C++ char vector addition - c++

Question

This is a part of a program that I am writing to compute the addition of two integers as strings. (Writing my own bigInt class).
There appears to be a problem when I am adding the two integers together. Because they are both in vectors of char type, I had to add a '0' to each element of the vector before concatenating it into a string.
However, the results are still not what I am expecting:
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main()
{
string const Number = "1000";
string const Number2 = "1000";
vector<char> reverse;
vector<char> reverse2;
//cout << (rostrNumber[1] - '0') << endl;
cout << "Original Number: " << Number << endl;
reverse.clear();
for (int i = Number.size() - 1; i >= 0; i--)
{
reverse.push_back(Number[i]);
}
cout << "Reversed: " << endl;
cout << reverse[0] << reverse[1] << reverse[2] << reverse[3] << endl;
cout << endl << endl;
reverse2.clear();
{
for (int i = Number2.size() - 1; i >= 0; i--)
{
reverse2.push_back(Number[i]);
}
}
cout << "Adding these two integers" << endl;
vector<char> const rcvN1 = reverse;
vector<char> const rcvN2 = reverse2;
vector<char> Results;
Results.clear();
//Local copies
vector<char> vN1 = rcvN1;
vector<char> vN2 = rcvN2;
int iSize1 = vN1.size();
int iSize2 = vN2.size();
int i, iSize = iSize2;
int iC = 0, iR;
for (i = 0; i<iSize; i++)
{
iR = vN1[i] + vN2[i] + iC;
if (iR > 9)
{
iR -= 10;
iC = 1;
}
else
iC = 0;
Results.push_back(iR);
cout << Results[0] << endl;
}
if (iC > 0)
Results.push_back(iC);
string ostr;
vector<char>::const_reverse_iterator rIter = Results.rbegin();
for (; rIter != Results.rend(); rIter++)
ostr += *rIter +'0';
cout << "Results: " << ostr << endl;
system("PAUSE");
return 0;
}