I need to find the biggest sum and it containing numbers and whether the first or second number out of two was bigger. How to find it?
Let's say that n=10, the two put numbers are 6 and 2, followings: 7 and 1,
5 and 6, 1 and 8, 4 and 3. Then the answer should be that the biggest sum is 11, it containing numbers are 5 and 6, and the bigger numb was the second one.
I have a code:
#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;
int main()
{
int p, a, i;
int n;
int sum;
ofstream fr("Rezults.txt");
ifstream fd("Data.txt");
fd>>n;
cout<<n<<endl;
for (i=1; i<=n/2; i++)
{
fd>>p>>a;
sum=p+a;
for (int j=sum; j<=n/2; j++);
{
cout<<sum<<endl;
}
}
fd.close();
fr<<sum;
fr.close();
return 0;
}
I think your code should be like this :
#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;
int main()
{
int p, a, i;
int n;
int sum;
ofstream fr("Rezults.txt");
ifstream fd("Data.txt");
fd>>n;
cout<<n<<endl;
fd>>p>>a;
int biggestSum=p+a;
int first = p;
int second = a;
for (i=2; i<=n/2; i++)
{
fd>>p>>a;
sum=p+a;
if(sum > biggestSum)
{
biggestSum = sum;
first = p;
second = a;
}
}
cout <<"biggest sum is "<<biggestSum<<"\n";
cout <<"The first number is "<<first<<"\n";
cout<<"The second number is "<<second<<"\n";
fd.close();
fr<<sum;
fr.close();
return 0;
}
updated : you should be careful to the index i of the for loop it should start by 2 since you read the first two numbers before the for loop.
Related
I'm new to c++ but long story short , i want to write a c++ program that will accept input from user through an array and it will sum each array element input
#include <iostream>
#include <string>
#include <math.h>
using namespace std;
int main() {
int array[100];
int sum;
for(int i=0; i<100; i++){
cout<<"Insert element "<<i<<": ";
cin>>array[i];
sum = array[i]+ //summ with the next array input;
cout<<sum;
}
return 0;
}
means that if i enter any integer the program should be able to give the summation of the inputs in sequence from the first input to the last input
C++ standard library already has a function to do this which is std::accumulate:
#include <iostream>
#include <numeric>
int main() {
int array[5] = {1,2,3,4,5};
int total = std::accumulate(std::begin(array), std::end(array), 0);
return 0;
}
If you plan to use not a full array you should use std::begin(array), std::begin(array) + amount as ranges.
initialize your sum var to 0 initially and write sum+=array[i] instead of what you have written, there is also a limitation in this program as value of sum after all user input should be <=10^9 as int datatype store no. approximately upto 10^9 so take note of this fact also. Write cout<<sum<<endl; instead to be able to distinguish till previous input sum to the new input sum.
Hope this will help.
You can use a do while loop:
#include<iostream>
#include<string>
#include<math.h>
int main()
{
int array[100];
int sum=0;
int i=0;
std::cout<<"Insert element"<<" "<<i<<": ";
std::cin>>array[i];
do
{
sum=sum+array[i];
std::cout<<sum<<std::endl;
i++;
std::cout<<"Insert element"<<" "<<i<<": ";
}while(std::cin>>array[i]);
return 0;
}
If all you want is the sum then just compute the sum. No need to store anything:
#include <iostream>
#include <string>
#include <math.h>
int main() {
int sum = 0;
for(int i=0; i<100; i++){
std::cout << "Insert element " << i << ": ";
int t;
std::cin >> t;
sum += t
std::cout << sum;
}
}
The task is to read an integer array from a user and then count sort it. I used vector to take input of the array but it only stops reading integers after I enter non-integer symbol when it has to do it after the last integer. For example, if I enter (5 4 3 2 1) it does not proceed further but keeps expecting input from a user. Also the sorted array must look like "1 2 3 4 5) but I have 0 at the beginning of it (0 1 2 3 4 5).
#include <iostream>
#include <string>
#include <cstring>
#include <vector>
using namespace std;
int main(){
vector<int> arr;
int x;
int j = 0;
while(cin.good()==1){
cin>>x;
arr.push_back(x);
j++;
}
cin.clear();
int count_array[j]={0};
int s=0;
int new_array[j];
int i;
for(i=0; i<j; i++)
count_array[arr[i]]++;
for(i=0; i<j; i++){
count_array[i] = count_array[i] + s;
s=count_array[i];
}
for(i=0;i<j;i++){
new_array[count_array[arr[i]]]=arr[i];
count_array[arr[i]]--;
}
for(i=1;i<=j;i++)
{
cout<<new_array[i]<<" ";
}
return 0;
}
I have to make a scrabble scoring game using 2 arrays. The first array holds the user inputted word and the second array holds the value of each letter. Lastly a function is needed to calculate the score. Im having trouble assigning the user values to the second array to get the score and getting the right code for the function.
