Separating number input into units [closed] - c++

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I need to separate users input into units and store them in an array.
e.g if user enters 6547. Array will store {6,5,4,7} Using C++ on Linux
I would appreciate if you can help me with pseudocode or explain an algorithm.
I'm a beginner so please restrain from advising advanced function (and explain its use if you do) as we have studied basics so far
N.B| If such question has already been answered and I skipped it in search, please do point me to it.

Answer 1

The math for isolating right most digit:
digit = digit % 10;
The math for shifting a number right by one digit:
new_number = old_number / 10;
Every letter and number can be represented as a text character. For example, '5' is a character representing the single decimal digit 5.
The math for converting a textual digit (character) to numeric:
digit = char_digit - '0';
Example:
digit = '9' - '0';
The math for converting a numeric digit to a textual digit (character):
char_digit = digit + '0';
Example:
char_digit = 5 + '0';

Answer 2

Your problem basically breaks into few parts, which you need to figure out:
how to read one character from input
how to convert one character to the digit it represents
how to store it in the array
Please, try to explain if you have problem with some particular point from the list above or there is a problem somewhere else.

Answer 3

Suppose Variable input_string holds the number entered by the user & you want to store it in an array named 'a'...Here's a C snippet.. you can easily convert it into C++ code..
I would recommend taking the input as string rather than int so that you can directly insert the digits extracted from the end...(else you can start storing the integer from beginning and then reverse the array)
scanf("%s",&input_string)
size = strlen(input_string)-1
input = atoi(input_string)
while (input/10>0)
{
i=input%10;
input=input/10;
a[size]=i;
size--;
}
Hope that helps!

Answer 4

Here's a C++11 solution:
std::string input;
std::cin >> input;
int num = std::stoi(input);
std::vector<int> v_int;
for (unsigned int i = 0; i < input.size(); i++)
{
v_int.push_back(num % 10);
num /= 10;
}
// To get the numbers in the original order
std::sort(v_int.rbegin(), v_int.rend());
for (unsigned int i = 0; i < v_int.size(); i++) {
std::cout << v_int[i] << std::endl;
}
If you want it in a c-style array, do this:
int* dynamic_array = new int[v_int.size()];
std::copy(v_int.begin(), v_int.end(), dynamic_array);
delete dynamic_array;