My code is
char buffer[10]={0};
cin>>buffer; //here i enter the contents as "12345678912345"
//Now i tried to enter 14 characters into a buffer of 10
cin>>buffer; //This works as it waits for input on the console
cout<<buffer;
wheras
char buffer[10]={0};
cin>>buffer;//same input as above "12345678912345"
cin.getline(buffer,10);//This doesn't wait for input on console and returns
cout<<buffer;
why does this happen?
THANKS:
thanks everyone for your answers they were helpful
Neither of your code-snippets "work" in the sense that both overflow the buffer in the first input line. This is not a good thing at all.
The second case doesn't wait for input because of technical differences between operator>> and getline - they react differently to the newline character that you have entered. When reading the first cin >> buffer, the newline at the end of the input is left in the input stream (cin). In your first case, the second cin >> buffer will skip over the newline that is in the input buffer, and then wait for more input.
In the second case, because of the workings of getline, it accepts the remaining newline as input, and buffer is not filled in with anything.
This is a common problem when mixing getline and operator>> for input. The best solution to solve that particular problem is to either use only operator >> or only getline - there are various other solutions, but they are generally quite tricky to get just right.
First off you have a buffer overrun: Reading to a char* stops when the stream goes bad, a space is found, or the width() is exhausted if it were bigger than 0. You want to use
std::cin >> std::setw(10) >> buffer;
Assuming this undefined behavior is abouded, the difference between using formatted and unformatted input for the second read is that formatted input starts with skipping leading whitespace whike unformatted input does not. Your first input stopped right before the newline character resulting from the enter key. That newline is good enough for getline() but it is skipped when using >>.
When switching between formatted and unformatted I/O you normally want to skip leading whitespace using, e.g., the std::ws manipulator:
(std::cin >> std::ws). getline(buffer, 10);
You should also consider using std::string together with std::getline().
When you input the value for buffer in console, the return is still stored in the input stream.
Hence the termination character '\n' is already read by getline() from the previous read operation. This is why this function does not wait further for user input.
Try reading the getline() before the cin >> operation.
Also, as noted by Mike, you should be careful not to cause buffer overflow.
The >> operator does not consume any whitespace including the newline. The getline function returns when it sees a newline. Your problem is the newline that >> statement leaves at the buffer. You can solve this by consuming all characters, including the newline until you see a newline in the buffer. See the ignore function:
char buffer[10]={0};
cin>>buffer;
cin.ignore('\n', 256);
cin.getline(buffer,9);
cout<<buffer;
return 0;
Related
Here is the code:
string str;
cin>>str;
cout<<"first input:"<<str<<endl;
getline(cin, str);
cout<<"line input:"<<str<<endl;
The result is that getline never pauses for user input, therefore the second output is always empty.
After spending some time on it, I realized after the first call "cin>>str", it seems '\n' is still stored in cin (using cin.peek() to check), which ends getline immediately. The solution will be adding one more line between the first usage and the second one:
cin.ignore(numeric_limits::max(), '\n');
However, I still don't understand, why is '\n' left there after the first call? What does istream& operator>> really do?
The \n is left in the input stream as per the way operator>> is defined for std::string. The std::string is filled with characters from the input stream until a whitespace character is found (in this case \n), at which point the filling stops and the whitespace is now the next character in the input stream.
You can also remove the \n by calling cin.get() immediately after cin>>str. There are many, many different ways of skinning this particular I/O cat, however. (Perhaps a good question in and of itself?)
By default, the stream insertion operator reads until it sees whitespace. Your first call isn't returning until it sees a space, tab, newline, etc. Then the next character needs to be consumed so that you can get to the next one.
I generally recommend only doing line-oriented input from std::cin. So, your code could look something like this:
string str;
int val;
// Read an entire line and parse an integer from it
{
string line;
getline(cin, line);
istringstream iss(line);
iss >> val;
}
cout<<"first input:"<<val<<endl;
getline(cin, str);
cout<<"line input:"<<str<<endl;
Be sure to add error checking too.
The getline-only approach avoids having to think about line buffering of the input, of clearing the input, etc. If you directly read something with >>, the input does not terminate if the user hits enter instead of inputting what is required, but instead continues until a token is input (this behavior is usually not wanted).
As others have said, th problem is that the newline is left from the first extraction. One solution I do is to discard all the left characters in the stream:
std::cin.ignore( std::numeric_limits<std::streamsize>::max(), '\n' );
Good writeup that explains some of the reasons why you are running into this issue, primarily due to the behavior of the input types and that you are mixing them
Also was searching for most suitable solution. Implementation of this operator could produce problems. And not always is acceptable to read entire line, or not mix different types in one input line.
To solve problem, when you want to read some data from cin, and don't know if whitespaces was correctly extracted after last input operation, you can do like this:
std::string str;
std::cin >> std::ws >> str;
But you can't use this to clear trailing newline symbol after last input operation from cin to do not affect new input, because std::ws will consume all whitespaces and will not return control until first non-ws character or EOF will be found, so pressing enter will not finish input process.
In this case should be used
std::cin.ignore( std::numeric_limits<std::streamsize>::max(), '\n' );
which is more flexible.
