What's the syntax for 'fixed' option, in Doctrine XML schema files? - doctrine-orm

This is very similar to another question concerning how to switch a type from 'varchar' to 'char'. However, I'm having trouble getting my XML config to work.
One of the fields that app/console doctrine:schema:update --dump-sql is saying differs from my database is this:
ALTER TABLE user CHANGE password password VARCHAR(32) NOT NULL;
I'm pretty certain that that's because my database definition for that field is correctly set to char(32), but Doctrine isn't expecting the field to be fixed.
To poke Doctrine into knowing it's fixed, I've added the following XML:
<field name="password" type="string" column="password" length="32" nullable="false">
<options>
<option name="fixed" value="true" />
</options>
</field>
Is this not correct?
Some bonus information, if it matters: I'm using MySQL.

Just stumbled upon on your thread.
The syntax in your original post was incorrect. I wanted to leave my comment just in-case someone else happens to find this thread. While the accepted answer works, the 'fixed option' in the Doctrine schema works too.
With the code snipet above, it should look like this:
<field name="password" type="string" column="password" length="32" nullable="false">
<options>
<option name="fixed">true</option>
</options>
</field>
The attribute value is not valid.
Hope this helps whoever ventures on this thread!

I've stumbled upon a reasonable enough answer, but it's definitely a bit of a hack.
<field name="password" type="string" column="password" length="32" nullable="false" column-definition="CHAR(32) NOT NULL" />
length and nullable are actually ignored here, but I figured I'd leave them in the be verbose about what I want. The column-definition is actually what's forcing the fixed length CHAR.
Unfortunately, this attribute doesn't seem to get taken into account when doing the schema diff, so it'll always say there's a difference on that field.

Related

TFS 2013 Bug Work Item Template: Hide and Un-Hide Fields Based on Another Field's Value for Additional Input Parameters

I am in the process of updating my Bug template in TFS 2013 via the Process Editor tool in Visual Studio.
I'm attempting to only display an additional field when a specific choice is selected from one of the drop-down menus. We require individuals filing bugs to select the environment in which the bug was found, i.e., Development, Test, Staging, Production. I want an additional string field to display when "Production" is selected from the Environment drop-down menu. I also want this field to be required when "Production" is selected before the item can be saved.
I'm sure this is easy to do, but, I just can't figure it out.
Any help would be fantastic, thank you!
You can have the XML of Environment field looks like:
<FieldDefinition name="EnvironmentCustom" refname="env.field" type="String">
<ALLOWEDVALUES expanditems="true">
<LISTITEM value="Development" />
<LISTITEM value="Test" />
<LISTITEM value="Staging" />
<LISTITEM value="Production" />
</ALLOWEDVALUES>
</FieldDefinition>
And make the XML of additional field looks like:
<FieldDefinition name="VarCustom" refname="var.field" type="String">
<WHEN field="env.field" value="Production">
<REQUIRED />
<ALLOWEDVALUES expanditems="true">
<LISTITEM value="good" />
<LISTITEM value="bad" />
</ALLOWEDVALUES>
</WHEN>
</FieldDefinition>
In this way, you'll see Environment field has a drop down with values "Development", "Test", "Staging", "Production", and additional field has a drop down with values "good", "bad". Once you select "Production" in Environment field, the additional field will become Required, you'll have to select a vlue for additional field before saving this work item type.
Adding:
If you don't want to a drop down under the additional field, you can remove the ALLOWEDVALUES rule, then you can type any string in it. The XML looks like:
<FieldDefinition name="VarCustom" refname="var.field" type="String">
<WHEN field="env.field" value="Production">
<REQUIRED />
</WHEN>
</FieldDefinition>
It's not able to hide/un-hide VarCustom field by using Rules, you need to customize your own work item control to achieve your requirement. You can check the links and examples about custom work item control at website below:
https://witcustomcontrols.codeplex.com/

search user query pre-processing to search in specific field in solr

i am new to solr and django,i am working on implimenting search on a party hall venue search website though i have not worked on the website part just implimenting solr for the search i have indexed party hall venue information in solr with following fields
<field name="id" type="int" indexed="true" stored="true" required="true" multiValued="false" />
<field name="title" type="text_general" indexed="true" stored="true" required="true" />
<field name="slug" type="text_general" indexed="true" stored="true" required="true" />
<field name="description" type="text_general" indexed="true" stored="true"/>
<field name="location" type="text_general" indexed="true" stored="true"/>
<field name="city" type="text_general" indexed="true" stored="true"/>
<field name="area" type="text_general" indexed="true" stored="true"/>
<field name="featured" type="boolean" indexed="true" stored="true" />
<field name="facilities" type="text_general" indexed="true" stored="true" multiValued="true" />
<field name="type_of_venue" type="text_general" indexed="true" stored="true" multiValued="true" />...
there are many other fields which are used only for display of data on results page but only these fields are used to query data
on my website i have a search bar where user can enter any search term and then i search it against title,description,location,facilities
now i did enough reading on how to break down the search terms entered by user to identify which field to find it in so that i can have different template view to show the found matches but couldn't find any technique that will work with solr.
please can anyone suggest me any pre search text processing techniques to make it simpler to generate query to search in solr
thanks in advance
If you index your data carefully (read on examples) there is an easy (but not the best!) way to do this.
Lets say here are your party hall documents
1) party hall - "abc party hall", location - "san jose"
2) party hall - "xyz party hall", location - "san francisco"
3) party hall - "pqr party hall", location - "paris"
4) party hall - "best party hall", location - "san jose"
Lets say your user types "best party hall in san jose" in search bar, ideally you should return #4, 1, right?
You can certainly pre-process your query (complex NLP) to extract potential location data to be used for location field in your query.
For a moment lets take brute-force method here, lets use boolean query and search your full query with all important fields as-is
party_hall: "best party hall in san jose" AND location: "best party hall in san jose"
If you've indexed your data properly (as given in example documents above) you will get best results as expected.
party hall query will not have "san jose" so it will consider document with "best party hall", similarly location field will filter document with "san jose" so technically you should get your best matched documents #4,1. You can use "OR" instead of "AND" but you will get more matched documents (but rank sorting will still be accurate and expected)
Try it with your use case and see if it helps!
p.s - this will work if you use any tokenizer based analyzer like StandardAnalyzer (will not work for KeywordAnalyzer)

