i want to transfer a file local to server machine.
import os
import paramiko
local_path = "/home/e100075/python/ss.txt"
remote_path = "/home/developers/screenshots/"
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect('hostname', username="username", password="password")
ssh_stdin, ssh_stdout, ssh_stderr = ssh.exec_command('ls /tmp')
print "output", ssh_stdout.read()
#Reading output of the executed command
error = ssh_stderr.read()
#Reading the error stream of the executed command
print "err", error, len(error)
#Transfering files to and from the remote machine
sftp = ssh.open_sftp()
sftp.get(remote_path, local_path)
sftp.put(local_path, remote_path)
sftp.close()
ssh.close()
After run the program. I got the errors below
Traceback (most recent call last):
File "file_copy.py", line 21, in <module>
sftp.get(remote_path, local_path)
File "/usr/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 606, in get
fr = self.file(remotepath, 'rb')
File "/usr/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 245, in open
t, msg = self._request(CMD_OPEN, filename, imode, attrblock)
File "/usr/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 635, in _request
return self._read_response(num)
File "/usr/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 682, in
_read_response
self._convert_status(msg)
File "/usr/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 708, in
_convert_status
raise IOError(errno.ENOENT, text)
IOError: [Errno 2] No such file
If you know the answer. please let me know.
Thanks for reading.
If you want to put a file to the server you probably will need
sftp.put(local_path, remote_path)
not
sftp.get(remote_path, local_path)
You need to give file name also, otherwise it will throw errors
sftp.put('filename.txt','/home/user/performance/destination.txt')
where 'filename.txt' must be in current directory or else give full path
Related
I'm new in Python and I'm trying to use Selenium in Debian but it doesn't work, more concretely it seems to stay in a loop and nothing happens. The next script is the test that I've used:
#!/usr/bin/env python
from selenium import webdriver
browser = webdriver.Firefox()
browser.get('http://www.python.org')
When I interrupt the script the following text appears:
Traceback (most recent call last):
File "prueba_parseo.py", line 7, in browser =
webdriver.Firefox() File
"/usr/local/lib/python2.7/dist-packages/selenium/webdriver/firefox/webdriver.py",
line 154, in init
keep_alive=True)
File
"/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py",
line 140, in init
self.start_session(desired_capabilities, browser_profile)
File
"/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py",
line 229, in start_session
response = self.execute(Command.NEW_SESSION, parameters)
File
"/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py",
line 295, in execute
response = self.command_executor.execute(driver_command, params)
File
"/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/remote_connection.py",
line 464, in execute
return self._request(command_info[0], url, body=data)
File
"/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/remote_connection.py",
line 488, in _request
resp = self._conn.getresponse()
File "/usr/lib/python2.7/httplib.py", line 1111, in getresponse
response.begin()
File "/usr/lib/python2.7/httplib.py", line 444, in begin
version, status, reason = self._read_status()
File "/usr/lib/python2.7/httplib.py", line 400, in _read_status
line = self.fp.readline(_MAXLINE + 1)
File "/usr/lib/python2.7/socket.py", line 476, in readline
data = self._sock.recv(self._rbufsize)
KeyboardInterrupt
I've been searching for an answer, but nothing works. I've changed the versions of the packages, export no_proxy="localhost,127.0.0.1"
OS: Debian 5
Python: 2.7
Selenium: 3.5
Geckodriver: 0.17.0
Firefox: 52.0
I don't know what else to do or what to change.
Thank you very much!
My guess is that it actually all goes well and the browser is started in background. The reason why it's staying open is probably because of the default option keep_alive=True I can see in your traceback.
Try closing the browser using browser.close() or browser.quit() when you are done with the tests.
