Python Regex List into Another List - regex

Question

I currently have a piece of code that runs mainly as I would expect only it prints out both the original list and the one that has been filtered. Essentially what I am trying to do is read URL's from a webpage and store them into a list ( called match, this part works fine) and then filter that list into a new list (called fltrmtch) because the original contains all of the extra href tags ect.
For example at the moment it would print out A and B but Im only after B:
A Core Development',
B'http://docs.python.org/devguide/'),
Heres the code:
url = "URL WOULD BE IN HERE BUT NOT ALLOWED TO POST MULTIPLE LINKS" #Name of the url being searched
webpage = urllib.urlopen(url)
content = webpage.read() #places the read url contents into variable content
import re # Imports the re module which allows seaching for matches.
import pprint # This import allows all listitems to be printed on seperate lines.
match = re.findall(r'\<a.*href\=.*http\:.+', content)#matches any content that begins with a href and ands in >
def filterPick(list, filter):
return [( l, m.group(1) ) for l in match for m in (filter(l),) if m]
regex=re.compile(r'\"(.+?)\"').search
fltrmtch = filterPick(match, regex)
try:
if match: # defines that if there is a match the below is ran.
print "The number of URL's found is:" , len(match)
match.sort()
print "\nAnd here are the URL's found: "
pprint.pprint(fltrmtch)
except:
print "No URL matches have been found, please try again!"
Any help would be much appreciated.
Thank you in advance.
UPDATE: Thank you for the answer issued however I managed to find the flaw
return [( l, m.group(1) ) for l in match for m in (filter(l),) if m]
I simply had to remove the 1, from [(1, m.group(1)) ). Thanks again.

Answer 1

It appears that the bottom portion of your code is mostly catching errors from the top portion, and that the regex you provided has no capturing groups. Here is a revised example:
import re
url = "www.site.com" # place real web address here
# read web page into string
page = urllib.urlopen(url).read()
# use regex to extract URLs from <a href=""> patterns
matches = re.findall(r'''\<a\s[^\>]*?\bhref\=(['"])(.+?)\1[^\>]*?\>''', page, re.IGNORECASE)
# keep only the second group of positive matches
matches = sorted([match.group(2) for match in matches if match])
# print matches if they exist
if matches:
print("The number of URL's found is:" + str(len(matches)))
print("\nAnd here are the URL's found:")
# print each match
print('\n'.join(matches))
else:
print 'No URL matches have been found, please try again!'