Why this code failed to run - c++

Question

i want to generate a tree of siblings as under
ABCD
/ | \ \
A B C D
ABCD has four nodes i have taken a array for this *next[]. but this code does not run successfully but it produces the sequence. i have written code in main() which provide characters to the enque function. e.g. str.at(x) where x is variable in for loop.
struct node
{
string info;
struct node *next[];
}*root,*child;
string str, goal;
int dept=0,bnod=0,cl,z=0;
void enqueue(string n);
void enqueue(string n)
{
node *p, *temp;
p=new node[sizeof(str.length())];
p->info=n;
for (int x=0;x<str.length();x++)
p->next[x]=NULL;
if(root==NULL)
{
root=p;
child=p;
}
else
{
cout<<" cl="<<cl<<endl;
if(cl<str.length())
{
child->next[cl]=p;
temp=child->next[cl];
cout<<"chile-info "<<temp->info<<endl;
}
else
cout<<" clif="<<cl<<endl;
}
}
OUTPUT
Enter String: sham
cl=0
chile-info s
cl=1
chile-info h
cl=2
chile-info a
cl=3
chile-info m
RUN FAILED (exit value 1, total time: 2s)

Answer 1

Firstly, where does "RUN FAILED" come from? Is that specific to your compiler?
Secondly, about the line p=new node[sizeof(str.length())];, it probably won't give you what you wanted because you're taking the sizeof of an unsigned integer ( which, depending on your platform is likely to give you 4 regardless of the string length. Which is not what you're after - you want the actual length of the string ).
So - since you're already using std::string, why not use std::vector? Your code would look a lot friendlier :-)
If I take the first couple of lines as your desired output ( sorry, the code you posted is very hard to decipher, and I don't think it compiles either, so I'm ignoring it ;-) )
Would something like this work better for you?
#include <iostream>
#include <vector>
#include <string>
typedef struct node
{
std::string info;
std::vector<struct node*> children;
}Node;
Node * enqueue(std::string str)
{
Node * root;
root = new Node();
root->info = str;
for (int x = 0; x < str.length(); x++)
{
Node * temp = new Node();
temp->info = str[x];
root->children.push_back(temp);
}
return root;
}
int main()
{
Node * myRoot = enqueue("ABCD");
std::cout << myRoot->info << "\n";
for( int i = 0; i < myRoot->children.size(); i++)
{
std::cout << myRoot->children[i]->info << ", ";
}
char c;
std::cin >> c;
return 0;
}

Answer 2

Your code seems not full.
At least the line
p=new node[sizeof(str.length())];
seems wrong.
I guess enqueue should be something similar to the following:
struct node
{
string info;
struct node *next; // [] - is not necessary here
}*root,*child;
string str, goal;
int dept=0,bnod=0,cl,z=0;
void enqueue(string n)
{
node *p, *temp;
p = new node;
p->next = new node[str.length()];
p->info=n;
for (int x=0;x<str.length();x++)
{
p->next[x] = new node;
p->next[x]->next = 0;
p->next[x]->info = str[x];
}
if(root==NULL)
{
root=p;
child=p;
}
}
Please provide more info to give a more correct answer