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I need to extract information form a text using regex for statements like bellow
#1. 02/14/2013 05:21 pm - Safee Safeeul Bashir
- Status changed from New to In Progress
#2. 02/14/2013 10:43 pm - Safee Safeeul Bashir
- Status changed from In Progress to Resolved
- CL set to 1203474
#3. 08/16/2013 02:30 am - Mondal Amit Kumar
Task was automatically close beacuse last update was more than two months and the issue passed
From here I want to extract the date and time where the status is changed to resolve.
For example for this one the date with #2 **02/14/2013 10:43 pm**
How about this:
\d\d/\d\d/\d{4}\s\d\d:\d\d\s[ap]m(?=.*(\n?\r?).*Resolved)
See it on RegExr
The regex can be
\d{2}/\d{2}/\d{4}\s\d{2}:\d{2}\s[pa]m
Related
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I've never been very good at regex, but I really need to grab the percentage information from these log entries; however, the warn/critical message moves around depending on where the warning was located in either the In or the Out utilization. I just can't figure out the regex. Here are two example entries that show both in and out issues:
["XXXXXXX"], (up), MAC: XX:XX:XX:XX:XX:XX, Speed: 2 GBit/s, In: 0 Bit/s (0%), Out: 6.53 GBit/s (warn/crit at 1.6 GBit/s/1.8 GBit/s) (326.45%)(!!)
["XXXXXXX"], (up), MAC: XX:XX:XX:XX:XX:XX, Speed: 2 GBit/s, In: 0 Bit/s (warn/crit at 1.6 GBit/s/1.8 GBit/s) (95.45%), Out: 6.53 GBit/s (32.00%)(!!)
Ultimately I need to use capture groups to capture both the in and out utilization percentage. But every regex I try only finds a single percentage. Help on this would be greatly appreciated. Thanks in advance.
EDIT SHOWING EXPECTED RESULT:
for each line the regex capture groups would identify in and out so the program can see both the in and out utilization. The program is expecting a key value pair from every log entry like the following:
IN:0% OUT:326.45%
IN:95.45% OUT:32.00%
Do you need something like this?
In:.+\(([0-9\.]+%)\).+Out:.+\(([0-9\.]+%)
If you just need to pull out values with percentage information, then it can help
https://regex101.com/r/B9pZeO/1
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I am trying to come up with a regex to extract certain pieces of information from the below log. I've been messing with regex groups for awhile and am not getting anywhere. I would like to get the date/timestamp, the usr field, dstname field, and arg field. How can I accomplish this?
May 1 08:21:02 192.168.1.1 id=firewall sn=fakeserial time="2020-05-01 12:21:02 UTC" fw=1.2.3.4 pri=3 c=4 m=14 msg="Web site access denied" app=2515 sess="Auto" n=398533 usr="sampledomain\username" src=192.168.1.150:50334:X0 dst=72.21.81.240:80:X1 srcMac=b0:00:b4:18:4a:b5 dstMac=c0:ea:e4:9d:a0:8c proto=tcp/http dstname=ctldl.windowsupdate.com arg=/msdownload/update/v3/static/trustedr/en/disallowedcertstl.cab code=99 Category="Administrative Custom List settings" fw_action="drop"
You could base it on something like this
(\w{3} \d* [\d:]*).*usr="([a-z\\]*)".*dstname=([\w.]*).*arg=([\/][^ ]*)
https://regex101.com/r/VUIBAm/1
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I'm trying to write a fortran code for 1 phase flow in porous media.
In discretized equations and other long line I have a below problem as you see in the picture.
After that highlighted phrase my code become like comment.
Can anyone help me?
According to this:
In its current state, the syntax highlighting for fixed-form Fortran in the extension only supports a line length of 72 characters. Anything after column 72 appears as comments (green) in the source code, which also affects the appearance of the following lines (when a closing parenthesis is in this green region for example)
You can change it on fortran_fixed-form.tmLanguage.json file or on the VS code settings.
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I have hundred of song lyric database files, and I need to do something like this,
from this :
PPK4: B'rilah Hormat Pada Hu
Judul Inggris: Glory to God in the Highest
Lagu: unknown Syair: unknown
1=A, 4/4
to become like this :
PPK4: B'rilah Hormat Pada Hu
B'rilah Hormat Pada Hu
Judul Inggris: Glory to God in the Highest
Lagu: unknown Syair: unknown
1=A, 4/4
PPK4 is a song number. so, there will be like PPK1 until PPK255, KPPK1 .. KPPK300 etc.
and same format, "#songcode" ":" "(space)" "song title" "CRLF"
How do I do it using Find and Replace?
The answer involves regular expressions.
You could try "([A-Z]+[0-9]+[:])(.*)"
This will capture the song number as group 1 and the song title as group 2. You can then replace this with "\1\2\n\2", i.e. group 1 followed by group 2, a newline and group 2 again.
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I'm completely new to RegEx and could really use some help with my delimma. I have a large text file of IP addresses and corresponding Hosts.
eg.
157.55.33.47 msnbot-157-55-33-47.search.msn.com
157.56.93.62 msnbot-157-56-93-62.search.msn.com
etc...
I need a find and replace algorithm that apeends to the beginning and end of each line and replaces the delimeter, which in this case is just a space.
eg. the ouput after running the regex should be
'text1' 157.55.33.47 'text2' msnbot-157-55-33-47.search.msn.com 'text3'
'text1' 157.56.93.62 'text2' msnbot-157-56-93-62.search.msn.com 'text3'
Any guidance would be greatly appreciated!
Find what:
^([\S]+)\s([\S]+)$
Replace with:
'text1' $1 'text2' $2 'text3'
You can use a Macro for this instead of a regex. Record keystrokes on the first line. I'm on a Mac right now, so I can't be sure this is right, but it should be close to:
Home, [type 'text1'], CTRL+RightArrow [repeat 7 times], [type 'text2],
space, End, space, [type 'text3'], DownArrow
Once your Macro is recorded, re-run your Macro for the entire file. Again, I can't see the exact options, but it will be something like the following:
Go to Macros>Run a Macro Multiple Times..., select Current recorded macro, and Run until the end of file.