Solr : importing dynamic field names from XML with DIH and xpath

I'm indexing data from a XML file, with many fields like these declared in DataImportHandler's dataconfig.xml :
<field column="pos_A" xpath="/positions/pos_A/#pos" />
<field column="pos_B" xpath="/positions/pos_B/#pos" />
<field column="pos_C" xpath="/positions/pos_C/#pos" />
...
And one matching dynamicField declaration in schema.xml :
<dynamicField name="pos_*" type="sint" indexed="true" stored="true" />
I'm wondering if it's possible to use a transformer to dynamically generate the field names in dataconfig.xml, and have a single line, kinda like :
<field column="pos_{$1}" xpath="/positions/pos_(*)/#pos" />
(pardon my xpath and regex syntax :)
https://issues.apache.org/jira/browse/SOLR-3251 The latest release claims that you can dynamically add fields to the schema. I tried to find documentation for the public interface, but not much luck so far.
>
SOLR-4658: In preparation for REST API requests that can modify the schema,
126 a "managed schema" is introduced.
127 Add '<schemaFactory class="ManagedSchemaFactory" mutable="true"/>' to solrconfig.xml
128 in order to use it, and to enable schema modifications via REST API requests.
129 (Steve Rowe, Robert Muir)

Sharepoint Deploy new Column to list

I'm fairly new to SharePoint 2010, I've had some experience with 2007 but only debugging and fixing some small bug.
Assuming that i create a new solution for SP 2010 in VS2010 and i add a feature to create some list definitions and also some list instances of those list definition templates. These are all declared through Schema.xml =>
I deploy successfully and add a few items to my new lists.
Now i want to add a few extra columns (fields) to my lists, how will i deploy them?
I don't want to create them in code, i would like to have a up to date solution that with every new developer a simple deployment would create an up and running Dev environment.
What is the correct way to do the deployment in this case?
If you have the schema.xml file defined for the list, then you really want to add your new columns using the collection within the list definition. You also want to be sure your list is defined by a content type, allowing for reuse. So within your schema.xml file, it would look something like this:
<List xmlns:ows="Microsoft SharePoint" Title="Test List" FolderCreation="FALSE" Direction="$Resources:Direction;" Url="Lists/Test-List" BaseType="0" xmlns="http://schemas.microsoft.com/sharepoint/">
<MetaData>
<ContentTypes>
<ContentType ID="0x010068a2e063a1a74913a37ecdb61ab2c721" Name="Test" Group="Custom Content Types" Description="Test Description" Inherits="TRUE" Version="0">
<FieldRefs>
<FieldRef ID="{c2f80e7d-666e-4273-8b58-d5c8a13a9d6a}" Name="Col1" ShowInNewForm="TRUE" Required="TRUE" ShowInEditForm="TRUE"/>
<FieldRef ID="{a84d620a-d42d-455c-8ef8-7e9f1d443250}" Name="Col2" Required="TRUE" ShowInNewForm="TRUE" ShowInEditForm="TRUE"/>
<!-- Your new field refs here here -->
</FieldRefs>
</ContentType>
</ContentTypes>
<Fields>
<Field ID="{c2f80e7d-666e-4273-8b58-d5c8a13a9d6a}" Type="Text" AllowDeletion="FALSE" Description="Key" AllowDuplicateValues="FALSE" EnforceUniqueValues="TRUE" Indexed="TRUE" Name="Col1" DisplayName="Col1" Group="Custom Columns" />
<Field ID="{a84d620a-d42d-455c-8ef8-7e9f1d443250}" Type="Text" AllowDeletion="FALSE" Name="Col2" DisplayName="Col2" Group="Custom Columns" />
<!-- Your new fields here -->
</Fields>
...
</MetaData>
</List>
Don't forget to change your View as well!

SharePoint 2010 List Schema.XML not working as imagined

I am created an External List in VS and in the schema.XML file I have a few fields that I would like to change their display name, and format some dates.
We created an External List in SP, exported the wsp, and grabbed the list components of the site and added it to our project.
Here is an example of what I thought would work, but it does not.
<Field DisplayName="Date Closed" Format="DateOnly" Hidden="FALSE" Name="DateClosed" SourceID="http://schemas.microsoft.com/sharepoint/v3" StaticName="DateClosed" Type="DateTime" />
<Field DisplayName="Closed By" Hidden="FALSE" Name="ClosedBy" SourceID="http://schemas.microsoft.com/sharepoint/v3" StaticName="ClosedBy" Type="Text" />
We have a filter setup in the section which is working, so I know that the file is being used. Any insight as to why the changes I made to the field are not taking effect?