How to initialize argv[i]? - c++

Question

I am trying to initialize argv[i] to the value of "C:\Games\World_of_Tanks\res\packages\gui.pkg" with a const char* pointer. Can I get some help doing this as I am new to programming.
#include <windows.h>
#include <cstdio>
void pf(const char* name)
{
HANDLE file = CreateFile(name, GENERIC_READ, FILE_SHARE_READ | FILE_SHARE_WRITE, 0, OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL, 0);
if(file == INVALID_HANDLE_VALUE) { printf("couldn't open %s\n", name); return; };
unsigned int len = GetFileSize(file, 0);
HANDLE mapping = CreateFileMapping(file, 0, PAGE_READONLY, 0, 0, 0);
if(mapping == 0) { printf("couldn't map %s\n", name); return; }
const char* data = (const char*) MapViewOfFile(mapping, FILE_MAP_READ, 0, 0, 0);
if(data)
{
printf("prefetching %s... ", name);
// need volatile or need to use result - compiler will otherwise optimize out whole loop
volatile unsigned int touch = 0;
for(unsigned int i = 0; i < len; i += 4096)
touch += data[i];
}
else
printf("couldn't create view of %s\n", name);
UnmapViewOfFile(data);
CloseHandle(mapping);
CloseHandle(file);
}
int main(int argc, const char** argv)
{
if(argc >= 2) for(int i = 1; argv[i]; ++i) pf(argv[i]);
return 0;
}

Answer 1

The value of a const charcan not be changed. What is it you want to do?
If you want a value of the argv array in the main function to be set you need to execute the program with a command line argument like:
program argument argument etc
Edit from comment info:
If you want to run the pffunction on program start you could add
pf("C:\Games\World_of_Tanks\res\packages\gui.pkg"); // this might need to be escaped...
in the main function.

Answer 2

You can just use another array
const char *myargv[] = { "pgmname",
"my_first_filename.dat",
"my_second_filename.dat",
NULL };
argv = myargv;
argc = 3;
If this is just to be able to run the program from an IDE note however that there is for sure a GUI option for setting the command line arguments for the program.