How can I get all "clid's" which has the "client_type=0"? The pipe char "|" seperates each client info. The text, which I have is just one line:
clid=2 cid=3346 client_database_id=5153 client_nickname=xLukas\s\p\sLukas client_type=0|clid=3 cid=3346 client_database_id=1 client_nickname=powered\sby\sMirWayne.DE
client_type=1|clid=4 cid=3346 client_database_id=9661
client_nickname=Number\sone client_type=0|clid=5 cid=3469
client_database_id=1 client_nickname=powered\sby\sMirWayne
client_type=1|clid=6 cid=1716 client_database_id=1
client_nickname=FG\sBot client_type=1|clid=7 cid=3469
client_database_id=9661 client_nickname=Number\stwo
client_type=0|clid=8 cid=1762 client_database_id=4351
client_nickname=pr0zkillz1x\pTobi client_type=0|clid=9 cid=1764
client_database_id=5160 client_nickname=xL1mited\s/\sMax
client_type=0|clid=10 cid=1716 client_database_id=9704
client_nickname=Sebi client_type=0|clid=13 cid=3346
client_database_id=4336 client_nickname=checker284\s\p\sSebbo
client_type=0|clid=19 cid=1762 client_database_id=9312
client_nickname=pr0skillz1x\pDanie client_type=0|clid=30 cid=3346
client_database_id=9697 client_nickname=TeamSpeakUser
client_type=0|clid=33 cid=1716 client_database_id=1
client_nickname=serveradmin client_type=1
I need alle clid's, which has the client_type=0 in an extra line. For example like that:
clid=2
clid=3
clid=4
clid=5
...
My current solution is not working:
cat clientlist.txt | grep -Eo "clid=[0-9]+[\d\D]*client_type=0" | grep -Eo "clid=[0-9]+"
Can somebody help?
The pipe char "|" seperates each client info.
Making use of this information, you can say:
tr '|' '\n' < clientlist.txt | grep -Po 'clid=\d+(?=.*client_type=0)'
For your input, it'd result in:
clid=2
clid=4
clid=7
clid=8
clid=9
clid=10
clid=13
clid=19
clid=30
Using sed:
tr '|' '\n' < file | sed -n '/client_type=0/s/\(clid=[0-9]*\).*$/\1/p'
clid=2
clid=4
clid=7
clid=8
clid=9
clid=10
clid=13
clid=19
clid=30
Related
I would like to reverse the complete text from the file.
Say if the file contains:
com.e.h/float
I want to get output as:
float/h.e.com
I have tried the command:
rev file.txt
but I have got all the reverse output: taolf/h.e.moc
Is there a way I can get the desired output. Do let me know. Thank you.
Here is teh link of teh sample file: Sample Text
You can use sed and tac:
str=$(echo 'com.e.h/float' | sed -E 's/(\W+)/\n\1\n/g' | tac | tr -d '\n')
echo "$str"
float/h.e.com
Using sed we insert \n before and after all non-word characters.
Using tac we reverse the output lines.
Using tr we strip all new lines.
If you have gnu-awk then you can do all this in a single awk command using 4 argument split function call that populates split strings and delimiters separately:
awk '{
s = ""
split($0, arr, /\W+/, seps)
for (i=length(arr); i>=1; i--)
s = s seps[i] arr[i]
print s
}' file
For non-gnu awk, you can use:
awk '{
r = $0
i = 0
while (match(r, /[^a-zA-Z0-9_]+/)) {
a[++i] = substr(r, RSTART, RLENGTH) substr(r, 0, RSTART-1)
r = substr(r, RSTART+RLENGTH)
}
s = r
for (j=i; j>=1; j--)
s = s a[j]
print s
}' file
Is it possible to use Perl?
perl -nlE 'say reverse(split("([/.])",$_))' f
This one-liner reverses all the lines of f, according to PO's criteria.
If prefer a less parentesis version:
perl -nlE 'say reverse split "([/.])"' f
For portability, this can be done using any awk (not just GNU) using substrings:
$ awk '{
while (match($0,/[[:alnum:]]+/)) {
s=substr($0,RLENGTH+1,1) substr($0,1,RLENGTH) s;
$0=substr($0,RLENGTH+2)
} print s
}' <<<"com.e.h/float"
This steps through the string grabbing alphanumeric strings plus the following character, reversing the order of those two captured pieces, and prepending them to an output string.
Using GNU awk's split, splitting from separators . and /, define more if you wish.
