Primary expression before Double which is in my Array? - c++

Question

IT keep asking me for a primary expression before Double which is in my int Array and i dont know what to do. i have midterms tomorrow ugh this hurts my brain. All other input would be helpful thanks :)
#include <iostream>
#include <iomanip>
using namespace std;
void get_input(double array[50], int& sizearray1)
{
cout << "How many doubles do you wish to add?" << endl;
cin >> sizearray1;
while(sizearray1 < 1 || sizearray1 > 50) {
cout << "Error: That is an invalid number! You must enter a value between 1 and 50.\nHow many doubles do you wish to add?" << endl;
cin >> sizearray1;
}
for(int n=1;n<sizearray1;n++){
cout << "Enter Double " << n << endl;
cin >> array[n];
}
}
double calcSum(double array[50],int sizearray1)
{
int sum
cout << "The sum is ";
for(n=1,n<sizearray1,n++){
sum += array[n]
}
cout << sum << endl;
}
void printArray(double c[],int sizearray1)
{
cout << "The array contains:\n";
for(int n=1;n<sizearray1;n++){
cout << setprecision(2) << showpoint << fixed << c[n] << " ";
}
calcSum(double array[50],int sizearray1);
}
int main()
{
double array1[50];
int sizearray1 = 0;
get_input(double array[50],int sizearray1);
printArray(double array[50],int sizearray1);

Answer 1

Firstly I'm going to start off with some errors, as THIS code can't compile. No way.
You're missing a semicolon at int sum line 21. Your for loop at line 23 has commas instead of semicolons. You're using a undefined variable n = 1 in the same loop, you have to declare it before doing so for(n=1,n<sizearray1,n++). Again in the same for loop at line 24 you forgot another semicolon sum += array[n].
Back to your question:
You can't give a function a type parameter, you would actually try to declare a variable there. Also please don't declare a function like this double calcSum (double array[50], int sizearray1) as this is really not what you want... use this instead double calcSum (double array[/*Nothing here*/], int sizearray1).
Please check your whole code and fix all errors. This is a fix of me. Of course it doesn't work, your code is a bit to messy, check all the functions and give them the right parameters.
#include <iostream>
#include <iomanip>
using namespace std;
void get_input (double array[], int& sizearray1)
{
cout << "How many doubles do you wish to add?" << endl;
cin >> sizearray1;
while (sizearray1 < 1 || sizearray1 > 50)
{
cout << "Error: That is an invalid number! You must enter a value between 1 and 50.\nHow many doubles do you wish to add?" << endl;
cin >> sizearray1;
}
for (int n = 1; n < sizearray1; n++)
{
cout << "Enter Double " << n << endl;
cin >> array[n];
}
}
double calcSum (double array[], int sizearray1)
{
int sum;
cout << "The sum is ";
for (int n = 1; n < sizearray1; n++)
{
sum += array[n];
}
cout << sum << endl;
}
void printArray (double c[], int sizearray1)
{
cout << "The array contains:\n";
for (int n = 1; n < sizearray1; n++)
{
cout << setprecision(2) << showpoint << fixed << c[n] << " ";
}
calcSum (array[50], sizearray1); //This still can't work, the variable "array" has not been declared
}
int main()
{
double array1[50];
int sizearray1 = 0;
get_input (array[50], sizearray1); //Again "array" has not been declared
printArray (array[50], sizearray1); //Again "array" has not been declared
return EXIT_SUCCESS;
}

Answer 2

When calling a function don`t include the type like :
calcSum(double array[50],int sizearray1);
But simply use the variable names :
calcSum(array[50],sizearray1);
same with your get_input() and printArray() functions.
And in your printArray() function, I think you are recieving the passed array into the variable c. So it should be :
calcSum(c[50],sizearray1);
And I think you are trying to pass the whole array, then you just have to use the arrayname:
calcSum(c,sizearray1);
c[50] will only pass the element at 50th position in the array.