P.S. If got errors with max() function such as "identifier expected", it could be caused by max macros defined in some header (for example, by Microsoft); this could be fixed by using
#undef max
I wanted to ignore all characters in cin to flush cin in this answer: How to get rid of bad input one word at a time instead of one line at a time?
But I found that the program seemed to hang awaiting input if I wrote:
cin.ignore(std::numeric_limits<std::streamsize>::max());
It propperly flushed cin if I used the '\n' delimiter:
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
My question is, why can't I just ignore till EOF? Why do I have to provide the delimiter?
The ignore function name is a little bit misleading. What it actually does it read and discard input until the terminator is found. And that's a blocking read.
In your case, whatever input stream you are using with cin (by default it is stdin) never delivers an end-of-file condition, so ignore's read/discard loop blocks forever.
I have a do-while loop, shown below
do
{
dimensions = NULL;
printf("=======================================\nDo you want to multiply in 2 dimensions, or 3?\n\n");
scanf("%c", &dimensions);
... //do stuff
printf("\nEnter r to repeat, return to terminate\n");
scanf("%c", &key);
scanf("%c", &key);
}
while(key == 'r');
On the first run, it executes fine. The problem however is when it runs through the code again after the user enters 'r' and hits return. It'll take you to the first printf("==== etc., but won't allow the user to do anything, it'll go straight back to the second printf("\nEnter...
I stepped through the code to see what was going on, and on a second run through the program just skips the scanf( and all following code for absolutely no reason. Initially I thought it was because 'dimensions' wasn't being set to a value that doesn't run the following methods - but I have, and even if that were the case, the program would run the methods instead of skipping them without user input.
Am I missing something? Is scanf( not enough to stop the program once it's already been used?
Your problem is that when your program gets input from the console with scanf, it reads the data from the keyboard into the input buffer, then values are taken out of the buffer and placed into the locations you provide to scanf. The issue is that when scanf reads a character, it also reads the \n into the buffer, then upon being called again, it reads the second character that was placed into the buffer (without asking you for more input - because why would it? It already HAS things in the buffer).
So there are two solutions: one - use fflush on stdin like so: fflush(stdin). Second - write a while loop that clears out characters one by one from the input buffer: while (getchar() != '\n' );
EDIT: For more reading, see How to clear input buffer in C?
Think it through: "the user enters 'r' and hits return", then the program reads the 'r' and repeats. What's left in the input buffer? There were two keys pressed, and the code only read the first one.
That's also the reason that the code needs two calls to scanf. The first clears the extra character out of the input buffer and the second reads the new character.
What is happening now
To make the buffer flush you need to enter
r<enter>
Hitting <enter> flushes the buffer. So the input buffer now contains two characters.
r\n
So the first scanf will read r
The second scanf will read \n
So by the time you reach the while key has a value of \n. The test fails and the loop is not repeated. So you should remove the second scanf() reading into key.
So you remove the second scanf. Now what happens?
User types
r<enter>
This leaves the input buffer with:
r\n
The scanf() read r into key. The loop repeats correctly. But when we get back to the scanf(). The input buffer still has \n character in the buffer. So the scanf() immediately reads this value and the loop exists as it should have.
how you should fix it.
Ask for Y/N answer and validate that the input is correct.
std::string line;
std::getline(std::cin, line);
while (line != "Y" && line != "N")
{
std::cout << "Hey cluts enter a correct value. Y/N\n";
std::getline(std::cin, line);
}
When using the >> operator in c++ to capture user input, is it possible to prevent the console from printing the newline that is generated when the user presses the return key?
You cannot prevent newline character, because when you use cin, you are communicating with system core, which is not under control by users. console will return, when you enter \n or EOF or other exception situation.
So the better way is to use getchar() to capture the '\n', and do not leave it in buffer.
It is possible to prevent this newline behavior by inputting two EOFs instead of Carriage Return from the keyboard. After entering your string at the console prompt, hit
CTRL-D, CTRL-D
Note, this is a platform specific answer. This works on my Mac, but on Windows OS the EOF sequence may be CTRL-Z, RETURN. I would appreciate an answer edit <-- HERE.
Alternately, you can ditch the >> operator and use something like std::getline and specify an exact string termination delimiter. For example:
std::string myString;
std::getline(std::cin, myString, ';');
std::cout << myString;
This will read from standard input to myString, and put the string terminating NULL character where it finds the first semicolon ';'. Then you'll only have to hit CTRL-D (input EOF) once.
You can enter the values or input by pressing space every time. But at the end you must press enter key.
Let's say: you want to enter "5,4,3,2,1"
You can do: 5 [enter] 4 [enter] 3[enter] 2[enter] 1[enter]
Also: 5[space]4[space]3[space]2[space]1[enter]
But if you want to print the output near input, you can simply print the input first and than you can print the what you want.
Example:
Input: 3 Output: input+1
So you will do:
cout<<input;
cout<<" "<<input+1<<endl;
Good luck :)
I'm reading input using cin. If I leave the input blank (and just hit enter), the cursor moves to a new line and asks for input again. Is there any way to make cin or scanf just return an empty string in this case?
Instead of operator>>, use getline.
std::string data;
std::getline(std::cin, data);
Side note: There's no recursion involved here. Recursion is when a function calls itself, that's not happening here.