Lining columns up - c++

Question

Solved!
This is what I wrote:
cout << setw(4) << "Students";
cout << setw(20) << "Hours Worked";
cout << setw(20) << "of Total Hours";
cout << endl;
for (int i = 0; i < students; i++)
{
cout << setw(20);
cout << names[i];
cout << setw(10) << hours[i];
cout << setw(10) << percent[i];
cout << endl;
}
But if the first name is a few characters sorter or bigger than second name, they become misaligned. How would I keep each column aligned equally?

Answer 1

Try something like this:
#include<iostream>
#include <iomanip>
#include<string>
using namespace std;
int main()
{
int students = 5;
string names[5] = {"a","bccc","c","d","ecsdfsdfasdasasf"};
int hours[5] = {1,2,3,4,5};
int percent[5] = {10,20,30,40,54};
string column("Students");
int maxStringSize = 0;
int sizeOfStudentColumn = column.length();
for(int i = 0; i < 5; ++i)
{
if(maxStringSize < names[i].length())
maxStringSize = names[i].length();
}
if(sizeOfStudentColumn > maxStringSize)
maxStringSize = sizeOfStudentColumn;
cout<<"max size: "<<maxStringSize<<endl;
cout << setw(4) << "Students";
cout << setw(maxStringSize + 5) << "Hours Worked";
cout << setw(20) << "of Total Hours";
cout << endl;
for (int i = 0; i < students; i++)
{
// cout << setw(20);
cout << names[i];
int diff = maxStringSize - names[i].length();
cout << setw(diff + 5 ) << hours[i];
cout << setw(20) << percent[i];
cout << endl;
}
}