#include <iostream>
#include <stdlib.h>
#include <cmath>
#include <ctime>
using namespace std;
int scoreCalculator(int total);
char userWord;
int points;
int total=0;
int main()
{
char userWord[11];
for (int i=0; i<11; i++)
{
userWord[i]='\0';
}
cout<<"Enter your word less than 10 letters: "<<endl;
cin>>userWord;
cout<<"Here is the word you inputted: "<<userWord<<endl;
int scrabblePoints[26]={1,3,3,2,1,4,2,4,1,8,5,1,3,1,1,3,10,1,1,1,1,4,4,8,4,10};
for(int j=0; j<26; j++)
{
userWord[i]
}
cout<<"Here is your score: "<<scoreCalculator(total)<<endl;
}
int scoreCalculator(int total)
{
total+=scrabblePoints[j];
}
This is what I have so far and where im stuck at
#include <iostream>
int main()
{
std::string input;
std::cin>>input;
// fill this with scrable values
int scrable_values[26] = {1,3,3,2,1,4,2,4,1,9,5,1,3,1,1,3,10,1,1,1,1,4,4,8,4,10};
int ans = 0;
for(int i=0;i<input.size();i++)
{
ans += scrable_values[input[i]-97];
}
return ans;
}
I was given a task:
it is given an array of five numbers
First - Find all numbers that are multiples of four
Second - Find the biggest of them and write it vice versa.
I have written a code.
#include <iostream>
#include <iomanip>
using namespace std;
#define size 12
int main()
{
int new_max=0;
int a1, a2;
int i=0, j=0;
int a, b, c=0;
int u[size]={38,12,36,45,16,46,14,19,54,53,95, 98};
int max=0;
cout<<"Array: \n";
for(i=0; i<size; i++)
cout<<u[i]<<" \n";
for (int i=0; i<size; i++)
{
if (u[i]%4==0)
{
cout<<"array "<<u[i]<<" \n";
for (int j=0; j<size; j++)
{
if(max<u[i])
{
max=u[i];
}}}}
cout<<"max "<<max<<endl;
while(max > 0)
{
new_max = new_max*10 + ( max % 10);
max = max/10;
}
cout << new_max << endl;
return 0;
}
#include <iostream>
#include <algorithm>
#include <string>
#include <array>
int main() {
std::array<int, 5> input = { 36, 12, 38, 45, 16 };
auto validRangeEnd = std::remove_if(std::begin(input),
std::end(input),
[](int i){ return i % 4 != 0; });
// Now std::begin(input) -> validRangeEnd contain the ones divisible by 4
auto max = std::max_element(std::begin(input), validRangeEnd);
// Max contains the max number from the filtered range
auto stringMax = std::to_string(*max);
std::reverse(std::begin(stringMax), std::end(stringMax));
// Reverse reverses the max number
std::cout << stringMax;
}
By no means optimal but I feel it's useful for educational purposes :).
(Both remove_if and max_elements do a pass so I'll re-examine some stuff that I don't need to but this is a good algorithmic representation of the problem anyway. Also, no loops, look! :))
So I have to print Floyd's triangle but like this:
7
1
2 3
4 5 6
7 * * *
Here is my code, I just can't figure out how to print the * at the end of the last line if there is any space left.
#include<iostream>
#include<cmath>
using namespace std;
int main ()
{
int n;
cin>>n;
int br=1;
for (int i=1;i<=n;i++)
{
for(int j=1;j<=i;j++)
{
if(br<=n)
cout<<br<<" ";
br++;
}
if(br<=n)
cout<<endl;
}
}
Here is the modified code:
#include<iostream>
#include<cmath>
using namespace std;
int main ()
{
int n, i, j;
cin>>n;
int br=1;
for (i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
if(br>n)
break;
cout<<br<<" ";
br++;
}
if(br>n)
break;
cout<<endl;
}
for(int k = j; k <= i; k++)
{
cout<<"* ";
}
}
Note that on nth line, there are nth numbers. So, for every line, you must count the numbers you wrote already. So, when you write the number that you need you have written k numbers. Now, you need to add n-k stars.