I'd like to validate an email address input using the following regex:
^[_A-Za-z0-9-\+]+(\.[_A-Za-z0-9-]+)*#[A-Za-z0-9-]+(\.[A-Za-z0-9]+)*(\.[A-Za-z]{2,})$
However, it doesn't match an email in this format test#test.test-test.fr while it should be matched.
Could someone can get me a hint, where the problem is?
This should work :
^[_A-Za-z0-9-\+]+(\.[_A-Za-z0-9-]+)*#[A-Za-z0-9-]+(\.[A-Za-z0-9-]+)*(\.[A-Za-z]{2,})$
The problem was the dash in the second part of the domain, it didn't matched the original pattern.
Related
I am validating a domain field in the form. I am using Validators.pattern(this.domainPattern) for doing that.
I am using below pattern:
public domainPattern: string = "^(?:[a-z0-9][a-z0-9-]{0,61}[a-z0-9]\.)+[a-z0-9][a-z0-9-]{0,61}[a-z0-9]$";
It works fine for many cases. But when there is a white space in domain it is not triggering pattern error. What I am missing?
Quick help will be highly appreciated.
Thanks.
Try this pattern:
(?(?<= )(?=[^ ])|^)(?:[a-z0-9][a-z0-9-]{0,61}[a-z0-9]\.)+[a-z0-9][a-z0-9-]{0,61}[a-z0-9]
I just added (?(?<= )(?=[^ ])|^), conditional which checks:
first it checks condition (?<= ) if what is preceeding is space, if it is, then check if what's after is not a space with (?=[^ ]), if the condition fails, then check if we are at the beginning of a string with ^.
Demo
UPDATE
OP said:
I want user to enter just one valid domain name. If user enters "google.com google.com" it should be treated as invalid
Then you could use this pattern
^(?!.* .*)(?:[a-z0-9][a-z0-9-]{0,61}[a-z0-9]\.)+[a-z0-9][a-z0-9-]{0,61}[a-z0-9]$
Just added (?!.* .*) which checks if there's sapce in following line, if it is, then it won't match anything, as space indicated multiple domain names.
Another demo
I'm trying to regex a group called reason, i have got very close but can't quite figure out the last part. I want to regex everything between Reason: up to and not including the first bracket in (winRc=999)
The string that is being extracted is below.
Reason: The user name or password is incorrect. (winRc=999)
I wish to have an expression that shows:
A Full Match of "Reason: The user name or password is incorrect."
A Group 'Reason' Match of "The user name or password is incorrect."
you can use something similar to what #CodeManiac was mentioning above
/Reason: ([^(]*)/
A demo from regex101
https://regex101.com/r/J2ddFQ/1
The takes advantage of using a negative character class, very powerful.
I have a response like below
{"id":9,"announcementName":"Test","announcementText":"<p>TestAssertion</p>\n","effectiveStartDate":"03/01/2016","effectiveEndDate":"03/02/2016","updatedDate":"02/29/2016","status":"Active","moduleName":"Individual Portal"}
{"id":103,"announcementName":"d3mgcwtqhdu8003","announcementText":"<p>This announcement is a test announcement”,"effectiveStartDate":"03/01/2016","effectiveEndDate":"03/02/2016","updatedDate":"02/29/2016","status":"Active","moduleName":"Individual Portal"}
{"id":113,"announcementName":"asdfrtwju3f5gh7f21","announcementText":"<p>This announcement is a test announcement”,"effectiveStartDate":"03/02/2016","effectiveEndDate":"03/03/2016","updatedDate":"02/29/2016","status":"InActive","moduleName":"Individual Portal"}
I am trying get the value of id (103) of announcementName d3mgcwtqhdu8003.
I am using below regEx pattern to get the id
"id":(.*?),"announcementName":"${announcementName}","announcementText":"
But it is matching everything from the first id to the announcementName. and returning
9,"announcementName":"Test","announcementText":"<p>TestAssertion</p>\n","effectiveStartDate":"03/01/2016","effectiveEndDate":"03/02/2016","updatedDate":"02/29/2016","status":"Active","moduleName":"Individual Portal"}
{"id":103,"announcementName":"d3mgcwtqhdu8003","announcementText":
But I want to match only from the id just before the required announcementName.
How can I do this in RegEx . Can someone please help me on this ?
As an answer here as well. Either use appropriate JSON functions, if not, a simple regex like:
"id":(\d+)
will probably do as the IDs are numeric.
I found a lot of Regex email validation in SO but I did not find any that will accept an empty string. Is this possible through Regex only? Accepting either empty string or email only? I want to have this on Regex only.