$ cat program.awk
{
for(n=split($0,a,"[./]",s); n>=1; n--) # split to a and s, use n from split
printf "%s%s", a[n], (n==1?ORS:s[(n-1)]) # printf it pretty
}
Run it:
$ echo com.e.h/float | awk -f program.awk
float/h.e.com
EDIT:
If you want to run it as one-liner:
awk '{for(n=split($0,a,"[./]",s); n>=1; n--); printf "%s%s", a[n], (n==1?ORS:s[(n-1)])}' foo.txt
I wanna extract IP and download-total from mikrotik command /queue simple print stat
Here's some example :
0 name="101" target=192.168.10.101/32 rate=0bps/0bps total-rate=0bps
packet-rate=0/0 total-packet-rate=0 queued-bytes=0/0
total-queued-bytes=0 queued-packets=0/0 total-queued-packets=0
bytes=17574842/389197663 total-bytes=0 packets=191226/308561
total-packets=0 dropped=9/5899 total-dropped=0
1 name="102" target=192.168.10.102/32 rate=0bps/0bps total-rate=0bps
packet-rate=0/0 total-packet-rate=0 queued-bytes=0/0
total-queued-bytes=0 queued-packets=0/0 total-queued-packets=0
bytes=65593392/183786457 total-bytes=0 packets=163260/166022
total-packets=0 dropped=175/2403 total-dropped=0
2 name="103" target=192.168.10.103/32 rate=0bps/0bps total-rate=0bps
packet-rate=0/0 total-packet-rate=0 queued-bytes=0/0
total-queued-bytes=0 queued-packets=0/0 total-queued-packets=0
bytes=3263234/67407044 total-bytes=0 packets=41437/52602
total-packets=0 dropped=0/546 total-dropped=0
All that I need is :
192.168.10.101 389197663
192.168.10.102 183786457
192.168.10.103 67407044
But I get
target=192.168.10.101/32
bytes=17574842/389197663
target=192.168.10.102/32
bytes=65593392/183786457
target=192.168.10.103/32
bytes=3263234/67407044
I try it with grep -oP 'target=.*?\ |[^\-]bytes=.*?\ ' | sed 's/^ //g'.
So, how can I parse it? Sorry for bad english..
Just continue your line of parsing with another pipes (most easy way i think)
grep -oP 'target=.*?\ |[^\-]bytes=.*?\ ' file | sed 's/^ //g' | sed -r 's/target=([^/]*)[/].*/\1/; s/bytes=[^/]*[/]//' | sed 'N; s/\n/ /'
output
192.168.10.101 389197663
192.168.10.102 183786457
192.168.10.103 67407044
sed '/^[0-9]\{1,\}[[:blank:]]\{1,\}name/,/^[[:blank:]]*$/ {
/^[0-9]/{
s#.*target=\([^/]*\).*#\1#;h;d
}
\#^[[:blank:]]*bytes=[0-9]*/\([0-9]*\).*# !d
s//\1/
G
s/\(.*\)\n\(.*\)/\2 \1/p
}
d
' YourFile
A bit long but do the job in 1 sed
awk '{
if ( $3 ~ /target=/ ) split( $3, aIP, "[=/]")
if ( $1 ~ /^[[:blank:]]*bytes=[0-9]*/ ) {
split( $1, aByt, "/")
print aIP[2] " " aByt[2]
}
}' YourFile
same in awk
if always same exact structure
awk 'BEGIN{ RS="" }
{ split( $3, aIP, "[=/]"); split( $12, aByt, "/")
print aIP[2] " " aByt[2]
}' YourFile
I have a following content in the file:
NAME=ALARMCARDSLOT137 TYPE=2 CLASS=116 SYSPORT=2629 STATE=U ALARM=M APPL=" " CRMPLINK=CHASSIS131 DYNDATA="GL:1,15 ADMN:1 OPER:2 USAG:2 STBY:0 AVAL:0 PROC:0 UKNN:0 INH:0 ALM:20063;1406718801,"
I just want to filter out NAME , SYSPORT and ALM field using sed
Try the below sed command to filter out NAME,SYSPORT,ALM fields ,
$ sed 's/.*\(NAME=[^ ]*\).*\(SYSPORT=[^ ]*\).*\(ALM:[^;]*\).*/\1 \2 \3/g' file
NAME=ALARMCARDSLOT137 SYSPORT=2629 ALM:20063
why not using grep?