From the documentation:
Finally, the browser window is closed. You can also call quit method
instead of close. The quit will exit entire browser whereas close`
will close one tab, but if just one tab was open, by default most
browser will exit entirely.
http://selenium-python.readthedocs.io/getting-started.html#simple-usage
I am trying to copy a file from remote server to my local machine using FTP and i have written a python script for it.:
import os
from ftplib import FTP
btsIp=raw_input("Enter the IP:")
try:
ftp=FTP(btsIp,user='',passwd='',timeout=20)
except :
print("FTP Connection failed")
sys.exit(1)
ftp.cwd('/store/slv_imt')
filenames=ftp.nlst()
for eachFile in filenames:
localName=os.path.join('D:\Users\shaik-s\Documents\SLV_logs',eachFile)
file=open(localName,'w')
ftp.retrbinary('RETR' + eachFile,file.write)
file.close()
ftp.quit()
However, i am getting error, as command not understood:
slv_imt_2016-07-13__00-00-34.tar
Traceback (most recent call last):
File "C:/Python27/Scripts/ftp.py", line 16, in <module>
ftp.retrbinary('RETR' + eachFile,file.write)
File "C:\Python27\lib\ftplib.py", line 414, in retrbinary
conn = self.transfercmd(cmd, rest)
File "C:\Python27\lib\ftplib.py", line 376, in transfercmd
return self.ntransfercmd(cmd, rest)[0]
File "C:\Python27\lib\ftplib.py", line 339, in ntransfercmd
resp = self.sendcmd(cmd)
File "C:\Python27\lib\ftplib.py", line 249, in sendcmd
return self.getresp()
File "C:\Python27\lib\ftplib.py", line 224, in getresp
raise error_perm, resp
error_perm: 500 'RETRSLV_IMT_2016-07-13__00-00-34.TAR': command not understood.
Kindly help..
To fix the error, you need to add a space between "RETR" and "eachFile".
ftp.retrbinary('RETR %s'%eachFile, file.write)
But your code shows that you may encounter another problem, try to use the following cmd.
file = open(localName, 'wb')
I am trying to run the following Python 2.7.10 code on Win7:
from robot import run
run("Login.robot", variable=['USERNAME:testuser#fakemail.com'])
Login.robot is a very simple robot framework test that opens a browser window, loads our log in page, enters in a username and password, then confirms the user has logged in. I have tested it by running it from the command line with pybot and the test suite runs correctly. But trying to run the test suite from this script generates
Traceback (most recent call last):
File "C:\Users\dmdunn\Desktop\test_user_data.py", line 4, in <module>
run("Login.robot", variable=['USERNAME:testuser#fakemail.com'])
File "C:\Python27\lib\site-packages\robot\run.py", line 471, in run
return RobotFramework().execute(*datasources, **options)
File "C:\Python27\lib\site-packages\robot\utils\application.py", line 83, in execute
return self._execute(list(arguments), options)
File "C:\Python27\lib\site-packages\robot\utils\application.py", line 96, in _execute
details, rc=FRAMEWORK_ERROR)
File "C:\Python27\lib\site-packages\robot\utils\application.py", line 110, in _report_error
self._logger.error(message)
File "C:\Python27\lib\site-packages\robot\output\loggerhelper.py", line 59, in error
self.write(msg, 'ERROR')
File "C:\Python27\lib\site-packages\robot\output\loggerhelper.py", line 62, in write
self.message(Message(message, level, html))
File "C:\Python27\lib\site-packages\robot\output\logger.py", line 109, in message
logger.message(msg)
File "C:\Python27\lib\site-packages\robot\output\monitor.py", line 66, in message
self._writer.error(msg.message, msg.level, clear=self._running_test)
File "C:\Python27\lib\site-packages\robot\output\monitor.py", line 142, in error
self._highlight('[ ', level, ' ] ' + message, error=True)
File "C:\Python27\lib\site-packages\robot\output\monitor.py", line 158, in _highlight
self._write(before, newline=False, error=error)
File "C:\Python27\lib\site-packages\robot\output\monitor.py", line 154, in _write
stream.flush()
IOError: [Errno 9] Bad file descriptor
Any suggestions? I've tried using an absolute path to the robot file, single quotes, double quotes, referencing via an open file object, referencing via a closed file object. Thanks!