This regex pattern will match an empty string:
^$
And this will match (crudely) an email or an empty string:
(^$|^.*#.*\..*$)
matching empty string or email
(^$|^[a-zA-Z0-9._%+-]+#[a-zA-Z0-9.-]+\.(?:[a-zA-Z]{2}|com|org|net|edu|gov|mil|biz|info|mobi|name|aero|asia|jobs|museum)$)
matching empty string or email but also matching any amount of whitespace
(^\s*$|^[a-zA-Z0-9._%+-]+#[a-zA-Z0-9.-]+\.(?:[a-zA-Z]{2}|com|org|net|edu|gov|mil|biz|info|mobi|name|aero|asia|jobs|museum)$)
see more about the email matching regex itself:
http://www.regular-expressions.info/email.html
The answers above work ($ for empty), but I just tried this and it also works to just leave empty like so:
/\A(INTENSE_EMAIL_REGEX|)\z/i
Same thing in reverse order
/\A(|INTENSE_EMAIL_REGEX)\z/i
this will solve, it will accept empty string or exact an email id
"^$|^([\w\.\-]+)#([\w\-]+)((\.(\w){2,3})+)$"
I prefer /^\s+$|^$/gi to match empty and empty spaces.
console.log(" ".match(/^\s+$|^$/gi));
console.log("".match(/^\s+$|^$/gi));
If you need to cover any length of empty spaces then you may want to use following regex:
"^\s*$"
If you are using it within rails - activerecord validation you can set
allow_blank: true
As:
validates :email, allow_blank: true, format: { with: EMAIL_REGEX }
Don't match an email with a regex. It's extremely ugly and long and complicated and your regex parser probably can't handle it anyway. Try to find a library routine for matching them. If you only want to solve the practical problem of matching an email address (that is, if you want wrong code that happens to (usually) work), use the regular-expressions.info link someone else submitted.
As for the empty string, ^$ is mentioned by multiple people and will work fine.
I was using a regular expression for email formats which I thought was ok but the customer is complaining that the expression is too strict. So they have come back with the following requirement:
The email must contain an "#" symbol and end with either .xx or .xxx ie.(.nl or .com). They are happy with this to pass validation. I have started the expression to see if the string contains an "#" symbol as below
^(?=.*[#])
this seems to work but how do I add the last requirement (must end with .xx or .xxx)?
A regex simply enforcing your two requirements is:
^.+#.+\.[a-zA-Z]{2,3}$
However, there are email validation libraries for most languages that will generally work better than a regex.
I always use this for emails
^([a-zA-Z0-9_\-\.]+)#((\[[0-9]{1,3}" +
#"\.[0-9]{1,3}\.[0-9]{1,3}\.)|(([a-zA-Z0-9\-]+\" +
#".)+))([a-zA-Z]{2,4}|[0-9]{1,3})(\]?)$
Try http://www.ultrapico.com/Expresso.htm as well!
It is not possible to validate every E-Mail Adress with RegEx but for your requirements this simple regex works. It is neither complete nor does it in any way check for errors but it exactly meets the specs:
[^#]+#.+\.\w{2,3}$
Explanation:
[^#]+: Match one or more characters that are not #
#: Match the #
.+: Match one or more of any character
\.: Match a .
\w{2,3}: Match 2 or 3 word-characters (a-zA-Z)
$: End of string
Try this :
([\w-\.]+)#((?:[\w]+\.)+)([a-zA-Z]{2,4})\be(\w*)s\b
A good tool to test our regular expression :
http://gskinner.com/RegExr/
You could use
[#].+\.[a-z0-9]{2,3}$
This should work:
^[^#\r\n\s]+[^.#]#[^.#][^#\r\n\s]+\.(\w){2,}$
I tested it against these invalid emails:
#exampleexample#domaincom.com
example#domaincom
exampledomain.com
exampledomain#.com
exampledomain.#com
example.domain#.#com
e.x+a.1m.5e#em.a.i.l.c.o
some-user#internal-email.company.c
some-user#internal-ema#il.company.co
some-user##internal-email.company.co
#test.com
test#asdaf
test#.com
test.#com.co
And these valid emails:
example#domain.com
e.x+a.1m.5e#em.a.i.l.c.om
some-user#internal-email.company.co
edit
This one appears to validate all of the addresses from that wikipedia page, though it probably allows some invalid emails as well. The parenthesis will split it into everything before and after the #:
^([^\r\n]+)#([^\r\n]+\.?\w{2,})$
niceandsimple#example.com
very.common#example.com
a.little.lengthy.but.fine#dept.example.com
disposable.style.email.with+symbol#example.com
other.email-with-dash#example.com
user#[IPv6:2001:db8:1ff::a0b:dbd0]
"much.more unusual"#example.com
"very.unusual.#.unusual.com"#example.com
"very.(),:;<>[]\".VERY.\"very#\\ \"very\".unusual"#strange.example.com
postbox#com
admin#mailserver1
!#$%&'*+-/=?^_`{}|~#example.org
"()<>[]:,;#\\\"!#$%&'*+-/=?^_`{}| ~.a"#example.org
" "#example.org
üñîçøðé#example.com
üñîçøðé#üñîçøðé.com