of it and put all the separated functionalities each in different app.
Now I need a way to switch on and off this apps by both user and admin.
The user options panel would look like this:
[ ] blog
---------------------
[ ] tagging [BUY]
After checking "blog" option user would get the blog in his profile and after buying and checking "tagging" he would get tagging for the blog.
The admin panel would have an ability to show or hide an app from user panel.
I wonder if:
there is an app which would help me switch on and off an app for specyfic user
and if not -
what would be a proper "architecture" for such django app?
Can it be done dynamically in middleware or should it be done during login (check available apps from database, switch them on, redirect to user home page)?
Any advices for such a task?
Thanks,
Robert
I haven't heard of any such app… But I don't expect it would be too hard to build.
If I were doing it, I would put a permissions check in the entry points to each app. For example:
check_app_permission = lambda request: permissions.check_app_permission("blog", request)
def view_blog(request, …):
check_app_permission(request)
…
(it might even be possible to do some magic and inject this check at the urls.py level…)
Additionally, I would create a has_app_permission template tag:
<div id="sidebar">
{% if has_app_permission "blog" %}
{% include "blog/sidebar_recent_posts.html" %}
{% endif %}
</div>
Or similar.
Finally, there are approximately a million ways you could implement the permission system… And without more information I wouldn't be able to comment. The simplest, though, would be something like this:
class App(Model):
name = CharField(…)
class AppPermission(object):
app = ForeignKey(App)
user = ForiegnKey(User)
def user_has_permission(user, app_name):
return AppPermission.objects.filter(app__name=app_name, user=user).exists()
I would avoid trying to do this with middleware, because if I understand the problem correctly, I expect you will (or, at least, I expect I would) end up spending a bunch of time building a generic framework which, in the end, would just have checks similar to those above.
Does that help? Is there something I can clarify?

is there a way to use django generic views and some smart urlpatterns for quick ordering/sorting of queries?

let's assume I have a django model like this:
class Event(CommonSettings) :
author = models.ForeignKey(User)
timestamp = models.DateTimeField(auto_now_add=True)
event_type = models.ForeignKey(Event_Type, verbose_name="Event type")
text_field = models.TextField()
flag_box = models.BooleanField()
time = models.TimeField()
date = models.DateField()
project = models.ForeignKey(Project)
now, by default, I have a view where I sort all events by time & date:
event_list = Event.objects.filter().order_by('-date', '-time')
however, maybe the user wants to sort the events by time only, or by the date, or maybe in ascending order instead of descending. I know that I can create urlpatterns that match all these cases and then pass on the these options to my view, however I feel like I'm reinventing the wheel here. the django admin site can do all of this out of the box.
So here's my question: is there a clever, easy way of getting this done in a generic way, or do I have to hard code this for my models / views / templates?
and yes, I did find solutions like this (https://gist.github.com/386835) but this means you use three different projects to achieve one thing - this seems to be a too complicated solution for such a simple thing.
EDIT1:
how do I have to change the template so that I can combine multiple filters? Right now I have
Desc
Asc
but I want to allow the user to also change number of entries that get displayed. So I have:
order by date
order by name
This works all fine, but if I click on 'order by date' and then I click on 'Asc', then my previously selected order disappears. That's not what I want. I want the user to be able to combine some options but not others.
EDIT2:
unfortunately your solution doesn't work with
from django.views.generic.list_detail import object_list
and it's
paginate_by
option.
I tried:
prev
{% trans "next" %}
but the links then just don't work (nothing happens). maybe you need to do something special with "object_list"?
I don't think it's as much work as you're making it out to be - you can use variables instead of explicitly creating separate url patterns. If you look at how the django admin handles it, they tack on request variables to the url like ?ot=asc&o=2 This corresponds to sort in ascending order in by the 2nd column. Of course, if you designing a particular page, you might as well use more readable naming. So instead of numbering the categories, i'd do ?sort=desc&order_by=date and then put a regular expression in the view to match the different possibilities. Something like:
order = re.match(r"(?:date|time|name)$", request.GET['order_by'])
if request.GET['sort'] == 'desc':
order = '-' + order
results = Event.objects.filter().order_by(order)
You could instead use the regexp as a url pattern matcher as you suggested, but it's more common to let the url itself represent which part of the site you're at (i.e. website.com/events/) and the url request variables represent how that content is being displayed (i.e. ?order_by=date&sort=desc).
Hope that helps!
EDIT: For the second part of your question, use Django's templating system (which reads variables) instead of just html. There are several ways I can think of to do this, depending on personal preference and how exactly you want the UI to function (i.e. page loads with new variables anytime the user chooses a filter, or the user chooses all filter options in a form and then submits it so the page only has to reload once, etc). In this case, you could just do:
Ascending
Descending
Name
Date
Then in the view make sure your render_to_response arguments include a dictionary that looks like: {'order': request.GET['order_by'], 'sort': request.GET['sort_by'], }
Unfortunately, (and someone please correct me if I'm wrong) I don't think there's a template tag to generate a url with request.GET parameters - the url tag {% url name_of_view order_by=name sort_by=desc %} would generate "path/to/name_of_view/name/desc/", but I don't think there's a tag to generate "path/to/name_of_view?order_by=name&sort_by=desc". It would be pretty easy to write a custom tag for this though (I wouldn't be surprised if there's already one on django-snippets or something, although I just did a quick google search and didn't find anything).

Questions about Django's internationalization framework

When developing apps for use in multiple languages, I see a real benefit to using localization over trying to build some ad hoc localization library specific to your application. I'm working on a website that will have 16 languages, and each language will have different images in various places, as well as full text translations for each page's content, each language residing on a different URL (www.example.com/en/, etc). Django's internationalization framework seems very magical, and tricky. My idea was to do something basic, like:
class Language(models.Model):
name = models.CharField(max_length=50)
code = models.CharField(max_length=2) # (e.g. "FR")
class ContentSection(models.Model):
page = models.ForeignKey('mysite.Page')
name = models.CharField(max_length=50) # (e.g. ("main body text")
content = models.TextField(max_length=5000)
class Meta:
unique_together = (('name', 'page'),)
class ContentTranslation(models.Model):
content_section = models.ForeignKey(ContentSection)
language = models.ForeignKey(Language)
content = models.TextField(max_length=5000)
class Meta:
unique_together = (('content_section', 'language'),)
I would use middleware to set the current language based on the first URL segment, and in my views I would pull the content for a given page in a view with something like:
# In views.view_page
left_content = ContentSection.objects.filter(page=current_page, name='left column text')
if not request.language.code == 'EN':
left_content = ContentTranslation.objects.get(content_section=left_content, language=request.language)
Of course, in production I'd probably create a template tag that gets a content (with the correct language) by name, instead of explicitly pulling each content area in the view.
Does this seem so ridiculous to do this instead of using i18n? Am I missing the bigger picture with internationalization?
(keep in mind: the site will be browsed by users in other languages, but all admin stuff, including inserting translations, will be done in the US)
This is a sound approach if what you need is to be able to have your users change the content in all the different languages. You also get to create a nice interface for everything.
However, you are not using the Django i18n framework. So what is your question? :)
I have tried both using the i18n framework for content and using your approach. Storing translations in po-files is great for "system" text as you can use all your tools, like version control, bug tracking, etc. However, it is a pain in the ass if you have users who actually want to change the content all the time, which I believe is the case for almost any web site of some size.
As a side note, including the language in the URL makes it easier to cache the pages on the front end varnish proxy that everybody should be using, so +1 for that decision.