regex filename of a unixpath without the first two digits - regex

Question

I have filename in a unix-path starting with two digits ... how can i extract the name without the extension
/this/is/my/path/to/the/file/01filename.ext should be filename
I currently have [^/]+(?=\.ext$) so I get 01filename, but how do I get rid of the first two digits?

Answer 1

You can add a look-behind in front of what you already have, looking for two digits:
(?<=\d\d)[^/]+(?=.ext$)
This only works if you have exactly two digits! Unfortunately, in most regex engines it is not possible to use quantifiers like * or + in lookbehinds.
(?<=\d\d) - checks for two digits before the match
[^/]+ - matches 1 or more characters, except /
(?=.ext$) - checks for .ext behind the match

Answer 2

Try this one :
/\d\d(.*?).\w{3}$
Explanation :
/\d\d : slash followed by two digit
(.*?) : the capture
.\w{3} : a dot followed by three letters
$ : end of string
It works for me on Expresso

Answer 3

Consider the following Regex...
(?<=\d{2})[^/]+(?=.ext$)
Good Luck!

Answer 4

A more general regex:
(?:^|\/)[\d]+([^.]+)\.[\w.]+$
Explanation:
(?: group, but do not capture:
^ the beginning of the string
| OR
\/ '/'
) end of grouping
[\d]+ any character of: digits (0-9) (1 or more
times (matching the most amount possible))
( group and capture to \1:
[^.]+ any character except: '.' (1 or more
times (matching the most amount
possible))
) end of \1
\. '.'
[\w\.]+ any character of: word characters (a-z, A-
Z, 0-9, _), '.' (1 or more times
(matching the most amount possible))
$ before an optional \n, and the end of the
string