I discovered it was due to using IDLE, which prevented robot framework from writing to the console. My script runs when started from the Windows command line.
Open a file handle and call robot.run method inside while handle is open.
I hope this will solve your issue.
mydir = os.path.join('c:/','....')
os.makedirs(mydir)
with open('mydir', 'w') as stdout_file:
k = run("Login.robot",
variable=['USERNAME:testuser#fakemail.com'],
stdout=stdout_file)
I want to loop through the files present in Audio_files folder and check if it is raw file or wave file and put it in the respective directories.
Here is my code:
import shutil
import os
source = os.listdir("/home/GM/codec_implement/Audio_files/")
destination = "/home/GM/codec_implement/raw_files/"
destination2 = "/home/GM/codec_implement/raw_files/wave_files/"
for files in source:
if files.endswith(".wav"):
shutil.copy(files,destination)
elif files.endswith(".raw"):
shutil.copy(files,destination)
else:
print "Invalid format"
Please let me know where I am making mistake. Error i get is:
Traceback (most recent call last): File "./checkaudiofiles.py", line
12, in shutil.copy(files,destination) File
"/usr/lib/python2.7/shutil.py", line 119, in copy copyfile(src, dst)
File "/usr/lib/python2.7/shutil.py", line 82, in copyfile with
open(src, 'rb') as fsrc: IOError: [Errno 2] No such file or directory:
'test_sound.wav'
The error means that the test_sound.wav file is not on that directory. These file might be removed between the two proces or the os.listdir() and the shutil.copy() don't list the files the same way.
below is my code i am using to scrap some web page
i am using python in windows 8
import urllib
import re
htmlfile = urllib.urlopen("https://finance.yahoo.com/q?s=aapl&ql=1")
htmltext = htmlfile.read()
regex='<span id="yfs_l84_aapl">(.+?)</span>'
pattern = re.compile(regex)
price = re.findall(pattern,htmltext)
print price
error i am getting
Traceback (most recent call last):
File "C:\Python27\web.py", line 4, in
htmlfile = urllib.urlopen("https://finance.yahoo.com/q?s=aapl&ql=1")
File "C:\Python27\lib\urllib.py", line 87, in urlopen
return opener.open(url)
File "C:\Python27\lib\urllib.py", line 208, in open
return getattr(self, name)(url)
File "C:\Python27\lib\urllib.py", line 437, in open_https
h.endheaders(data)
File "C:\Python27\lib\httplib.py", line 969, in endheaders
self._send_output(message_body)
File "C:\Python27\lib\httplib.py", line 829, in _send_output
self.send(msg)
File "C:\Python27\lib\httplib.py", line 791, in send
self.connect()
File "C:\Python27\lib\httplib.py", line 1176, in connect
self.sock = ssl.wrap_socket(sock, self.key_file, self.cert_file)
File "C:\Python27\lib\ssl.py", line 387, in wrap_socket
ciphers=ciphers)
File "C:\Python27\lib\ssl.py", line 143, in init
self.do_handshake()
File "C:\Python27\lib\ssl.py", line 305, in do_handshake
self._sslobj.do_handshake()
IOError: [Errno socket error] [Errno 1] _ssl.c:507: error:140770FC:SSL routines:SSL23_GET_SERVER_HELLO:unknown protocol
how to debug this error
use inspect element > go to console > check if any errors in script > manage them > if problem still persists go to network option > now reload the page and check the flow of information > and rebuilt where info. flow is stopped or unexpected.
hope this will solve your problem.
i found an another answer my self
use inspect element > go to console > check if any errors in script > manage them > if problem still persists go to network option > now reload the page and check the flow of information > and rebuilt where info. flow is stopped or unexpected.