grep -oE 'NAME=\S*|SYSPORT=\S*|ALM:[^;]*'
test with your text:
kent$ echo 'NAME=ALARMCARDSLOT137 TYPE=2 CLASS=116 SYSPORT=2629 STATE=U ALARM=M APPL=" " CRMPLINK=CHASSIS131 DYNDATA="GL:1,15 ADMN:1 OPER:2 USAG:2 STBY:0 AVAL:0 PROC:0 UKNN:0 INH:0 ALM:20063;1406718801,"'|grep -oE 'NAME=\S*|SYSPORT=\S*|ALM:[^;]*'
NAME=ALARMCARDSLOT137
SYSPORT=2629
ALM:20063
Here is another awk
awk -F" |;" -v RS=" " '/NAME|SYSPORT|ALM/ {print $1}'
NAME=ALARMCARDSLOT137
SYSPORT=2629
ALM:20063
Whenever there are name=value pairs in input files, I find it best to first create an array mapping the names to the values and then operating on the array using the names of the fields you care about. For example:
$ cat tst.awk
function bldN2Varrs( i, fldarr, fldnr, subarr, subnr, tmp ) {
for (i=2;i<=NF;i+=2) { gsub(/ /,RS,$i) }
split($0,fldarr,/[[:blank:]]+/)
for (fldnr in fldarr) {
split(fldarr[fldnr],tmp,/=/)
gsub(RS," ",tmp[2])
gsub(/^"|"$/,"",tmp[2])
name2value[tmp[1]] = tmp[2]
split(tmp[2],subarr,/ /)
for (subnr in subarr) {
split(subarr[subnr],tmp,/:/)
subName2value[tmp[1]] = tmp[2]
}
}
}
function prt( fld, subfld ) {
if (subfld) print fld "/" subfld "=" subName2value[subfld]
else print fld "=" name2value[fld]
}
BEGIN { FS=OFS="\"" }
{
bldN2Varrs()
prt("NAME")
prt("SYSPORT")
prt("DYNDATA","ALM")
}
.
$ awk -f tst.awk file
NAME=ALARMCARDSLOT137
SYSPORT=2629
DYNDATA/ALM=20063;1406718801,
and if 20063;1406718801, isn't the desired value for the ALM field and you just want some subsection of that, simply tweak the array construction function to suit whatever your criteria is.
All is in the title :
here is the string pattern of a multi-line file:
foo_bar_alpha = "a1b2c3_cat_andthis"
barfoo_bar_alpha = "just a int number"
loremfoo_bar_beta = "192.168.0.0"
... other lines come here ...
Using sed (and/or awk and/or perl), I need to substitute char "_" with "." , but only in the first part of the string, which is right delimited by "=", and keep the 2nd part (after "=").
Sthg like :
sed "s/(.*)=(.*)/ \1 with "_" replaced by "." = \2/g" < my_file
¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
how to do that ?
Thx in adv.
awk '{gsub("_",".",$1)}1' ./infile
Input
$ cat ./infile
foo_bar_alpha = "a1b2c3_cat_andthis"
barfoo_bar_alpha = "just a int number"
loremfoo_bar_beta = "192.168.0.0"
Output
$ awk '{gsub("_",".",$1)}1' ./infile
foo.bar.alpha = "a1b2c3_cat_andthis"
barfoo.bar.alpha = "just a int number"
loremfoo.bar.beta = "192.168.0.0"
*Note: If you for sure need to delimit on = because your variable names somehow contain spaces (highly doubtful) then this works:
awk -F= '{gsub("_",".",$1)}1' OFS="=" ./infile
Crude but effective:
sed 'h;s/.*=/=/;x;s/=.*//;s/_/\./g;G;s/\n//' filename
use awk instead of sed
awk 'BEGIN{OFS=FS="="}{gsub("_",".",$1)}1' file
ruby -F"=" -ane '$F[0].gsub!(/_/,".");print $F.join("=")' file
Format:
[Headword]{}"UC(icl>restriction)"(Attributes);(gloss)
The testme.txt file has 2 lines
[testme] {} "acetify" (V,lnk,CJNCT,AJ-V,VINT,VOO,VOO-CHNG,TMP,Vo) <H,0,0>;
[newtest] {} "acid-fast" (ADJ,DES,QUAL,TTSM) <H,0,0>;
The expected output is this:
testme = acetify
newtest = acid-fast
What I have achieved so far is:
cat testme.txt | sed 's/[//g' | sed 's/]//g' | sed 's/{}/=/g' | sed 's/\"//'
testme = acetify" (V,lnk,CJNCT,AJ-V,VINT,VOO,VOO-CHNG,TMP,Vo) <H,0,0>;
newtest = acid-fast" (ADJ,DES,QUAL,TTSM) <H,0,0>;
How do I remove all the text from the second " to the end of the line?
Remove everything after the doublequote-space-openparenthesis " (:
sed 's/" (.*//g'
The whole process might be a little quicker with awk:
awk 'NF > 0 { print $1 " = " $3 }' testme.txt | tr -d '[]"'
this is how you do it with awk instead of all those sed commands, which is unnecessary. what you want is field 1 and field 3. use gsub() to remove the quotes and brackets
$ awk '{gsub(/\"/,"",$3);gsub(/\]|\[/,"",$1);print $1" = "$3}' file
testme = acetify
newtest = acid-fast
Your whole sequence of multiple calls to sed can be replaced by:
sed 's/\[\([^]]*\)][^"]*"\([^"]*\).*/\1 = \2/' inputfile